
If a steady current of 4 amp maintained for 40 minutes, deposits 4.5 gm of zinc at the cathode and then the electro-chemical equivalent will be
A. \[51 \times {10^{ - 17}}gm/C\]
B. \[28 \times {10^{ - 6}}gm/C\]
C. \[32 \times {10^{ - 5}}gm/C\]
D. \[47 \times {10^{ - 5}}gm/C\]
Answer
163.5k+ views
Hint: We use Faraday’s first law of electrolysis which gives the relation between the mass of ion liberated during electrolysis, electric current, and the time.
Formula Used:\[m = Zit\], where m is the mass of ion liberated from an electrolyte when current I is passed through it for the time period of t and Z is the electro-chemical equivalent of the substance.
Complete answer:According to Faraday’s first law of electrolysis the mass (m) of ions liberated from an electrolyte is directly proportional to the amount of the current (i) passed through the electrolyte during the process of electrolysis and the time (t) for which the current is flowing through the electrolyte.
Mathematically, \[m \propto it\]
\[m = Zit\]where the Z is the proportionality constant and it is a characteristic property of the substance of the electrolyte used in the process of electrolysis.
If a steady current of 4 amp is maintained for 40 minutes, deposits of 4.5 gm of zinc are at the cathode, and then the electro-chemical equivalent will be
For the given question, the amount of current passing through the electrolyte is 4A.
\[i = 4A\]
The time period in which the electric current is passing is given as 40 minutes.
On changing the time in the standard unit, we get
\[t = 40\min \]
\[t = 40 \times 60s\]
\[t = 2400s\]
The mass of zinc deposited is given as 4.5 gm.
\[m = 4.5gm\]
From faraday’s first law of electrolysis,
\[m = Zit\]
\[Z = \dfrac{m}{{it}}\]
\[Z = \dfrac{{4.5gm}}{{4 \times 2400C}}\]
\[Z = 4.7 \times {10^{ - 4}}gm/C\]
\[Z = 47 \times {10^{ - 5}}gm/C\]
Hence, the electrochemical equivalent is \[47 \times {10^{ - 5}}gm/C\]
Therefore,
the correct option is (D).
Note: We should be careful while using Faraday’s first law of electrolysis. We need to change the time to seconds. The unit of the product of the electric current and time in the standard unit will be the unit of charge.
Formula Used:\[m = Zit\], where m is the mass of ion liberated from an electrolyte when current I is passed through it for the time period of t and Z is the electro-chemical equivalent of the substance.
Complete answer:According to Faraday’s first law of electrolysis the mass (m) of ions liberated from an electrolyte is directly proportional to the amount of the current (i) passed through the electrolyte during the process of electrolysis and the time (t) for which the current is flowing through the electrolyte.
Mathematically, \[m \propto it\]
\[m = Zit\]where the Z is the proportionality constant and it is a characteristic property of the substance of the electrolyte used in the process of electrolysis.
If a steady current of 4 amp is maintained for 40 minutes, deposits of 4.5 gm of zinc are at the cathode, and then the electro-chemical equivalent will be
For the given question, the amount of current passing through the electrolyte is 4A.
\[i = 4A\]
The time period in which the electric current is passing is given as 40 minutes.
On changing the time in the standard unit, we get
\[t = 40\min \]
\[t = 40 \times 60s\]
\[t = 2400s\]
The mass of zinc deposited is given as 4.5 gm.
\[m = 4.5gm\]
From faraday’s first law of electrolysis,
\[m = Zit\]
\[Z = \dfrac{m}{{it}}\]
\[Z = \dfrac{{4.5gm}}{{4 \times 2400C}}\]
\[Z = 4.7 \times {10^{ - 4}}gm/C\]
\[Z = 47 \times {10^{ - 5}}gm/C\]
Hence, the electrochemical equivalent is \[47 \times {10^{ - 5}}gm/C\]
Therefore,
the correct option is (D).
Note: We should be careful while using Faraday’s first law of electrolysis. We need to change the time to seconds. The unit of the product of the electric current and time in the standard unit will be the unit of charge.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main 2025 Session 2: Exam Date, Admit Card, Syllabus, & More

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Trending doubts
Types of Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE

Classification of Drugs

Instantaneous Velocity - Formula based Examples for JEE

JEE Main Chemistry Question Paper with Answer Keys and Solutions

JEE Main Chemistry Online Mock Test for Class 12

Other Pages
Haloalkanes and Haloarenes

Alcohol Phenol and Ether Class 12 Notes: CBSE Chemistry Chapter 7

Coordination Compounds Class 12 Notes: CBSE Chemistry Chapter 5

NCERT Solutions for Class 12 Chemistry In Hindi Chapter 10 Haloalkanes and Haloarenes In Hindi Mediem

Total MBBS Seats in India 2025: Government College Seat Matrix

NEET Total Marks 2025: Important Information and Key Updates
