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# A vertical hanging bar of length \$l\$ and mass \[m\] per unit length carries a load of mass \$M\$ at the lower end, its upper end clamped at a rigid support. The tensile stress a distance \[x\] from support is (\$A\$- area of cross-section of the bar)A) \$\dfrac{{Mg + mg(l - x)}}{A}\$B) \$\dfrac{{Mg}}{A}\$C) \$\dfrac{{Mg + mgl}}{A}\$D) \$\dfrac{{(M + m)gx}}{{Al}}\$

Last updated date: 17th Sep 2024
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Hint: To answer this question we will calculate the mass of the hanging bar and its sum with the load mass at any arbitrary point on the rod. Only the mass of the rod and the load below an arbitrary point will contribute to the tensile stress at that point.

Formula used: In this solution, we will use the following formula:
Tensile stress: \$S = \dfrac{F}{A}\$ where \$F\$ is the force acting on a point on the rod and \$A\$ is the cross-sectional area of the rod