
If $5.0gm$of $BaC{{l}_{2}}$is present in ${{10}^{6}}gm$solution, the concentration is
A.$1\,ppm$
B.$5\,ppm$
C.$50\,ppm$
D.$1000\,ppm$
Answer
163.5k+ views
Hint: In solution, the concentration is the amount of solute dissolved in the solution of volume in $litre$or the solvent in $kg$. Concentration can be in terms of parts per million or $ppm$. Here we have to calculate the concentration in terms of $ppm$ by putting the given values in the respective formulas that are provided below.
Formula Used:Concentration in terms of $ppm$ $=\dfrac{mass\,\,of\,solute\,}{total\,\,mass\,\,of\,\,the\,\,solution}\times {{10}^{6}}$
Complete answer:In this problem, a definite amount of solute $BaC{{l}_{2}}$ is dissolved in a large mixture solution of mass${{10}^{6}}gm$. Here $ppm$ parts per million are best to describe the concentration of any large mixture solution. It is expressed as $1$in $1\,million$ or ${{10}^{6}}$.
There are various procedures to calculate the concentration of any solution. Generally, the concentration of any solution can be represented by the ratio of the mass of the solute to the total mass of the solution.
$\therefore $The concentration of any solution $=\dfrac{Weight\,\,of\,\,solution}{Volume\,\,in\,\,litre}$
As the given mass of the solution is very large, therefore concentration $ppm$will be a suitable way.
Given the mass of the solute, $BaC{{l}_{2}}=5.0g$
And the total mass of the solution $={{10}^{6}}gm$
$\therefore $ Concentration in$ppm=\dfrac{mass\,\,of\,solute\,}{total\,\,mass\,\,of\,\,the\,\,solution}\times {{10}^{6}}$
Or, Concentration$=\dfrac{5.0\,gm\,}{{{10}^{6}}gm}\times {{10}^{6}}=5.0\,ppm$
Thus, option (B) is correct.
Additional information: To know the exact concentration of a solution we need to know the exact amount of solute in terms of grams or moles and the mass of solvent or volume of solution. There are also other ways of expressing the concentration such as molarity, normality, mole fraction, mass percentage, and volume percentage.
Note: In chemistry especially in physical chemistry or other branched subjects mole concept is a very important fundamental concept. The given problem is also based on the mole concept. So, one should understand the concept of mole very well to deal with any problem related to this concept.
Formula Used:Concentration in terms of $ppm$ $=\dfrac{mass\,\,of\,solute\,}{total\,\,mass\,\,of\,\,the\,\,solution}\times {{10}^{6}}$
Complete answer:In this problem, a definite amount of solute $BaC{{l}_{2}}$ is dissolved in a large mixture solution of mass${{10}^{6}}gm$. Here $ppm$ parts per million are best to describe the concentration of any large mixture solution. It is expressed as $1$in $1\,million$ or ${{10}^{6}}$.
There are various procedures to calculate the concentration of any solution. Generally, the concentration of any solution can be represented by the ratio of the mass of the solute to the total mass of the solution.
$\therefore $The concentration of any solution $=\dfrac{Weight\,\,of\,\,solution}{Volume\,\,in\,\,litre}$
As the given mass of the solution is very large, therefore concentration $ppm$will be a suitable way.
Given the mass of the solute, $BaC{{l}_{2}}=5.0g$
And the total mass of the solution $={{10}^{6}}gm$
$\therefore $ Concentration in$ppm=\dfrac{mass\,\,of\,solute\,}{total\,\,mass\,\,of\,\,the\,\,solution}\times {{10}^{6}}$
Or, Concentration$=\dfrac{5.0\,gm\,}{{{10}^{6}}gm}\times {{10}^{6}}=5.0\,ppm$
Thus, option (B) is correct.
Additional information: To know the exact concentration of a solution we need to know the exact amount of solute in terms of grams or moles and the mass of solvent or volume of solution. There are also other ways of expressing the concentration such as molarity, normality, mole fraction, mass percentage, and volume percentage.
Note: In chemistry especially in physical chemistry or other branched subjects mole concept is a very important fundamental concept. The given problem is also based on the mole concept. So, one should understand the concept of mole very well to deal with any problem related to this concept.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
