
If magnification is positive, the nature of the image is:
(A) Real and inverted
(B) Virtual and erect
(C) Real
(D) None of these
Answer
522.8k+ views
Hint Magnification is given by the ratio of image size to the object size $m = \dfrac{I}{O}$ . Cartesian sign conventions say that when the ratio is positive, the image is virtual and erect. When the ratio is negative the image is real and virtual.
Complete step-by-step answer
Magnification can be defined as the ratio of size of the image to the size of the object. It is denoted by m.
$m = \dfrac{I}{O}$

For example
This magnification can tell us about the nature of the image based on the sign itself. If the ratio is negative then the image is real and inverted. If the ratio is positive then the image is virtual and erect.
So, according to these sigh conventions, when the magnification is positive then the image has to be erect and virtual.
Hence, the correct option will be B.
Note Lateral magnification is when an object is placed perpendicular to the principle axis.
$m = - \dfrac{v}{u}$
Axial magnification is when object lies on the principle axis
$m = - \dfrac{{{v_2} - {v_1}}}{{{u_2} - {u_1}}}$
Areal magnification is if a 2D object is placed with its plane perpendicular to the principle axis. It is the ratio of area of image to that of object.
$m = \dfrac{{{A_i}}}{{{A_o}}}$ .
Complete step-by-step answer
Magnification can be defined as the ratio of size of the image to the size of the object. It is denoted by m.
$m = \dfrac{I}{O}$

For example
This magnification can tell us about the nature of the image based on the sign itself. If the ratio is negative then the image is real and inverted. If the ratio is positive then the image is virtual and erect.
So, according to these sigh conventions, when the magnification is positive then the image has to be erect and virtual.
Hence, the correct option will be B.
Note Lateral magnification is when an object is placed perpendicular to the principle axis.
$m = - \dfrac{v}{u}$
Axial magnification is when object lies on the principle axis
$m = - \dfrac{{{v_2} - {v_1}}}{{{u_2} - {u_1}}}$
Areal magnification is if a 2D object is placed with its plane perpendicular to the principle axis. It is the ratio of area of image to that of object.
$m = \dfrac{{{A_i}}}{{{A_o}}}$ .
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

