
IIdentify the product in following order
$3,4,5 - Tribromoaniline \xrightarrow[\left ( ii \right )H_3PO_4]{\left ( i \right )Diazotisation}$?
A. 3,4,5-Tribromobenzene
B. 1,2,3-Tribromobenzene
C. 2,4,6-Tribromobenzene
D. 3,4,5-Tribromo nitro benzene
E. 3,4,5-Tribromo phenol
Answer
161.1k+ views
Hint: 3,4,5-Tribromoaniline is a compound containing primary aromatic amine with three bromine groups at 3, 4 and 5 positions of aniline. Here in the first step diazotization is performed and then acid is given which will provide its proton in the reaction. Diazotization reaction is a type of coupling reaction for primary amine compounds.
Complete Step by Step Solution:
In the first step, a diazotisation reaction will take place where sodium nitrite and hydrochloric acid at \[{0^ \circ }\]C condition react to give nitrous acid, \[HONO\] which attacks the primary aromatic amine to give diazonium salt i.e., 3,4,5-Tribromobenzene diazonium salt. This then reacts with hypo phosphorus acid reagent which gives its hydrogen to the carbon of benzene ring where diazonium group is attached. So, from the final product nitrogen group is removed and hydrogen is present in its place. The name of the final compound is 1,2,3-tribromobenzene which is option B.

Image: Diazotisation reaction and further treatment with acid of 3,4,5-Tribromoaniline.
So, option B is correct. 2
Note: Ethanimine are the organic compounds having imine functional group i.e.,\[ - C = N - \]. This reacts with water and forms a compound containing a carbonyl functional group such as ketone or aldehyde. In this question acetonitrile is given so it forms acetaldehyde. Here, the overall number of carbons remains the same.
Complete Step by Step Solution:
In the first step, a diazotisation reaction will take place where sodium nitrite and hydrochloric acid at \[{0^ \circ }\]C condition react to give nitrous acid, \[HONO\] which attacks the primary aromatic amine to give diazonium salt i.e., 3,4,5-Tribromobenzene diazonium salt. This then reacts with hypo phosphorus acid reagent which gives its hydrogen to the carbon of benzene ring where diazonium group is attached. So, from the final product nitrogen group is removed and hydrogen is present in its place. The name of the final compound is 1,2,3-tribromobenzene which is option B.

Image: Diazotisation reaction and further treatment with acid of 3,4,5-Tribromoaniline.
So, option B is correct. 2
Note: Ethanimine are the organic compounds having imine functional group i.e.,\[ - C = N - \]. This reacts with water and forms a compound containing a carbonyl functional group such as ketone or aldehyde. In this question acetonitrile is given so it forms acetaldehyde. Here, the overall number of carbons remains the same.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main Mock Test Series Class 12 Chemistry for FREE

Classification of Drugs Based on Pharmacological Effect, Drug Action

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2026 Syllabus PDF - Download Paper 1 and 2 Syllabus by NTA

JEE Main Eligibility Criteria 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

Solutions Class 12 Notes: CBSE Chemistry Chapter 1
