
If $x\left[ \begin{array}{l} - 3\\4\end{array} \right] + y\left[ \begin{array}{l}4\\3\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$. Then what are the values of $x$ and $y$?
A. $x = - 2, y = 1$
B. $x = - 9, y = 10$
C. $x = 22, y = 1$
D. $x = 2, y = - 1$
Answer
163.2k+ views
Hint: Here simplify the left-hand side by using the scalar multiplication property of a matrix. Then use the additional property of matrices. After that, use the property of equality of matrix and equate the corresponding elements. In the end, solve the equations with variables $x$ and $y$ to reach the required answer.
Formula Used:
The scalar multiplication of a matrix is a product of a matrix and a real number.
Equality property: Two matrices are equal if and only if the matrices have the same order and the corresponding elements are identical.
Complete step by step solution:
The given equation of matrices is $x\left[ \begin{array}{l} - 3\\4\end{array} \right] + y\left[ \begin{array}{l}4\\3\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$.
Let’s simplify the above equation.
Apply the scalar multiplication property of a matrix.
$x\left[ \begin{array}{l} - 3\\4\end{array} \right] + y\left[ \begin{array}{l}4\\3\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$
$ \Rightarrow $$\left[ \begin{array}{l} - 3x\\4x\end{array} \right] + \left[ \begin{array}{l}4y\\3y\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$
Now apply the additional property of matrices.
$\left[ \begin{array}{l} - 3x + 4y\\4x + 3y\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$
Apply equality property of matrices.
We get,
$ - 3x + 4y = 10$ $.....\left( 1 \right)$
$4x + 3y = - 5$ $.....\left( 2 \right)$
Multiply equation $\left( 1 \right)$ by 4 and multiply equation $\left( 2 \right)$ by 3.
$ - 12x + 16y = 40$
$12x + 9y = - 15$
Now add the above equations.
$25y = 25$
Divide both sides by $25$.
$y = 1$
Substitute $y = 1$ in the equation $\left( 1 \right)$.
$ - 3x + 4\left( 1 \right) = 10$
$ \Rightarrow $$ - 3x + 4 = 10$
$ \Rightarrow $$ - 3x = 6$
Divide both sides by $ - 3$.
$x = - 2$
Thus, the values are $x = - 2$, and $y = 1$.
Option ‘A’ is correct
Note: Many students make a mistake to multiply $x$ and $y$ with $\left[ \begin{array}{l} - 3\\4\end{array} \right]$ and $\left[ \begin{array}{l}4\\3\end{array} \right]$ respectively. They multiply it with first row which is incorrect way. In scalar multiplication, each element of the matrix is multiplied by the given scalar. So $x$ and $y$will be multiplied with each elements of $\left[ \begin{array}{l} - 3\\4\end{array} \right]$ and $\left[ \begin{array}{l}4\\3\end{array} \right]$ respectively.
Formula Used:
The scalar multiplication of a matrix is a product of a matrix and a real number.
Equality property: Two matrices are equal if and only if the matrices have the same order and the corresponding elements are identical.
Complete step by step solution:
The given equation of matrices is $x\left[ \begin{array}{l} - 3\\4\end{array} \right] + y\left[ \begin{array}{l}4\\3\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$.
Let’s simplify the above equation.
Apply the scalar multiplication property of a matrix.
$x\left[ \begin{array}{l} - 3\\4\end{array} \right] + y\left[ \begin{array}{l}4\\3\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$
$ \Rightarrow $$\left[ \begin{array}{l} - 3x\\4x\end{array} \right] + \left[ \begin{array}{l}4y\\3y\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$
Now apply the additional property of matrices.
$\left[ \begin{array}{l} - 3x + 4y\\4x + 3y\end{array} \right] = \left[ \begin{array}{l}10\\ - 5\end{array} \right]$
Apply equality property of matrices.
We get,
$ - 3x + 4y = 10$ $.....\left( 1 \right)$
$4x + 3y = - 5$ $.....\left( 2 \right)$
Multiply equation $\left( 1 \right)$ by 4 and multiply equation $\left( 2 \right)$ by 3.
$ - 12x + 16y = 40$
$12x + 9y = - 15$
Now add the above equations.
$25y = 25$
Divide both sides by $25$.
$y = 1$
Substitute $y = 1$ in the equation $\left( 1 \right)$.
$ - 3x + 4\left( 1 \right) = 10$
$ \Rightarrow $$ - 3x + 4 = 10$
$ \Rightarrow $$ - 3x = 6$
Divide both sides by $ - 3$.
$x = - 2$
Thus, the values are $x = - 2$, and $y = 1$.
Option ‘A’ is correct
Note: Many students make a mistake to multiply $x$ and $y$ with $\left[ \begin{array}{l} - 3\\4\end{array} \right]$ and $\left[ \begin{array}{l}4\\3\end{array} \right]$ respectively. They multiply it with first row which is incorrect way. In scalar multiplication, each element of the matrix is multiplied by the given scalar. So $x$ and $y$will be multiplied with each elements of $\left[ \begin{array}{l} - 3\\4\end{array} \right]$ and $\left[ \begin{array}{l}4\\3\end{array} \right]$ respectively.
Recently Updated Pages
If tan 1y tan 1x + tan 1left frac2x1 x2 right where x frac1sqrt 3 Then the value of y is

Geometry of Complex Numbers – Topics, Reception, Audience and Related Readings

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

JoSAA JEE Main & Advanced 2025 Counselling: Registration Dates, Documents, Fees, Seat Allotment & Cut‑offs

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Verb Forms Guide: V1, V2, V3, V4, V5 Explained

1 Billion in Rupees

Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE
