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# Define 1 Ohm resistance. A student has a resistance wire of 1 Ohm. If the length of this wire is 50cm, to what length he should stretch it uniformly so as to obtain a wire of 4 Ohms resistance? Justify your answer.

Last updated date: 09th Apr 2024
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Hint: From ohm’s law, the definition of 1 ohm resistance can be defined. The resistance of a substance is directly proportional to its length.

Formula used: In this solution we will be using the following formulae;
$R = \dfrac{V}{I}$ where $R$ is resistance, $V$ is voltage and $I$ is current.
$R = \rho \dfrac{l}{A}$ where $\rho$ is the resistivity of the wire, $l$ is the length and $A$ is the cross sectional area.

Complete Step-by-Step Solution:
From the ohm law equation, the definition of 1 ohm, could be derived.
The ohm’s law equation is can be written as
$R = \dfrac{V}{I}$ where $R$ is resistance, $V$ is voltage and $I$ is current.
Hence, for 1 ohms, we can write
$1\Omega = \dfrac{{1{\text{V}}}}{{1{\text{A}}}}$
Hence, 1 ohm’s could be defined as the resistance to a 1 A current which causes 1 volt potential difference or voltage drop. Or it can be defined as the resistance value which would allow only 1 A of current to flow when the component is connected to a 1 volt source.
For the second part of the question, a student possesses a resistance wire of 1 ohms which has a length 50 cm. to what length should he stretch it uniformly to obtain a resistance wire of 4 ohms.
Recall that the resistance of a wire can be given as
$R = \rho \dfrac{l}{A}$ where $\rho$ is the resistivity of the wire, $l$ is the length and $A$ is the cross sectional area.
Hence, if the all other properties are kept constant,
$\dfrac{R}{l} = k$ where $k$ is a constant.
Then,
$\dfrac{{{R_1}}}{{{l_1}}} = \dfrac{{{R_2}}}{{{l_2}}}$
$\Rightarrow \dfrac{1}{{50}} = \dfrac{4}{{{l_2}}}$
Hence, by cross multiplication,
${l_2} = 50 \times 4 = 250cm$

Hence, the length of the wire has to be stretched to 250 cm.

Note: In actuality, the wire would not need to stretch that far before the resistance actually attains 4 ohms as desired. This is due to the Poisson phenomenon, which is the fact that as the length stretches, the cross sectional area of the wire will reduce, hence creating a double effect of increment of resistivity (the smaller the cross sectional area, the lower the resistance).