
Express the following numbers in scientific notation:
(i) 0.0048
(ii) 234,000
(iii) 8008
(iv) 500.0
(v) 6.0012
Answer
161.1k+ views
Hint: Scientific notation is a way of representing very large or very small numbers that are written in decimal form to a simpler form i.e. a number that is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10. Numbers written in scientific notation are written in the form\[A \times {10^n}\] , where A is a number between 1 and 10, but not 10 itself, and n is any integer (positive or negative number).
Complete Step by Step Solution:
Steps to write a number in scientific notation are as follows:-
For a large number,
Step 1: Move the decimal point to the left to create a number greater than or equal to 1 and less than 10.
Step 2: Calculate the number of decimal places you moved the decimal point to the left and use that number as the positive power of 10.
Step 3: Substitute the value of A and n in the general form of scientific notation i.e.
For a small number,
Step 1: Move the decimal point to the left to create a number greater than or equal to 1 and less than 10.
Step 2: Calculate the number of decimal places you moved the decimal point to the right and use that number as the negative power of 10.
Step 3: Substitute the value of A and n in the general form of scientific notation i.e.
Hence, of the given options:
(1) 0.0048 in scientific notation is \[4.8 \times {10^{ - 3}}\] .
(2) 234,000 in scientific notation is \[2.34 \times {10^5}\] .
(3) 8008 in scientific notation is \[8.008 \times {10^3}\] .
(4) 500.0 in scientific notation is \[5.000 \times {10^2}\] .
(5) 6.0012 in scientific notation is 6.0012.
Note: To determine the power or exponent of 10, we must follow the rules listed below:
1) The base should always be 10.
2) The exponent must be a non-zero integer (it can be either positive or negative).
3) The absolute value of the coefficient is greater than or equal to 1 but it should always be less than 10.
4) Coefficient can be a positive or negative number including whole and decimal numbers.
Complete Step by Step Solution:
Steps to write a number in scientific notation are as follows:-
For a large number,
Step 1: Move the decimal point to the left to create a number greater than or equal to 1 and less than 10.
Step 2: Calculate the number of decimal places you moved the decimal point to the left and use that number as the positive power of 10.
Step 3: Substitute the value of A and n in the general form of scientific notation i.e.
For a small number,
Step 1: Move the decimal point to the left to create a number greater than or equal to 1 and less than 10.
Step 2: Calculate the number of decimal places you moved the decimal point to the right and use that number as the negative power of 10.
Step 3: Substitute the value of A and n in the general form of scientific notation i.e.
Hence, of the given options:
(1) 0.0048 in scientific notation is \[4.8 \times {10^{ - 3}}\] .
(2) 234,000 in scientific notation is \[2.34 \times {10^5}\] .
(3) 8008 in scientific notation is \[8.008 \times {10^3}\] .
(4) 500.0 in scientific notation is \[5.000 \times {10^2}\] .
(5) 6.0012 in scientific notation is 6.0012.
Note: To determine the power or exponent of 10, we must follow the rules listed below:
1) The base should always be 10.
2) The exponent must be a non-zero integer (it can be either positive or negative).
3) The absolute value of the coefficient is greater than or equal to 1 but it should always be less than 10.
4) Coefficient can be a positive or negative number including whole and decimal numbers.
Recently Updated Pages
Two pi and half sigma bonds are present in A N2 + B class 11 chemistry JEE_Main

Which of the following is most stable A Sn2+ B Ge2+ class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

The specific heat of metal is 067 Jg Its equivalent class 11 chemistry JEE_Main

The increasing order of a specific charge to mass ratio class 11 chemistry JEE_Main

Which one of the following is used for making shoe class 11 chemistry JEE_Main

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Displacement-Time Graph and Velocity-Time Graph for JEE

Degree of Dissociation and Its Formula With Solved Example for JEE

Free Radical Substitution Mechanism of Alkanes for JEE Main 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced 2025 Notes
