
: A small air bubble of $0.1mm$ diameter is formed just below the surface of water. If surface tension of water is $0.072N{m^{ - 1}}$ , the pressure inside the air bubble in kilo pascal is (Atmospheric pressure $ = 1.01 \times {10^5}Pa$ )
1)28.9
2) 0.289
3) 0.0289
4) 103.88
Answer
232.8k+ views
Hint The excess pressure inside the bubble is Pressure inside the bubble would be the sum of pressure outside and the excess pressure inside the bubble. So by adding both we will get the desired answer.
Complete step by step solution
For the bubble to be stable and not to collapse, the pressure inside the bubble must be greater than the pressure on the outside. The force due to the pressure difference must balance the force from the surface tension. The outward force due to the pressure difference between the inside and the outside air is balanced by the surface tension. We have two surfaces, the inner and the outer surface of the bubble both having different pressure.
Given:
Radius of air bubble $R = \dfrac{{0.1}}{2}mm = 0.05 \times {10^{ - 3}}m$ (As $1mm = {10^{ - 3}}m$)
Surface tension of water $T = 7.2 \times {10^{ - 2}}N{m^{ - 1}}$
The excess pressure inside an air bubble would be :
${P_2} - {P_1} = \dfrac{{2T}}{R}$
Where
${P_1}$ is Atmospheric Pressure (${P_0}$)
And ${P_2}$ is pressure inside the air bubble (${P_i}$)
So
${P_i} = {P_0} + \dfrac{{2T}}{R}$
${P_i} = 1.01 \times {10^5} + \dfrac{{2 \times 0.072}}{{0.05 \times {{10}^{ - 3}}}}$
${P_i} = 1.01 \times {10^5} + \dfrac{{2 \times 72}}{5} \times {10^2}$
${P_i} = 1.01 \times {10^5} + 28.8 \times {10^2}$
${P_i} = 1.01 \times {10^5} + 0.288 \times {10^5}$
${P_i} = 1.0388 \times {10^5}Pa$
As we were asked to give answer in kilopascal So,
${P_i} = 103.88kPa$
Note The soap film has less surface tension as compared to the pure water, which would pull itself into the tiny droplets. Surface tension of the water provides the necessary surface tension for the formation of bubbles with water. And also the Soap bubbles and raindrops are spherical because the sphere is the shape with the smallest surface to volume ratio.
Complete step by step solution
For the bubble to be stable and not to collapse, the pressure inside the bubble must be greater than the pressure on the outside. The force due to the pressure difference must balance the force from the surface tension. The outward force due to the pressure difference between the inside and the outside air is balanced by the surface tension. We have two surfaces, the inner and the outer surface of the bubble both having different pressure.
Given:
Radius of air bubble $R = \dfrac{{0.1}}{2}mm = 0.05 \times {10^{ - 3}}m$ (As $1mm = {10^{ - 3}}m$)
Surface tension of water $T = 7.2 \times {10^{ - 2}}N{m^{ - 1}}$
The excess pressure inside an air bubble would be :
${P_2} - {P_1} = \dfrac{{2T}}{R}$
Where
${P_1}$ is Atmospheric Pressure (${P_0}$)
And ${P_2}$ is pressure inside the air bubble (${P_i}$)
So
${P_i} = {P_0} + \dfrac{{2T}}{R}$
${P_i} = 1.01 \times {10^5} + \dfrac{{2 \times 0.072}}{{0.05 \times {{10}^{ - 3}}}}$
${P_i} = 1.01 \times {10^5} + \dfrac{{2 \times 72}}{5} \times {10^2}$
${P_i} = 1.01 \times {10^5} + 28.8 \times {10^2}$
${P_i} = 1.01 \times {10^5} + 0.288 \times {10^5}$
${P_i} = 1.0388 \times {10^5}Pa$
As we were asked to give answer in kilopascal So,
${P_i} = 103.88kPa$
Note The soap film has less surface tension as compared to the pure water, which would pull itself into the tiny droplets. Surface tension of the water provides the necessary surface tension for the formation of bubbles with water. And also the Soap bubbles and raindrops are spherical because the sphere is the shape with the smallest surface to volume ratio.
Recently Updated Pages
Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Circuit Switching vs Packet Switching: Key Differences Explained

Dimensions of Pressure in Physics: Formula, Derivation & SI Unit

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding Uniform Acceleration in Physics

Understanding How a Current Loop Acts as a Magnetic Dipole

Understanding Average and RMS Value in Electrical Circuits

Understanding Collisions: Types and Examples for Students

Other Pages
JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions For Class 11 Physics Chapter 10 Thermal Properties of Matter (2025-26)

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Understanding Atomic Structure for Beginners

NCERT Solutions For Class 11 Physics Chapter 12 Kinetic Theory (2025-26)

