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A person walks up a stalled escalator in 90 seconds. When standing on the same escalator, now moving, he is carried in 60 second. The time it would take him to walk up the moving escalator will be:
A) 27 s
B) 72 s
C) 18 s
D) 36 s

Answer
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Hint: In this question we have to find the value of time taken by the man to move on a moving escalator. The time taken by the man to walk on a stalled escalator is given and the time for which the escalator was moving is given. We will use the formula of time to solve this question.

Complete step by step solution:
Given,
Let the time taken by the man to walk on stalled escalator is t1, t1=90s
Let the time for which the escalator was moving is t2, t2=60s
Let the total distance travelled is d and the speed of man is vm and the speed of escalator is ve
As we know that the formula of time given by,
time=distancevelocity
The time taken by man t1=dvm
90=dvm
Speed of man is vm=d90
The time taken by escalator t2=dve
60=dve
ve=d60
If total time taken is t then
Total time taken t=dvm+dve
Putting the values of vmand vein above equation
t=dd90+dd60
t=1190+1160
t=60×9060+90
t=5400150
t=36s
Result- Hence, the total time taken by the man to walk up the moving escalator is t=36s.

Hence, option (D) is correct.

Note; In this question we had to find the value of time that the man will take to walk up the escalator. So, it is important to understand that the total time is the one that we have to calculate and we can find it in a very simple way by using the formula of time. The calculation in this question is quite easy but we have to remember that in such types of questions first we will find individual time taken by both man and escalator and then we will find total time taken.