
A source of light lies on the angle bisector of two plane mirrors inclined at an angle $\theta $. The value of $\theta $, so that the light reflected from one mirror does not reach the other mirror will be:
A. $\theta \geqslant {120^ \circ }$
B. $\theta > {90^ \circ }$
C. $\theta \leqslant {120^ \circ }$
C. None of the above
Answer
147.6k+ views
Hint It is given in the question that the light reflected from one mirror does not reach the other mirror, so we can determine from here that the number of images formed in this system must not be greater than two. Replacing this value in the appropriate formula we get the condition for the angle.
Formula used
$n = \dfrac{{{{360}^ \circ }}}{\theta } - 1$ where $n$ is the number of images formed when two plane mirrors are inclined at an angle $\theta $
Complete step by step answer
When light is incident on a plane mirror, it leads to the following observation:
The incident ray, the normal at the point of incidence and the reflected ray all lie in the same plane.
The angle of reflection is equal to the angle of incidence.
These observations are termed as the ‘laws of reflection’
Now, let us consider two plane mirrors who are inclined such that they make an angle of \[\theta \] with one another.
Since it's given that the light reflected from one mirror does not reach the other, the number of images formed must not be greater than two.
So we have $n \leqslant 2$
Now the formula for the number of images formed is given as
$n = \dfrac{{{{360}^ \circ }}}{\theta } - 1$
So equation these two equations we get,
$\dfrac{{{{360}^ \circ }}}{\theta } - 1 \leqslant 2$ where $\theta $ is the angle between the two inclined mirrors.
$
\Rightarrow \dfrac{{{{360}^ \circ }}}{\theta } \leqslant 3 \\
\Rightarrow \theta \geqslant \dfrac{{{{360}^ \circ }}}{3} \\
\Rightarrow \theta \geqslant {120^ \circ } \\
$
So the condition for which the light reflected from one mirror does not reach the other mirror is $\theta \geqslant {120^ \circ }$
Therefore, the correct answer is A.
Note Apart from plane mirrors, there are also spherical mirrors of two types-convex and concave. A concave mirror is one whose reflecting surface is towards the centre of the sphere of which the mirror is a part of. A convex mirror is one whose reflecting surface is away from the centre of the sphere of which the mirror is a part.
Formula used
$n = \dfrac{{{{360}^ \circ }}}{\theta } - 1$ where $n$ is the number of images formed when two plane mirrors are inclined at an angle $\theta $
Complete step by step answer
When light is incident on a plane mirror, it leads to the following observation:
The incident ray, the normal at the point of incidence and the reflected ray all lie in the same plane.
The angle of reflection is equal to the angle of incidence.
These observations are termed as the ‘laws of reflection’
Now, let us consider two plane mirrors who are inclined such that they make an angle of \[\theta \] with one another.
Since it's given that the light reflected from one mirror does not reach the other, the number of images formed must not be greater than two.
So we have $n \leqslant 2$
Now the formula for the number of images formed is given as
$n = \dfrac{{{{360}^ \circ }}}{\theta } - 1$
So equation these two equations we get,
$\dfrac{{{{360}^ \circ }}}{\theta } - 1 \leqslant 2$ where $\theta $ is the angle between the two inclined mirrors.
$
\Rightarrow \dfrac{{{{360}^ \circ }}}{\theta } \leqslant 3 \\
\Rightarrow \theta \geqslant \dfrac{{{{360}^ \circ }}}{3} \\
\Rightarrow \theta \geqslant {120^ \circ } \\
$
So the condition for which the light reflected from one mirror does not reach the other mirror is $\theta \geqslant {120^ \circ }$
Therefore, the correct answer is A.
Note Apart from plane mirrors, there are also spherical mirrors of two types-convex and concave. A concave mirror is one whose reflecting surface is towards the centre of the sphere of which the mirror is a part of. A convex mirror is one whose reflecting surface is away from the centre of the sphere of which the mirror is a part.
Recently Updated Pages
How to find Oxidation Number - Important Concepts for JEE

How Electromagnetic Waves are Formed - Important Concepts for JEE

Electrical Resistance - Important Concepts and Tips for JEE

Average Atomic Mass - Important Concepts and Tips for JEE

Chemical Equation - Important Concepts and Tips for JEE

Concept of CP and CV of Gas - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

Degree of Dissociation and Its Formula With Solved Example for JEE

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry
