Assertion: Pulling a lawn roller is easier than pushing it.
Reason: Pushing increases the apparent weight and hence the force of friction.
A. Both Assertion and Reason is true and Reason is the correct explanation of Assertion.
B. Both Assertion and Reason is true and Reason is not the correct explanation of Assertion.
C. Assertion is true, but Reason is false
D. Assertion is false, but Reason is true
Answer
282.3k+ views
Hint:Use the concept of force applied in horizontal and vertical direction while pushing and pulling of a lawn roller. Then find the change in weight of the body that is the lawn roller here with respect to the horizontal and vertical force applied on the body while pushing and pulling.
Formula used
Horizontal force, ${F_H} = F\cos \theta $
Vertical force, ${F_V} = F\sin \theta $
Complete answer:
Here, there are two cases of pulling and pushing a lawn roller.
Case1: Pulling
When we applied force F at an angle $\theta $ then we get two component of force;
Horizontal force, ${F_H} = F\cos \theta $
Vertical force, ${F_V} = F\sin \theta $
This vertical force will act in the opposite direction of weight.
Therefore, the apparent weight = $mg - F\sin \theta $
That means the weight will decrease. Hence, pulling becomes easier.
Case2: Pushing
When we applied force F at an angle $\theta $ in case of pushing then we get two component of force;
Horizontal force, ${F_H} = F\cos \theta $
Vertical force, ${F_V} = F\sin \theta $
But here this vertical force will be in the direction of weight.
Therefore, the apparent weight = $mg + F\sin \theta $
That means the weight will increase. Hence, pushing becomes difficult.
Thus, Assertion and Reason both are true.
Hence, the correct answer is Option A.
Note: Be careful of the vertical component of the force applied on the body that is a lawn roller here, it is the deciding factor as the direction of the vertical force will increase or decrease the weight of the body and then we get the apparent weight which make pulling easier and pushing difficult.
Formula used
Horizontal force, ${F_H} = F\cos \theta $
Vertical force, ${F_V} = F\sin \theta $
Complete answer:
Here, there are two cases of pulling and pushing a lawn roller.
Case1: Pulling
When we applied force F at an angle $\theta $ then we get two component of force;
Horizontal force, ${F_H} = F\cos \theta $
Vertical force, ${F_V} = F\sin \theta $
This vertical force will act in the opposite direction of weight.
Therefore, the apparent weight = $mg - F\sin \theta $
That means the weight will decrease. Hence, pulling becomes easier.
Case2: Pushing
When we applied force F at an angle $\theta $ in case of pushing then we get two component of force;
Horizontal force, ${F_H} = F\cos \theta $
Vertical force, ${F_V} = F\sin \theta $
But here this vertical force will be in the direction of weight.
Therefore, the apparent weight = $mg + F\sin \theta $
That means the weight will increase. Hence, pushing becomes difficult.
Thus, Assertion and Reason both are true.
Hence, the correct answer is Option A.
Note: Be careful of the vertical component of the force applied on the body that is a lawn roller here, it is the deciding factor as the direction of the vertical force will increase or decrease the weight of the body and then we get the apparent weight which make pulling easier and pushing difficult.
Recently Updated Pages
How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

Mass vs Weight: Key Differences Explained for Students

Uniform Acceleration Explained: Formula, Examples & Graphs

JEE Main 2025-26 Mock Test: Binomial Theorem & Quick Practice

Properties of Solids and Liquids Mock Test 2025

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Derivation of Equation of Trajectory Explained for Students

Electron Gain Enthalpy and Electron Affinity Explained

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2026-27

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2026-27 Free PDF Download (Login Required)

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2026-27

NCERT Solutions For Class 11 Physics Chapter 2 Motion In A Straight Line - 2026-27 Free PDF Download (Login Required)

CBSE Notes Class 11 Physics Chapter 2 - Motion in a Straight Line - 2026-27

