
For any vector $a$ , which is the value of ${\left| {a \times i} \right|^2} + {\left| {a \times j} \right|^2} + {\left| {a \times k} \right|^2}$ ?
A. ${\left| a \right|^2}$
B. $2{\left| a \right|^2}$
C. $3{\left| a \right|^2}$
D. $4{\left| a \right|^2}$
Answer
164.4k+ views
Hint: To find the solution to a given problem, the properties of cross-product (vector-product) between two vectors must be known. In this problem, we will first assume any random vector $a$, apply the properties of a cross-product and then compute the modulus of the resulting vector to find the correct solution to the given problem.
Formula used:
The cross product of unit vectors used in this problem are: -
$\widehat i \times \widehat i = \widehat j \times \widehat j = \widehat k \times \widehat k = 0$ and $\widehat i \times \widehat j = - \widehat j \times \widehat i = \widehat k$ , $\widehat j \times \widehat k = - \widehat k \times \widehat j = \widehat i$ & $\widehat k \times \widehat i = - \widehat i \times \widehat k = \widehat j$and the modulus of any vector $a$ is given as:
$\left| {\overrightarrow a } \right| = \left( {\sqrt {{x^2} + {y^2} + {z^2}} } \right)$
Complete step by step solution:
Let us first consider the value of $\overrightarrow a = x\widehat i + y\widehat j + z\widehat k$.
Let, ${\left| {a \times i} \right|^2} + {\left| {a \times j} \right|^2} + {\left| {a \times k} \right|^2}$ $\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\,(1)$
Now, let us find out the values of the given expressions one by one in the problem: -
For cross-product with Vector $\widehat i$ ,
$a \times \widehat i = \left( {(x\widehat i + y\widehat j + z\widehat k) \times \widehat i} \right) = \left( {x(\widehat i \times \widehat i) + y(\widehat j \times \widehat i) + z(\widehat k \times \widehat i)} \right) = \left( {0 + y( - \widehat k) + z(\widehat j)} \right) = \left( { - y\widehat k + z\widehat j} \right)$
By taking the modulus and then squaring it, we will get: -
${\left| {a \times \widehat i} \right|^2} = {\left( {\sqrt {{{( - y)}^2} + {z^2}} } \right)^2} = {y^2} + {z^2}$
For cross-product with Vector $\widehat j$ ,
$a \times \widehat j = \left( {(x\widehat i + y\widehat j + z\widehat k) \times \widehat j} \right) = \left( {x(\widehat i \times \widehat j) + y(\widehat j \times \widehat j) + z(\widehat k \times \widehat j)} \right) = \left( {x(\widehat k) + 0 + z( - \widehat i)} \right) = \left( {x\widehat k - z\widehat i} \right)$By taking the modulus and then squaring it, we will get: -
${\left| {a \times \widehat j} \right|^2} = {\left( {\sqrt {{x^2} + {{( - z)}^2}} } \right)^2} = {x^2} + {z^2}$
For cross-product with Vector $\widehat k$ ,
By taking the modulus and then squaring it, we will get: -
$a \times \widehat k = \left( {(x\widehat i + y\widehat j + z\widehat k) \times \widehat k} \right) = \left( {x(\widehat i \times \widehat k) + y(\widehat j \times \widehat k) + z(\widehat k \times \widehat k)} \right) = \left( {x( - \widehat j) + y(\widehat i) + 0} \right) = \left( { - x\widehat j + y\widehat i} \right)$ -
${\left| {a \times \widehat k} \right|^2} = {\left( {\sqrt {{{( - x)}^2} + {y^2}} } \right)^2} = {x^2} + {y^2}$
Now substitute the values in eq. $\left( 1 \right)$ , we get
${\left| {a \times i} \right|^2} + {\left| {a \times j} \right|^2} + {\left| {a \times k} \right|^2} = ({y^2} + {z^2}) + ({x^2} + {z^2}) + ({x^2} + {y^2}) = 2({x^2} + {y^2} + {z^2})$ $\,\,...\,(2)$
Let us find the modulus of the vector $a$and square it, we get
${\left| {\overrightarrow a } \right|^2} = {\left( {\sqrt {{x^2} + {y^2} + {z^2}} } \right)^2} = {x^2} + {y^2} + {z^2}$
Now, on substituting this value in equation $\left( 2 \right)$ , we get
${\left| {a \times i} \right|^2} + {\left| {a \times j} \right|^2} + {\left| {a \times k} \right|^2} = 2({x^2} + {y^2} + {z^2}) = 2{\left| {\overrightarrow a } \right|^2}$
Thus, the final value of the expression given is $2{\left| {\overrightarrow a } \right|^2}$.
Hence, the correct option is: (B) $2{\left| a \right|^2}$
Note: Since the problem is based on Vector Algebra, it is essential to analyze the given conditions carefully on the basis of which the procedure of solving the problem is identified. Also, we can use the natural formula of cross-product by using the determinant method here. Calculations must be performed very carefully and all the signs of the vector must be used in the solution in a proper manner.
