
In electrolysis, if the duration of the passage of current is doubled, the mass liberated is
A) Doubled
B) Halved
C) Increased four times
D) Remains the same
Answer
164.7k+ views
Hint: The question is from the chemical effects of the current section of physics. We have to apply the concepts of electrolysis to solve this problem. We need to use Faraday’s first law and current-charge relation here.
Complete step by step solution:According to Faraday's first law, the mass of the substance released or deposited on an electrode during electrolysis is directly proportional to the amount of electric charge carried through the electrolyte.
If m = mass of a substance liberated or deposited at an electrode and q = charge. Then according to Faraday's law of electrolysis,
\(m \propto q\)
We know the relation between current and charge, which is given below.
\(I = \frac{q}{t} \Rightarrow q = I \cdot t\)
Where I = current, q = charge and t= time.
Then the Faraday's first law becomes:
\(m \propto I \cdot t\)
From this relation we can see that mass and time are directly proportional to each other. When time is doubled mass will also become double.
Hence, the correct option is Option (A).
Additional Information:Electrolysis is a technique for eliminating iron oxide. By applying a tiny electrical charge to the rusted metal from a battery or battery charger to stimulate ion exchange while the device is submerged in an electrolyte solution.
The Faraday constant represents the amount of electric charge carried by one mole, or Avogadro's number of electrons. It is a crucial constant in physics, electronics, and chemistry. The measurement is given in coulombs per mole (C/mol).
Note: According to Faraday's law of electrolysis,
\(m \propto q \Rightarrow m = zq\)
Where z = electrochemical equivalent of the substance. The z is calculated by the given equation.
\(z = \frac{{Atomic{\rm{ }}mass}}{{Valency}} \times \frac{1}{{96500}}gm{C^{ - 1}}\)
Complete step by step solution:According to Faraday's first law, the mass of the substance released or deposited on an electrode during electrolysis is directly proportional to the amount of electric charge carried through the electrolyte.
If m = mass of a substance liberated or deposited at an electrode and q = charge. Then according to Faraday's law of electrolysis,
\(m \propto q\)
We know the relation between current and charge, which is given below.
\(I = \frac{q}{t} \Rightarrow q = I \cdot t\)
Where I = current, q = charge and t= time.
Then the Faraday's first law becomes:
\(m \propto I \cdot t\)
From this relation we can see that mass and time are directly proportional to each other. When time is doubled mass will also become double.
Hence, the correct option is Option (A).
Additional Information:Electrolysis is a technique for eliminating iron oxide. By applying a tiny electrical charge to the rusted metal from a battery or battery charger to stimulate ion exchange while the device is submerged in an electrolyte solution.
The Faraday constant represents the amount of electric charge carried by one mole, or Avogadro's number of electrons. It is a crucial constant in physics, electronics, and chemistry. The measurement is given in coulombs per mole (C/mol).
Note: According to Faraday's law of electrolysis,
\(m \propto q \Rightarrow m = zq\)
Where z = electrochemical equivalent of the substance. The z is calculated by the given equation.
\(z = \frac{{Atomic{\rm{ }}mass}}{{Valency}} \times \frac{1}{{96500}}gm{C^{ - 1}}\)
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
