
Four identical rods of the same material are joined at ends so as to form a square. If the temperature difference at the ends of a diagonal is ${{100}^{\circ }}C$, then the temperature difference across the ends of another diagonal will be
A. ${{0}^{\circ }}C$
B. ${{25}^{\circ }}C$
C. ${{50}^{\circ }}C$
D. ${{100}^{\circ }}C$
Answer
232.8k+ views
Hint: We have given four identical rods which are joined to form a square and we have to find the temperature difference across the diagonals. As we know heat will be transferred due to temperature difference and heat flows from higher temperature to lower temperature. So by using the difference in the temperature , we are able to find the temperature difference.
Complete step by step solution:
Let the four identical rods be A,B,C and D which have AC and BD as a diagonal point. We are asked to find the temperature difference between points B and D, which is ${{T}_{B}}-{{T}_{D}}$.
Consider the temperature at A = ${{T}^{\circ }}C$
Therefore, temperature at C = $t+{{100}^{\circ }}C$
As heat is conducted from A to C via B or D. B and D lie midway along with the passing of heat conduction through ABC and ADC respectively.
Hence temperature of B = \[\dfrac{t+(t+100)}{2}\] = $t+{{50}^{\circ }}C$
Similarly temperature of D = \[\dfrac{t+(t+100)}{2}\] = $t+{{50}^{\circ }}C$
So the temperature difference across the ends of another diagonal will be ${{0}^{\circ }}C$.
Hence, option A is the correct answer.
Note: By conduction, we mean the transfer of energy when one of the parts of an object is heated and it gets excited and transfers energy to its nearest particle, which further transmits the energy and with this process, heat energy gets transferred from one end to another.
Complete step by step solution:
Let the four identical rods be A,B,C and D which have AC and BD as a diagonal point. We are asked to find the temperature difference between points B and D, which is ${{T}_{B}}-{{T}_{D}}$.
Consider the temperature at A = ${{T}^{\circ }}C$
Therefore, temperature at C = $t+{{100}^{\circ }}C$
As heat is conducted from A to C via B or D. B and D lie midway along with the passing of heat conduction through ABC and ADC respectively.
Hence temperature of B = \[\dfrac{t+(t+100)}{2}\] = $t+{{50}^{\circ }}C$
Similarly temperature of D = \[\dfrac{t+(t+100)}{2}\] = $t+{{50}^{\circ }}C$
So the temperature difference across the ends of another diagonal will be ${{0}^{\circ }}C$.
Hence, option A is the correct answer.
Note: By conduction, we mean the transfer of energy when one of the parts of an object is heated and it gets excited and transfers energy to its nearest particle, which further transmits the energy and with this process, heat energy gets transferred from one end to another.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

