
In the reaction, $A + B \rightleftharpoons 2C$, at equilibrium, the concentration of A and B is $0.20mol/{{L}^{-1}}$ each, and that of C was found to be $0.60mol/{{L}^{-1}}$. Calculate the equilibrium constant of the reaction .
(A) 2.4
(B) 18
(C) 4.8
(D) 9
Answer
162.3k+ views
Hint: An equilibrium constant (K) is the relationship between the concentration of reactants and products present at equilibrium in a reversible chemical process at a given temperature. It is the ratio of the concentration of products and reactants.
Formula Used: For the reaction: $A + B \rightleftharpoons 2C$
The equilibrium constant is $K=\frac{{{[C]}^{2}}}{[A][B]}$
Complete Step by Step Answer:
The given reaction is-
The concentration of the reactants and products are $\left[ A \right]=0.20$ ,$\left[ B \right]=0.20$,
$\left[ C \right]=0.60$
The equilibrium constant of this reaction is given by $K=\frac{{{[C]}^{2}}}{[A][B]}$
$K=\frac{{{(0.60)}^{2}}}{(0.20)(0.20)}$
$K=9$
Thus, the equilibrium constant of this reaction is 9.
Correct Option: (D) 9.
Additional Information: Chemical equilibrium is a state in which the rates of both the forward and backward reactions are equal and the concentration of both the reactants and products is constant. At equilibrium, there is no net change in the number of moles, although conversion from reactants to products or products to reactants is still occurring. According to the law of mass action, the value of the equilibrium constant, Kc, is constant at a constant temperature. The concentrations of reactants and products may vary, but the value for Kc remains the same.
Note: The units of equilibrium constant depend upon the number of moles of reactant and product. Its units can be given by ${{\left( mol/l \right)}^{\Delta n}}$ . Here, $\Delta n={{n}_{P}}-{{n}_{R}}=2-2=0$ .So, K has no units. To calculate the equilibrium constant, you must first understand the entire reaction and its stoichiometric coefficients. If K>1, the equilibrium favours products, and if K<1, then the equilibrium favours reactants. But, if K = 1, then both reactants and products are present in the mixture in significant amounts.
Formula Used: For the reaction: $A + B \rightleftharpoons 2C$
The equilibrium constant is $K=\frac{{{[C]}^{2}}}{[A][B]}$
Complete Step by Step Answer:
The given reaction is-
The concentration of the reactants and products are $\left[ A \right]=0.20$ ,$\left[ B \right]=0.20$,
$\left[ C \right]=0.60$
The equilibrium constant of this reaction is given by $K=\frac{{{[C]}^{2}}}{[A][B]}$
$K=\frac{{{(0.60)}^{2}}}{(0.20)(0.20)}$
$K=9$
Thus, the equilibrium constant of this reaction is 9.
Correct Option: (D) 9.
Additional Information: Chemical equilibrium is a state in which the rates of both the forward and backward reactions are equal and the concentration of both the reactants and products is constant. At equilibrium, there is no net change in the number of moles, although conversion from reactants to products or products to reactants is still occurring. According to the law of mass action, the value of the equilibrium constant, Kc, is constant at a constant temperature. The concentrations of reactants and products may vary, but the value for Kc remains the same.
Note: The units of equilibrium constant depend upon the number of moles of reactant and product. Its units can be given by ${{\left( mol/l \right)}^{\Delta n}}$ . Here, $\Delta n={{n}_{P}}-{{n}_{R}}=2-2=0$ .So, K has no units. To calculate the equilibrium constant, you must first understand the entire reaction and its stoichiometric coefficients. If K>1, the equilibrium favours products, and if K<1, then the equilibrium favours reactants. But, if K = 1, then both reactants and products are present in the mixture in significant amounts.
Recently Updated Pages
Two pi and half sigma bonds are present in A N2 + B class 11 chemistry JEE_Main

Which of the following is most stable A Sn2+ B Ge2+ class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

The specific heat of metal is 067 Jg Its equivalent class 11 chemistry JEE_Main

The increasing order of a specific charge to mass ratio class 11 chemistry JEE_Main

Which one of the following is used for making shoe class 11 chemistry JEE_Main

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

JoSAA JEE Main & Advanced 2025 Counselling: Registration Dates, Documents, Fees, Seat Allotment & Cut‑offs

NIT Cutoff Percentile for 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Degree of Dissociation and Its Formula With Solved Example for JEE
