
What is the electronic configuration for tin?
$\begin{align}
& \text{A}\text{. }\!\![\!\!\text{ Kr }\!\!]\!\!\text{ 5}{{\text{s}}^{\text{2}}}\text{5}{{\text{p}}^{\text{2}}} \\
& \text{B}\text{. }\!\![\!\!\text{ Kr }\!\!]\!\!\text{ 4}{{\text{d}}^{\text{10}}}\text{5}{{\text{s}}^{\text{2}}}\text{5}{{\text{p}}^{\text{2}}} \\
& \text{C}\text{.1}{{\text{s}}^{\text{2}}}\text{2}{{\text{s}}^{\text{2}}}\text{2}{{\text{p}}^{\text{6}}}\text{3}{{\text{s}}^{\text{2}}}\text{3}{{\text{p}}^{\text{6}}}\text{3}{{\text{d}}^{\text{10}}}\text{4}{{\text{s}}^{\text{2}}}\text{4}{{\text{p}}^{\text{2}}} \\
& \text{D}\text{. }\!\![\!\!\text{ Kr }\!\!]\!\!\text{ 4}{{\text{d}}^{\text{11}}}\text{5}{{\text{s}}^{\text{2}}}\text{5}{{\text{p}}^{\text{1}}} \\
\end{align}$
Answer
221.4k+ views
Hint:To answer this question the information of tin atomic number must be known. The tin has an atomic number of 50, which means tin has 50 electrons. Thus, Aufbau principle will be utilized to solve the question.
Complete step by step answer:
The electronic configuration can be described via Aufbau principle.
This principle states that the electrons of an atom or ions, that are in ground state, fill the orbital of lower energy first then they enter to the highest energy orbital.
For example, the electrons first enter to 1s then 2s then 2p, 3s, 3p, 4s, 3d and so on.
The atom or ions are most stable when the s, p, d, f orbital are fully or half filled with electrons.
Tin (symbol – Sn) has an atomic number 50. It means it has 50 electrons.
Here, as the electron of tin reaches and fulfil the vacant orbitals it would be filling the orbital as following according to the Aufbau principle i.e. 1s, 2s,2p,3s,3p,4s,3d,4p,5s,4d and 5p orbitals.
Tin lies in the group-14 of the periodic table, so it’s electronic configuration will be similar to the carbon.
So the electronic configuration is $\text{1}{{\text{s}}^{\text{2}}}\text{2}{{\text{s}}^{\text{2}}}\text{2}{{\text{p}}^{\text{6}}}\text{3}{{\text{s}}^{\text{2}}}\text{3}{{\text{p}}^{\text{6}}}\text{3}{{\text{d}}^{\text{10}}}\text{4}{{\text{s}}^{\text{2}}}\text{4}{{\text{p}}^{\text{6}}}\text{4}{{\text{d}}^{\text{10}}}\text{5}{{\text{s}}^{\text{2}}}\text{5}{{\text{p}}^{\text{2}}}$ or \[\text{ }\!\![\!\!\text{ Kr }\!\!]\!\!\text{ 4}{{\text{d}}^{\text{10}}}\text{5}{{\text{s}}^{\text{2}}}\text{5}{{\text{p}}^{\text{2}}}\]as Krypton has electronic configuration $\text{1}{{\text{s}}^{\text{2}}}\text{2}{{\text{s}}^{\text{2}}}\text{2}{{\text{p}}^{\text{6}}}\text{3}{{\text{s}}^{\text{2}}}\text{3}{{\text{p}}^{\text{6}}}\text{3}{{\text{d}}^{\text{10}}}\text{4}{{\text{s}}^{\text{2}}}\text{4}{{\text{p}}^{\text{6}}}$.
So, the correct answer is option-B.
Note:
Aufbau principle describes the manner of electrons filled in an atomic orbital of an atom in the ground state configuration. The principle stated that, based on the energy level of atomic orbital electron fills happen. The electron fills to the respective atomic orbital happens with the fact that lowest energy orbitals are first occupied by electrons, if they completely fill then in the higher energy level orbitals start to be occupied by electrons.
Complete step by step answer:
The electronic configuration can be described via Aufbau principle.
This principle states that the electrons of an atom or ions, that are in ground state, fill the orbital of lower energy first then they enter to the highest energy orbital.
For example, the electrons first enter to 1s then 2s then 2p, 3s, 3p, 4s, 3d and so on.
The atom or ions are most stable when the s, p, d, f orbital are fully or half filled with electrons.
Tin (symbol – Sn) has an atomic number 50. It means it has 50 electrons.
Here, as the electron of tin reaches and fulfil the vacant orbitals it would be filling the orbital as following according to the Aufbau principle i.e. 1s, 2s,2p,3s,3p,4s,3d,4p,5s,4d and 5p orbitals.
Tin lies in the group-14 of the periodic table, so it’s electronic configuration will be similar to the carbon.
So the electronic configuration is $\text{1}{{\text{s}}^{\text{2}}}\text{2}{{\text{s}}^{\text{2}}}\text{2}{{\text{p}}^{\text{6}}}\text{3}{{\text{s}}^{\text{2}}}\text{3}{{\text{p}}^{\text{6}}}\text{3}{{\text{d}}^{\text{10}}}\text{4}{{\text{s}}^{\text{2}}}\text{4}{{\text{p}}^{\text{6}}}\text{4}{{\text{d}}^{\text{10}}}\text{5}{{\text{s}}^{\text{2}}}\text{5}{{\text{p}}^{\text{2}}}$ or \[\text{ }\!\![\!\!\text{ Kr }\!\!]\!\!\text{ 4}{{\text{d}}^{\text{10}}}\text{5}{{\text{s}}^{\text{2}}}\text{5}{{\text{p}}^{\text{2}}}\]as Krypton has electronic configuration $\text{1}{{\text{s}}^{\text{2}}}\text{2}{{\text{s}}^{\text{2}}}\text{2}{{\text{p}}^{\text{6}}}\text{3}{{\text{s}}^{\text{2}}}\text{3}{{\text{p}}^{\text{6}}}\text{3}{{\text{d}}^{\text{10}}}\text{4}{{\text{s}}^{\text{2}}}\text{4}{{\text{p}}^{\text{6}}}$.
So, the correct answer is option-B.
Note:
Aufbau principle describes the manner of electrons filled in an atomic orbital of an atom in the ground state configuration. The principle stated that, based on the energy level of atomic orbital electron fills happen. The electron fills to the respective atomic orbital happens with the fact that lowest energy orbitals are first occupied by electrons, if they completely fill then in the higher energy level orbitals start to be occupied by electrons.
Recently Updated Pages
The hybridization and shape of NH2 ion are a sp2 and class 11 chemistry JEE_Main

What is the pH of 001 M solution of HCl a 1 b 10 c class 11 chemistry JEE_Main

Aromatization of nhexane gives A Benzene B Toluene class 11 chemistry JEE_Main

Show how you will synthesise i 1Phenylethanol from class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

Which of the following Compounds does not exhibit tautomerism class 11 chemistry JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

