Answer
64.8k+ views
Hint: Electrolytic refining process is used for purification of metal. Metals obtained after smelting or other methods may contain impurities like unreacted oxides, other metals, non- metals and gases.
The purification of crude metals by removing metallic and non- metallic impurities is known as refining.
Complete step by step answer:
In electrolytic refining, anode [positively charged] and cathode [negatively charged] electrode is dipped into aqueous solution of their salt.
The rod of impure metal is used as anode and thin sheet of pure metal as cathode.
During electrolysis, metal from anode dissolve in the solution while the same amount of pure metal deposits on cathode.
The impurities like more reactive metals dissolve in the solution.
Less reactive metals are insoluble. They form anode mud at the bottom.
In this process $99.99\% $ pure metal is obtained.
Metals like $Ni,Al,Zn$ are refined by his method.
![](https://www.vedantu.com/question-sets/18769ef8-c905-4a08-a073-23ae1b0bddc74760402600619044597.png)
In the given question:
Assertion is – impure metal is made cathode while a strip of pure metal is used as anode.
But as we already discussed, impure metal is made anode and pure metal is used as cathode.
Reason is – The pure metal gets deposited at anode mud.
But pure metal gets deposited at cathode and impurities form anode mud.
Therefore, the above explanation, the correct option is [D] Both assertion and reason are incorrect.
Note: Impure metal is made anode and pure metal strip is made cathode during electrolytic refining. During electrolysis pure metal from impure anode gets dissolved in the solution. As metal is always positively charged, it is migrated towards cathode and deposit. then cathodes become thick and replaced from time to time.
The purification of crude metals by removing metallic and non- metallic impurities is known as refining.
Complete step by step answer:
In electrolytic refining, anode [positively charged] and cathode [negatively charged] electrode is dipped into aqueous solution of their salt.
The rod of impure metal is used as anode and thin sheet of pure metal as cathode.
During electrolysis, metal from anode dissolve in the solution while the same amount of pure metal deposits on cathode.
The impurities like more reactive metals dissolve in the solution.
Less reactive metals are insoluble. They form anode mud at the bottom.
In this process $99.99\% $ pure metal is obtained.
Metals like $Ni,Al,Zn$ are refined by his method.
![](https://www.vedantu.com/question-sets/18769ef8-c905-4a08-a073-23ae1b0bddc74760402600619044597.png)
In the given question:
Assertion is – impure metal is made cathode while a strip of pure metal is used as anode.
But as we already discussed, impure metal is made anode and pure metal is used as cathode.
Reason is – The pure metal gets deposited at anode mud.
But pure metal gets deposited at cathode and impurities form anode mud.
Therefore, the above explanation, the correct option is [D] Both assertion and reason are incorrect.
Note: Impure metal is made anode and pure metal strip is made cathode during electrolytic refining. During electrolysis pure metal from impure anode gets dissolved in the solution. As metal is always positively charged, it is migrated towards cathode and deposit. then cathodes become thick and replaced from time to time.
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