Question

Consider an amylose chain of $4000$ glucose units. At how much cleavage requires to lower the average length to $400$ units.

Answer 1

Hint: You only have to calculate that for each fragment how many units are obtained from which you will get the fragments per unit after which you only have to find the cleavage required and there is your answer.

Complete step by step solution:
As given in the question that,
Amylose chain of glucose unit = $4000$ glucose units
And we want to lower it to the average length = $400$ units.
Now for this firstly we find the fragment for each unit,
For each unit we know that,
For each fragment of $400$units = $\dfrac{{total}}{{average}}$
By using that we get that,
$ = \dfrac{{4000}}{{400}}$
As by doing further solution we get the fragments for unit length,
$ = 10$ fragments are obtained for $400$ unit length
Now after getting unit length we have to find the Glycosidic linkage Cleavage =
$ = 10 - 1$
As per doing further solution we get that,
$ = 9$
Therefore, the cleavage required to lower the average length to $400$ units is $9$ .

Note: We must know that Plants use amylose, a straight chain of glucose molecules, as a means of storing energy. It is composed of molecules of alpha-D-glucose joined by covalent alpha $(1,4)$ glycosidic linkages. One amylose molecule often contains hundreds or thousands of glucose molecules.