
A tuning fork of frequency produces beats per second when sounded with another tuning fork of unknown frequency. If is located with wax the number of beats is again per second. The frequency of the tuning fork before it was loaded is
(A)
(B)
(C)
(D)
Answer
140.1k+ views
HintThe frequency of is equal to the sum of the frequency of the and the number of beats produced from the frequency of . And then the condition is given, the is located in the wax and again per second. By sing this condition, the frequency of is determined.
Complete step by step solution
Given that,
The tuning fork of frequency is, ,
The tuning fork of produces the beats of, .
Then the tuning fork is placed in the wax and again beats per second.
Now, the frequency of is given by,
Where, is the frequency of the tuning fork .
By substituting the frequency of and the number of beats produced by the frequency of in the equation (1), then
By adding and subtracting the terms in the above equation, then the above equation is written as,
or
On loading the tuning fork , the frequency decreases from to , so that the number of beats per second remains .
Thus, the frequency of the tuning fork before it was loaded is .
Hence, the option (C) is the correct answer.
Note A tuning fork of frequency produces beats per second when sounded with another tuning fork of unknown frequency. If is located with wax the number of beats is again per second. The frequency of the tuning fork before it was loaded is .
Complete step by step solution
Given that,
The tuning fork
The tuning fork of
Then the tuning fork
Now, the frequency of
Where,
By substituting the frequency of
By adding and subtracting the terms in the above equation, then the above equation is written as,
On loading the tuning fork
Thus, the frequency of the tuning fork
Hence, the option (C) is the correct answer.
Note A tuning fork
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