
Among $C{{l}^{-}},B{{r}^{-}},{{I}^{-}}$ , the correct order for being oxidise to dihalogen is
A. ${{I}^{-}}>C{{l}^{-}}>B{{r}^{-}}$
B. $C{{l}^{-}}>B{{r}^{-}}>{{I}^{-}}$
C. ${{I}^{-}}>B{{r}^{-}}>C{{l}^{-}}$
D. $B{{r}^{-}}>{{I}^{-}}>C{{l}^{-}}$
Answer
163.2k+ views
Hint: In this question, we have to answer the correct order of the ions being oxidised easily. Oxidation state is the charge of an atom if all of its bonds to other atoms were fully charged.
Complete Step by Step Solution:
We know group 17 are referred as halogens and are known as halogen groups. This group consists of fluorine, chlorine, bromine, iodine and a radioactive element astatine.
We know all the elements of the halogen family show -1 oxidation state and fluorine is the most electronegative element.
We know as we move down the group, the atomic size goes on increasing because of the increase in the number of shells. Due to this, electron density goes on decreasing. So the fluorine molecule will be the strongest oxidising agent due to its small size. On the other hand, iodine exists as the weakest oxidising agent.
The tendency of the halogens to form ionic compounds increases in the following order :-
Astatine < iodine < bromine < chlorine < fluorine
So fluorides are more stable than chlorides, bromides or iodides.
Hence, fluorine ions will have the lowest oxidation state.
Iodine will exist with the strongest oxidation state.
Thus the correct order for oxidation to dihalogen is
${{I}^{-}}>C{{l}^{-}}>B{{r}^{-}}$
Thus, Option (A) is correct.
Note: Students become confused in the oxidising agent and in oxidation state. Remember that oxidation is the process of losing or gaining electrons or losing hydrogens and oxidising agent is the substance which donates electrons or oxygen or gains hydrogen.
Complete Step by Step Solution:
We know group 17 are referred as halogens and are known as halogen groups. This group consists of fluorine, chlorine, bromine, iodine and a radioactive element astatine.
We know all the elements of the halogen family show -1 oxidation state and fluorine is the most electronegative element.
We know as we move down the group, the atomic size goes on increasing because of the increase in the number of shells. Due to this, electron density goes on decreasing. So the fluorine molecule will be the strongest oxidising agent due to its small size. On the other hand, iodine exists as the weakest oxidising agent.
The tendency of the halogens to form ionic compounds increases in the following order :-
Astatine < iodine < bromine < chlorine < fluorine
So fluorides are more stable than chlorides, bromides or iodides.
Hence, fluorine ions will have the lowest oxidation state.
Iodine will exist with the strongest oxidation state.
Thus the correct order for oxidation to dihalogen is
${{I}^{-}}>C{{l}^{-}}>B{{r}^{-}}$
Thus, Option (A) is correct.
Note: Students become confused in the oxidising agent and in oxidation state. Remember that oxidation is the process of losing or gaining electrons or losing hydrogens and oxidising agent is the substance which donates electrons or oxygen or gains hydrogen.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
