If \[\vec a,\vec b,\vec c\] are vectors such that \[\vec a + \vec b + \vec c = 0\] and \[\left| {\vec a} \right| = 7,\left| {\vec b} \right| = 5,\left| {\vec c} \right| = 3\]then the angle between the vectors \[\vec b\] and \[\vec c\] is
A. \[{60^ \circ }\]
B. \[{40^ \circ }\]
C. \[{70^ \circ }\]
D. \[{20^ \circ }\]
Answer
249.6k+ views
Hint: In the given question, we need to find the value of the angle between the vectors \[\vec b\] and \[\vec c\]. For this, we will use the relation \[\vec a + \vec b + \vec c = 0\] and the definition of the dot product to get the desired result.
Formula used: The following formula is used for solving the given question.
The dot product of two vectors such as \[\vec u\] and \[\vec v\] is given by \[\vec u \cdot \vec v = uv\cos \theta \]
Complete step by step solution: We know that \[\vec a + \vec b + \vec c = 0\]
Here, \[\vec a,\vec b,\vec c\] are vectors.
Now, we will simplify \[\vec a + \vec b + \vec c = 0\]
\[\vec b + \vec c = - \vec a\]
By taking square on both sides, we get
\[{\left( {\vec b + \vec c} \right)^2} = {\left( { - \vec a} \right)^2}\]
By simplifying, we get
\[\left( {\vec b + \vec c} \right)\left( {\vec b + \vec c} \right) = \vec a \cdot \vec a\]
This gives
\[{\left| {\vec b} \right|^2} + {\left| {\vec c} \right|^2} + 2\vec b \cdot \vec c = {\left| {\vec a} \right|^2}\]
But \[\left| {\vec a} \right| = 7,\left| {\vec b} \right| = 5,\left| {\vec c} \right| = 3\]
Thus, we get
\[{\left( 5 \right)^2} + {\left( 3 \right)^2} + 2\vec b \cdot \vec c = {\left( 7 \right)^2}\]
\[2\vec b \cdot \vec c = 15\]
Also, \[2\left| {\vec b} \right|\left| {\vec c} \right|\cos \theta = 15\]
This gives,
\[30\cos \theta = 15\]
By simplifying, we get
\[\cos \theta = 1/2\]
\[\theta = {\cos ^{ - 1}}\left( {\dfrac{1}{2}} \right)\]
Thus, we get
\[\theta = {60^ \circ }\]
Hence, the angle between the vectors \[\vec b\] and \[\vec c\] is \[{60^ \circ }\] if If \[\vec a,\vec b,\vec c\] are vectors such that \[\vec a + \vec b + \vec c = 0\] and \[\left| {\vec a} \right| = 7,\left| {\vec b} \right| = 5,\left| {\vec c} \right| = 3\].
Thus, Option (A) is correct.
Additional Information: The definition of a vector is an entity with both magnitude and direction. The movement of an object between two points is described by a vector. The directed line segment can be used to geometrically represent vector mathematics. The magnitude of a vector is the length of the directed line segment, and the vector's direction is indicated by the angle at which it is inclined. A vector's "Tail" (the point where it begins) and "Head" (the point where it ends and has an arrow) are its respective names.
Note: Many students make mistake in simplification of vector expression such as \[\vec a + \vec b + \vec c = 0\]. This is the only way, through which we can solve the example in simplest way. Also, it is necessary to use the definition of dot product to get the desired result.
Formula used: The following formula is used for solving the given question.
The dot product of two vectors such as \[\vec u\] and \[\vec v\] is given by \[\vec u \cdot \vec v = uv\cos \theta \]
Complete step by step solution: We know that \[\vec a + \vec b + \vec c = 0\]
Here, \[\vec a,\vec b,\vec c\] are vectors.
Now, we will simplify \[\vec a + \vec b + \vec c = 0\]
\[\vec b + \vec c = - \vec a\]
By taking square on both sides, we get
\[{\left( {\vec b + \vec c} \right)^2} = {\left( { - \vec a} \right)^2}\]
By simplifying, we get
\[\left( {\vec b + \vec c} \right)\left( {\vec b + \vec c} \right) = \vec a \cdot \vec a\]
This gives
\[{\left| {\vec b} \right|^2} + {\left| {\vec c} \right|^2} + 2\vec b \cdot \vec c = {\left| {\vec a} \right|^2}\]
But \[\left| {\vec a} \right| = 7,\left| {\vec b} \right| = 5,\left| {\vec c} \right| = 3\]
Thus, we get
\[{\left( 5 \right)^2} + {\left( 3 \right)^2} + 2\vec b \cdot \vec c = {\left( 7 \right)^2}\]
\[2\vec b \cdot \vec c = 15\]
Also, \[2\left| {\vec b} \right|\left| {\vec c} \right|\cos \theta = 15\]
This gives,
\[30\cos \theta = 15\]
By simplifying, we get
\[\cos \theta = 1/2\]
\[\theta = {\cos ^{ - 1}}\left( {\dfrac{1}{2}} \right)\]
Thus, we get
\[\theta = {60^ \circ }\]
Hence, the angle between the vectors \[\vec b\] and \[\vec c\] is \[{60^ \circ }\] if If \[\vec a,\vec b,\vec c\] are vectors such that \[\vec a + \vec b + \vec c = 0\] and \[\left| {\vec a} \right| = 7,\left| {\vec b} \right| = 5,\left| {\vec c} \right| = 3\].
Thus, Option (A) is correct.
Additional Information: The definition of a vector is an entity with both magnitude and direction. The movement of an object between two points is described by a vector. The directed line segment can be used to geometrically represent vector mathematics. The magnitude of a vector is the length of the directed line segment, and the vector's direction is indicated by the angle at which it is inclined. A vector's "Tail" (the point where it begins) and "Head" (the point where it ends and has an arrow) are its respective names.
Note: Many students make mistake in simplification of vector expression such as \[\vec a + \vec b + \vec c = 0\]. This is the only way, through which we can solve the example in simplest way. Also, it is necessary to use the definition of dot product to get the desired result.
Recently Updated Pages
JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Instantaneous Velocity Explained: Formula, Examples & Graphs

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Hybridisation in Chemistry – Concept, Types & Applications

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

CBSE Class 12 Maths 2026 Question Paper: Free PDF & Solutions

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Understanding the Angle of Deviation in a Prism

Understanding Centrifugal Force in Physics

