
In an experiment, a spirit burner is used to heat $250\,c{m^{^3}}$of water by burning methanol ($C{H_3}OH$).
(At. Values C= 12.0, H= 1.0, O=16.0; specific heat capacity of water = $4.18\,J{g^{ - 1o}}{C^{ - 1}}$) Results:
Starting temperature of water = ${20.0^{^0}}C$
Starting mass of burner + fuel = $248.8\,g$
Final temperature of water= ${43.0^{^0}}C$
Final mass of burner + fuel = $245.9\,g$
(A) How many joules of heat energy went into the water?
(B) How many moles of fuel were burnt?
(C) Calculate an experimental value for the enthalpy change of combustion of methanol from these results.
(D) Suggest three reasons why your answer is much smaller than the accepted standard enthalpy of combustion of methanol.
Answer
233.1k+ views
Hint: We will firstly find out the joules of heat energy went into the water and then how many moles of fuels were burnt. We will also state the reason why our answer will be smaller than the accepted enthalpy. Using our knowledge, we will be approaching our answer.
Complete step by step solution:
(A) Change in the temperature $ \Rightarrow \,43 - 20\, = {23^{^0}}C$
Change in mass $ \Rightarrow \,\,248.8\, - \,245.9\, = \,2.9\,g$
We know,
$q\,\, = \,\,mc\vartriangle t$
$\Rightarrow \,\,2.9\, \times \,4.18\, \times 23 \\
\Rightarrow \,\,278.8J \\ $
Now,
(B) Moles of fuel burnt = $2.9\,/$molar mass
$ \Rightarrow \,\,2.9\,/\,32$
$ \Rightarrow 0.09$
(C) The amount of heat which is evolved or absorbed in the reaction which is carried out at constant pressure is known as enthalpy change and its symbol is $\vartriangle H$ and is pronounced or read as delta.
Physical and Chemical states are the standard states for enthalpy change. Elements which have allotropes have the most energetically stable standard state.
(D) My answer is much smaller than the accepted standard enthalpy of combustion of methanol because of the energy loss and incomplete reaction. The water may end up in the gaseous state or reactants may not be in the standard states.
NOTE: The heat of a reaction or the Enthalpy of reaction is defined as the change in the enthalpy of a chemical reaction. It describes the quantity of the heat released or absorbed in the reaction. The term ‘Enthalpy Change’ is only applied to the reactions which are done at the constant pressure because most of the lab reactions are performed in flasks or in test tubes which are open to the atmosphere so that pressure remains constant at atmospheric pressure.
Complete step by step solution:
(A) Change in the temperature $ \Rightarrow \,43 - 20\, = {23^{^0}}C$
Change in mass $ \Rightarrow \,\,248.8\, - \,245.9\, = \,2.9\,g$
We know,
$q\,\, = \,\,mc\vartriangle t$
$\Rightarrow \,\,2.9\, \times \,4.18\, \times 23 \\
\Rightarrow \,\,278.8J \\ $
Now,
(B) Moles of fuel burnt = $2.9\,/$molar mass
$ \Rightarrow \,\,2.9\,/\,32$
$ \Rightarrow 0.09$
(C) The amount of heat which is evolved or absorbed in the reaction which is carried out at constant pressure is known as enthalpy change and its symbol is $\vartriangle H$ and is pronounced or read as delta.
Physical and Chemical states are the standard states for enthalpy change. Elements which have allotropes have the most energetically stable standard state.
(D) My answer is much smaller than the accepted standard enthalpy of combustion of methanol because of the energy loss and incomplete reaction. The water may end up in the gaseous state or reactants may not be in the standard states.
NOTE: The heat of a reaction or the Enthalpy of reaction is defined as the change in the enthalpy of a chemical reaction. It describes the quantity of the heat released or absorbed in the reaction. The term ‘Enthalpy Change’ is only applied to the reactions which are done at the constant pressure because most of the lab reactions are performed in flasks or in test tubes which are open to the atmosphere so that pressure remains constant at atmospheric pressure.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

Organic Chemistry Some Basic Principles And Techniques Class 11 Chemistry Chapter 8 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reactions (2025-26)

