
If the ratio of gradients of the lines represented by \[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\] is \[1:3\], then the value of the ratio \[{{h}^{2}}:ab\] is
A. $\dfrac{1}{3}$
B. $\dfrac{3}{4}$
C. $\dfrac{4}{3}$
D. 1
Answer
164.1k+ views
Hint: The gradient is the measure of the steepness of a line. If the two lines represented by the homogeneous equation \[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\] be \[y={{m}_{1}}x\] and \[y={{m}_{2}}x\], where \[{{m}_{1}}\] and \[{{m}_{2}}\] be the slope or gradient of the line. The expression \[a{{x}^{2}}+2hxy+b{{y}^{2}}\] should be comparable with the product \[\left( y-{{m}_{1}}x \right)\left( y-{{m}_{2}}x \right)={{y}^{2}}-({{m}_{1}}+{{m}_{2}})xy+{{m}_{1}}{{m}_{2}}{{x}^{2}}\]. Therefore, we must have \[{{m}_{1}}+{{m}_{2}}=\dfrac{-2h}{b}\] and \[{{m}_{1}}\cdot {{m}_{2}}=\dfrac{a}{b}\].
Formula used:
The equation of lines \[y={{m}_{1}}x\] and \[y={{m}_{2}}x\]
Complete step-by-step solution:
Let \[y={{m}_{1}}x\] and \[y={{m}_{2}}x\] be the equation of lines
Given, \[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\] be the equation of pair of lines and their ratio of gradient is \[{{m}_{1}}:{{m}_{2}}=1:3\].
\[\Rightarrow \,\,\,\dfrac{{{m}_{1}}}{{{m}_{2}}}=\dfrac{1}{3}\]
\[\Rightarrow \,\,\,{{m}_{2}}=3{{m}_{1}}\] -------- (1)
Then, Sum of two slopes i.e., \[{{m}_{1}}+{{m}_{2}}=\dfrac{-2h}{b}\]
\[\Rightarrow \,\,\,{{m}_{1}}+3{{m}_{1}}=\dfrac{-2h}{b}\] (By (1))
\[\Rightarrow \,\,\,4{{m}_{1}}=\dfrac{-2h}{b}\]
\[\Rightarrow \,\,\,{{m}_{1}}=\dfrac{-2h}{4b}\]
\[\Rightarrow \,\,\,{{m}_{1}}=\dfrac{-h}{2b}\] -------- (2)
Product of two slopes i.e., \[{{m}_{1}}\cdot {{m}_{2}}=\dfrac{a}{b}\]
\[\Rightarrow \,\,\,{{m}_{1}}\cdot 3{{m}_{1}}=\dfrac{a}{b}\] (By (1))
\[\Rightarrow \,\,\,3m_{1}^{2}=\dfrac{a}{b}\] -------- (3)
Substitute the value of (2) in (3), then
\[\Rightarrow \,\,\,3{{\left( \dfrac{-h}{2b} \right)}^{2}}=\dfrac{a}{b}\]
\[\Rightarrow \,\,\,\dfrac{3{{h}^{2}}}{4{{b}^{2}}}=\dfrac{a}{b}\]
\[\therefore \,\,\,\dfrac{{{h}^{2}}}{ab}=\dfrac{4}{3}\]
Hence, the required ratio of \[{{h}^{2}}:ab\] is \[4:3\].
So the correct answer is option(C)
Note: Gradient of the line is the ratio of the change in the y-axis to the change in the x-axis, the slope m represents the gradient of the line. If two lines are perpendicular then the product of the gradient of line is always equal to -1 i.e., \[{{m}_{1}}\cdot {{m}_{2}}=-1\] and if two lines are parallel the gradient is equal in value i.e., \[{{m}_{1}}={{m}_{2}}\].
Formula used:
The equation of lines \[y={{m}_{1}}x\] and \[y={{m}_{2}}x\]
Complete step-by-step solution:
Let \[y={{m}_{1}}x\] and \[y={{m}_{2}}x\] be the equation of lines
Given, \[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\] be the equation of pair of lines and their ratio of gradient is \[{{m}_{1}}:{{m}_{2}}=1:3\].
\[\Rightarrow \,\,\,\dfrac{{{m}_{1}}}{{{m}_{2}}}=\dfrac{1}{3}\]
\[\Rightarrow \,\,\,{{m}_{2}}=3{{m}_{1}}\] -------- (1)
Then, Sum of two slopes i.e., \[{{m}_{1}}+{{m}_{2}}=\dfrac{-2h}{b}\]
\[\Rightarrow \,\,\,{{m}_{1}}+3{{m}_{1}}=\dfrac{-2h}{b}\] (By (1))
\[\Rightarrow \,\,\,4{{m}_{1}}=\dfrac{-2h}{b}\]
\[\Rightarrow \,\,\,{{m}_{1}}=\dfrac{-2h}{4b}\]
\[\Rightarrow \,\,\,{{m}_{1}}=\dfrac{-h}{2b}\] -------- (2)
Product of two slopes i.e., \[{{m}_{1}}\cdot {{m}_{2}}=\dfrac{a}{b}\]
\[\Rightarrow \,\,\,{{m}_{1}}\cdot 3{{m}_{1}}=\dfrac{a}{b}\] (By (1))
\[\Rightarrow \,\,\,3m_{1}^{2}=\dfrac{a}{b}\] -------- (3)
Substitute the value of (2) in (3), then
\[\Rightarrow \,\,\,3{{\left( \dfrac{-h}{2b} \right)}^{2}}=\dfrac{a}{b}\]
\[\Rightarrow \,\,\,\dfrac{3{{h}^{2}}}{4{{b}^{2}}}=\dfrac{a}{b}\]
\[\therefore \,\,\,\dfrac{{{h}^{2}}}{ab}=\dfrac{4}{3}\]
Hence, the required ratio of \[{{h}^{2}}:ab\] is \[4:3\].
So the correct answer is option(C)
Note: Gradient of the line is the ratio of the change in the y-axis to the change in the x-axis, the slope m represents the gradient of the line. If two lines are perpendicular then the product of the gradient of line is always equal to -1 i.e., \[{{m}_{1}}\cdot {{m}_{2}}=-1\] and if two lines are parallel the gradient is equal in value i.e., \[{{m}_{1}}={{m}_{2}}\].
Recently Updated Pages
Geometry of Complex Numbers – Topics, Reception, Audience and Related Readings

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main 2025 Session 2: Exam Date, Admit Card, Syllabus, & More

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Trending doubts
Degree of Dissociation and Its Formula With Solved Example for JEE

Instantaneous Velocity - Formula based Examples for JEE

JEE Main Chemistry Question Paper with Answer Keys and Solutions

JEE Main Reservation Criteria 2025: SC, ST, EWS, and PwD Candidates

What is Normality in Chemistry?

Chemistry Electronic Configuration of D Block Elements: JEE Main 2025

Other Pages
NCERT Solutions for Class 11 Maths Chapter 6 Permutations and Combinations

NCERT Solutions for Class 11 Maths Chapter 8 Sequences and Series

Total MBBS Seats in India 2025: Government College Seat Matrix

NEET Total Marks 2025: Important Information and Key Updates

Neet Cut Off 2025 for MBBS in Tamilnadu: AIQ & State Quota Analysis

Karnataka NEET Cut off 2025 - Category Wise Cut Off Marks
