A standing wave is formed by the superposition of two waves travelling in opposite directions. The transverse displacement is given by
$y\left( {x,t} \right) = 0.5\sin \left( {\dfrac{{5\pi }}{4}x} \right)\cos \left( {200\pi t} \right)$
What is the speed of the travelling wave moving in the positive $x$ direction?
($x$ and $t$ are in meter and second, respectively)
(A) $120m/s$
(B) $180m/s$
(C) $90m/s$
(D) $160m/s$
Answer
289.5k+ views
Hint: First compare the equation given in the question with the general standing wave equation generated due to superposition of two waves travelling in opposite directions. We can get the value of angular frequency and propagation constant from here. Then using these two values, calculate the velocity of the wave.
Formulas used:
$v = \dfrac{\omega }{k}$ where $v$ is the velocity of the wave, $w$is its angular frequency and $k$ is its propagation constant.
Complete step by step answer
Standing or stationary waves can be generated in two ways:
1. By moving the medium in a direction opposite to the wave.
2. By the superposition of two waves with equal frequency travelling in opposite directions.
In this question, the standing wave is generated due to the superposition of two waves.
Let us consider two waves travelling in positive $x$ direction and negative $x$ direction represented by the equations
${y_1} = a\sin \left( {kx - \omega t} \right)$ and ${y_2} = a\sin \left( {kx + \omega t} \right)$
Where $a$ is the amplitude of the waves, $k$is the propagation constant and $w$ is the angular velocity.
By the principle of superposition the resultant standing wave is given by,
$y = {y_1} + {y_2}$
$
\Rightarrow y = a\left[ {\sin \left( {kx - \omega t} \right) + \sin \left( {kx + \omega t} \right)} \right] \\
\Rightarrow y = a\left[ {\sin kx\cos \omega t - \cos kx\sin \omega t + \sin kx\cos \omega t + \cos kx\sin \omega t} \right] \\
\Rightarrow y = 2a\sin kx\cos \omega t \\
\Rightarrow y = A\sin kx\cos \omega t \\
$
Comparing this equation with the equation given in the question we have,
$k = \dfrac{{5\pi }}{4}$ and $\omega = 200\pi $
Now velocity of a wave is given by the formula, $v = \dfrac{\omega }{k}$
So, $v = \dfrac{{200\pi }}{{\dfrac{{5\pi }}{4}}} = \dfrac{{200\pi \times 4}}{{5\pi }} = 160m/s$
Therefore, the speed of the travelling wave moving in positive $x$ direction is $160m/s$
So, the correct option is D.
Note: An example of standing wave formation is in the open ocean formed by waves with the same wave period moving in opposite directions. These may form near storm centres, or from reflection of a swell at the shore.
Formulas used:
$v = \dfrac{\omega }{k}$ where $v$ is the velocity of the wave, $w$is its angular frequency and $k$ is its propagation constant.
Complete step by step answer
Standing or stationary waves can be generated in two ways:
1. By moving the medium in a direction opposite to the wave.
2. By the superposition of two waves with equal frequency travelling in opposite directions.
In this question, the standing wave is generated due to the superposition of two waves.
Let us consider two waves travelling in positive $x$ direction and negative $x$ direction represented by the equations
${y_1} = a\sin \left( {kx - \omega t} \right)$ and ${y_2} = a\sin \left( {kx + \omega t} \right)$
Where $a$ is the amplitude of the waves, $k$is the propagation constant and $w$ is the angular velocity.
By the principle of superposition the resultant standing wave is given by,
$y = {y_1} + {y_2}$
$
\Rightarrow y = a\left[ {\sin \left( {kx - \omega t} \right) + \sin \left( {kx + \omega t} \right)} \right] \\
\Rightarrow y = a\left[ {\sin kx\cos \omega t - \cos kx\sin \omega t + \sin kx\cos \omega t + \cos kx\sin \omega t} \right] \\
\Rightarrow y = 2a\sin kx\cos \omega t \\
\Rightarrow y = A\sin kx\cos \omega t \\
$
Comparing this equation with the equation given in the question we have,
$k = \dfrac{{5\pi }}{4}$ and $\omega = 200\pi $
Now velocity of a wave is given by the formula, $v = \dfrac{\omega }{k}$
So, $v = \dfrac{{200\pi }}{{\dfrac{{5\pi }}{4}}} = \dfrac{{200\pi \times 4}}{{5\pi }} = 160m/s$
Therefore, the speed of the travelling wave moving in positive $x$ direction is $160m/s$
So, the correct option is D.
Note: An example of standing wave formation is in the open ocean formed by waves with the same wave period moving in opposite directions. These may form near storm centres, or from reflection of a swell at the shore.
Recently Updated Pages
Environmental Chemistry Chapter for JEE Main Chemistry

Chemical Bonding and Molecular Structure Chapter for JEE Main Chemistry

Chelating Ligand, Ambidentate Ligand, and Flexidentate Ligand for JEE Exam

JEE Main 2023 (February 1st Shift 2) Physics Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 1) Maths Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 2) Chemistry Question Paper with Answer Key

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 2 Motion In A Straight Line - 2026-27 Free PDF Download (Login Required)

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2026-27 Free PDF Download (Sign-in Required)

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

CBSE Notes Class 11 Physics Chapter 2 - Motion in a Straight Line - 2026-27 PDF Download (Login Required)

