
If 12 persons are seated in a row, the number of ways of selecting 3 persons from them, so that no two of them are seated next to each other.
a) 85
b) 100
c) 120
d) 240
Answer
232.8k+ views
Hint: First, select three people from the group of twelve, and then arrange the remaining nine seated people so that there is an empty seat before and after each seated person. Then occupy the empty seats with those three people in different combinations.
Formula Used:The number of ways of selecting r things out of n different things is called combinations.
\[n{C_r} = \dfrac{{n!}}{{(n - r)!r!}}\], \[0 \le r \le n\]
Complete step by step solution:First, select 3 persons out of the group of 12 persons.
Number of person to be seated in a row = 12 – 3
= 9
Now, arrange the 9 person seated in a row in such a way such that there is an empty seat before and after each seated person, as shown below. Yellow shaded boxes represent the seats occupied by 9 persons.
From the figure, it is clear that there are 10 empty seats among and around the 9 seated persons.
The 3 persons who were chosen earlier can now be seated in different combinations among the 10 empty seats, so that no two of them are seated next to each other.
Number of ways 3 persons can be seated among the 10 empty seats = \[10{C_3}\]
\[ = \dfrac{{10!}}{{(10 - 3)!3!}}\]
\[ = \dfrac{{10 \times 9 \times 8}}{{3 \times 2 \times 1}}\]
\[ = 5 \times 3 \times 8\]
= 120
Option ‘C’ is correct
Note: Student may ignore the empty seats at the extremes and calculated wrongly as\[8{C_3}\].
Student may wrongly calculate the empty seats as 9 and calculated wrongly as \[9{C_3}\].
Formula Used:The number of ways of selecting r things out of n different things is called combinations.
\[n{C_r} = \dfrac{{n!}}{{(n - r)!r!}}\], \[0 \le r \le n\]
Complete step by step solution:First, select 3 persons out of the group of 12 persons.
Number of person to be seated in a row = 12 – 3
= 9
Now, arrange the 9 person seated in a row in such a way such that there is an empty seat before and after each seated person, as shown below. Yellow shaded boxes represent the seats occupied by 9 persons.
From the figure, it is clear that there are 10 empty seats among and around the 9 seated persons.
The 3 persons who were chosen earlier can now be seated in different combinations among the 10 empty seats, so that no two of them are seated next to each other.
Number of ways 3 persons can be seated among the 10 empty seats = \[10{C_3}\]
\[ = \dfrac{{10!}}{{(10 - 3)!3!}}\]
\[ = \dfrac{{10 \times 9 \times 8}}{{3 \times 2 \times 1}}\]
\[ = 5 \times 3 \times 8\]
= 120
Option ‘C’ is correct
Note: Student may ignore the empty seats at the extremes and calculated wrongly as\[8{C_3}\].
Student may wrongly calculate the empty seats as 9 and calculated wrongly as \[9{C_3}\].
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding Electromagnetic Waves and Their Importance

Inductive Effect and Its Role in Acidic Strength

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Average and RMS Value in Electrical Circuits

Other Pages
Understanding Collisions: Types and Examples for Students

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Chemistry Question Papers for JEE Main, NEET & Boards (PDFs)

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Keys & Solutions

If y xxx cdots infty then find dfracdydx A yxy 1 B class 12 maths JEE_Main

JEE Advanced 2026 Revision Notes for Practical Organic Chemistry