Formula used:
The cross product of unit vectors used in this problem are: -
$\widehat i \times \widehat i = \widehat j \times \widehat j = \widehat k \times \widehat k = 0$ and $\widehat i \times \widehat j = - \widehat j \times \widehat i = \widehat k$ , $\widehat j \times \widehat k = - \widehat k \times \widehat j = \widehat i$ & $\widehat k \times \widehat i = - \widehat i \times \widehat k = \widehat j$and the modulus of any vector $a$ is given as:
$\left| {\overrightarrow a } \right| = \left( {\sqrt {{x^2} + {y^2} + {z^2}} } \right)$
Complete step by step solution:
Let us first consider the value of $\overrightarrow a = x\widehat i + y\widehat j + z\widehat k$.
Let, ${\left| {a \times i} \right|^2} + {\left| {a \times j} \right|^2} + {\left| {a \times k} \right|^2}$ $\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\,(1)$
Now, let us find out the values of the given expressions one by one in the problem: -
For cross-product with Vector $\widehat i$ ,
$a \times \widehat i = \left( {(x\widehat i + y\widehat j + z\widehat k) \times \widehat i} \right) = \left( {x(\widehat i \times \widehat i) + y(\widehat j \times \widehat i) + z(\widehat k \times \widehat i)} \right) = \left( {0 + y( - \widehat k) + z(\widehat j)} \right) = \left( { - y\widehat k + z\widehat j} \right)$
By taking the modulus and then squaring it, we will get: -
${\left| {a \times \widehat i} \right|^2} = {\left( {\sqrt {{{( - y)}^2} + {z^2}} } \right)^2} = {y^2} + {z^2}$
For cross-product with Vector $\widehat j$ ,
$a \times \widehat j = \left( {(x\widehat i + y\widehat j + z\widehat k) \times \widehat j} \right) = \left( {x(\widehat i \times \widehat j) + y(\widehat j \times \widehat j) + z(\widehat k \times \widehat j)} \right) = \left( {x(\widehat k) + 0 + z( - \widehat i)} \right) = \left( {x\widehat k - z\widehat i} \right)$By taking the modulus and then squaring it, we will get: -
${\left| {a \times \widehat j} \right|^2} = {\left( {\sqrt {{x^2} + {{( - z)}^2}} } \right)^2} = {x^2} + {z^2}$
For cross-product with Vector $\widehat k$ ,
By taking the modulus and then squaring it, we will get: -
$a \times \widehat k = \left( {(x\widehat i + y\widehat j + z\widehat k) \times \widehat k} \right) = \left( {x(\widehat i \times \widehat k) + y(\widehat j \times \widehat k) + z(\widehat k \times \widehat k)} \right) = \left( {x( - \widehat j) + y(\widehat i) + 0} \right) = \left( { - x\widehat j + y\widehat i} \right)$ -
${\left| {a \times \widehat k} \right|^2} = {\left( {\sqrt {{{( - x)}^2} + {y^2}} } \right)^2} = {x^2} + {y^2}$
Now substitute the values in eq. $\left( 1 \right)$ , we get
${\left| {a \times i} \right|^2} + {\left| {a \times j} \right|^2} + {\left| {a \times k} \right|^2} = ({y^2} + {z^2}) + ({x^2} + {z^2}) + ({x^2} + {y^2}) = 2({x^2} + {y^2} + {z^2})$ $\,\,...\,(2)$
Let us find the modulus of the vector $a$and square it, we get
${\left| {\overrightarrow a } \right|^2} = {\left( {\sqrt {{x^2} + {y^2} + {z^2}} } \right)^2} = {x^2} + {y^2} + {z^2}$
Now, on substituting this value in equation $\left( 2 \right)$ , we get
${\left| {a \times i} \right|^2} + {\left| {a \times j} \right|^2} + {\left| {a \times k} \right|^2} = 2({x^2} + {y^2} + {z^2}) = 2{\left| {\overrightarrow a } \right|^2}$
Thus, the final value of the expression given is $2{\left| {\overrightarrow a } \right|^2}$.
Hence, the correct option is: (B) $2{\left| a \right|^2}$
Note: Since the problem is based on Vector Algebra, it is essential to analyze the given conditions carefully on the basis of which the procedure of solving the problem is identified. Also, we can use the natural formula of cross-product by using the determinant method here. Calculations must be performed very carefully and all the signs of the vector must be used in the solution in a proper manner.
Recently Updated Pages
Geometry of Complex Numbers – Topics, Reception, Audience and Related Readings

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Instantaneous Velocity - Formula based Examples for JEE

JEE Advanced 2025 Notes

JEE Main Chemistry Question Paper with Answer Keys and Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE
