
If $A(0,0)$, $B(12,0)$,$C(12,2)$,$D(6,7)$,$E(0,5)$ are the vertices of the pentagon $ABCDE$, then its area in square units, is
A. 58
B. 60
C. 61
D. 62
E. 63
Answer
164.7k+ views
Hint: In the question we are given the coordinates of all the 5 points. We will use the formula of area of pentagon which is
Area
$A = \dfrac{1}{2}\sum {{x_n}{y_{n + 1}} - {y_n}{x_{n + 1}}} $
where n = 1, 2, 3, 4, 5. We substitute the values and find the area.
Formula Used:
$A = \dfrac{1}{2}\sum {{x_n}{y_{n + 1}} - {y_n}{x_{n + 1}}} $
Complete step by step Solution:
Pentagon is a figure with 5 straight sides and 5 angles. A regular pentagon has 5 lines of symmetry, and rotational symmetry of order 5 (through 72°, 144°, 216°, and 288°).
A convex pentagon has no angles pointing inwards and no internal angles can be more than 180°. When any internal angle is greater than 180° it becomes a concave pentagon.
A convex pentagon is defined as one whose vertices where the sides meet, are pointing outwards unlike a concave pentagon whose vertices point inwards.
The given vertices are $A(0,0)$, $B(12,0)$,$C(12,2)$,$D(6,7)$,$E(0,5)$
Now let $({x_1},{y_1}) = (0,0)$
$({x_2},{y_2}) = (12,0)$
$({x_3},{y_3}) = (12,2)$
$({x_4},{y_4}) = (6,7)$
$({x_5},{y_5}) = (0,5)$
Now, substituting the value in formula of area of a pentagon we get,
$A = \dfrac{1}{2}[{x_1}{y_2} + {x_2}{y_3} + {x_3}{y_4} + {x_4}{y_5} + {x_5}{y_1} - ({y_1}{x_2} + {y_2}{x_3} + {y_3}{x_4} + {y_4}{x_5} + {y_5}{x_1})]$
$A = \dfrac{1}{2}[0 \times 0 + 12 \times 2 + 12 \times 7 + 6 \times 5 + 0 \times 0 - (0 + 0 + 2 \times 6 + 7 \times 0 + 0 \times 5)]$
$A = 63$
Hence, the area of the pentagon is 63 sq. units.
Hence, the correct option is E.
Note: The properties of a simple pentagon are that it must have five straight sides that meet to create five vertices but they should not self-intersect: Pentagons have 5 interior angles, which sum to 540°. The five sides do not intersect. The formula given can also be used for all polygons. There are also many ways to calculate the area of a pentagon like we can convert it into different shapes and calculate the area of each shape. It depends on the value given in the question we have to deal accordingly.
Area
$A = \dfrac{1}{2}\sum {{x_n}{y_{n + 1}} - {y_n}{x_{n + 1}}} $
where n = 1, 2, 3, 4, 5. We substitute the values and find the area.
Formula Used:
$A = \dfrac{1}{2}\sum {{x_n}{y_{n + 1}} - {y_n}{x_{n + 1}}} $
Complete step by step Solution:
Pentagon is a figure with 5 straight sides and 5 angles. A regular pentagon has 5 lines of symmetry, and rotational symmetry of order 5 (through 72°, 144°, 216°, and 288°).
A convex pentagon has no angles pointing inwards and no internal angles can be more than 180°. When any internal angle is greater than 180° it becomes a concave pentagon.
A convex pentagon is defined as one whose vertices where the sides meet, are pointing outwards unlike a concave pentagon whose vertices point inwards.
The given vertices are $A(0,0)$, $B(12,0)$,$C(12,2)$,$D(6,7)$,$E(0,5)$
Now let $({x_1},{y_1}) = (0,0)$
$({x_2},{y_2}) = (12,0)$
$({x_3},{y_3}) = (12,2)$
$({x_4},{y_4}) = (6,7)$
$({x_5},{y_5}) = (0,5)$
Now, substituting the value in formula of area of a pentagon we get,
$A = \dfrac{1}{2}[{x_1}{y_2} + {x_2}{y_3} + {x_3}{y_4} + {x_4}{y_5} + {x_5}{y_1} - ({y_1}{x_2} + {y_2}{x_3} + {y_3}{x_4} + {y_4}{x_5} + {y_5}{x_1})]$
$A = \dfrac{1}{2}[0 \times 0 + 12 \times 2 + 12 \times 7 + 6 \times 5 + 0 \times 0 - (0 + 0 + 2 \times 6 + 7 \times 0 + 0 \times 5)]$
$A = 63$
Hence, the area of the pentagon is 63 sq. units.
Hence, the correct option is E.
Note: The properties of a simple pentagon are that it must have five straight sides that meet to create five vertices but they should not self-intersect: Pentagons have 5 interior angles, which sum to 540°. The five sides do not intersect. The formula given can also be used for all polygons. There are also many ways to calculate the area of a pentagon like we can convert it into different shapes and calculate the area of each shape. It depends on the value given in the question we have to deal accordingly.
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