A person walks up a stalled escalator in 90 seconds. When standing on the same escalator, now moving, he is carried in 60 second. The time it would take him to walk up the moving escalator will be:
A) 27 s
B) 72 s
C) 18 s
D) 36 s
Answer
249k+ views
Hint: In this question we have to find the value of time taken by the man to move on a moving escalator. The time taken by the man to walk on a stalled escalator is given and the time for which the escalator was moving is given. We will use the formula of time to solve this question.
Complete step by step solution:
Given,
Let the time taken by the man to walk on stalled escalator is ${t_1}$, ${t_1} = 90s$
Let the time for which the escalator was moving is ${t_2}$, ${t_2} = 60s$
Let the total distance travelled is d and the speed of man is ${v_m}$ and the speed of escalator is ${v_e}$
As we know that the formula of time given by,
$time = \dfrac{{distance}}{{velocity}}$
The time taken by man ${t_1} = \dfrac{d}{{{v_m}}}$
$\Rightarrow 90 = \dfrac{d}{{{v_m}}}$
Speed of man is ${v_m} = \dfrac{d}{{90}}$
The time taken by escalator ${t_2} = \dfrac{d}{{{v_e}}}$
$\Rightarrow 60 = \dfrac{d}{{{v_e}}}$
$\Rightarrow {v_e} = \dfrac{d}{{60}}$
If total time taken is t then
Total time taken \[t = \dfrac{d}{{{v_m}}} + \dfrac{d}{{{v_e}}}\]
Putting the values of ${v_m}$and ${v_e}$in above equation
\[\Rightarrow t = \dfrac{d}{{\dfrac{d}{{90}}}} + \dfrac{d}{{\dfrac{d}{{60}}}}\]
\[\Rightarrow t = \dfrac{1}{{\dfrac{1}{{90}}}} + \dfrac{1}{{\dfrac{1}{{60}}}}\]
\[\Rightarrow t = \dfrac{{60 \times 90}}{{60 + 90}}\]
\[\Rightarrow t = \dfrac{{5400}}{{150}}\]
\[\Rightarrow t = 36s\]
Result- Hence, the total time taken by the man to walk up the moving escalator is \[t = 36s\].
Hence, option (D) is correct.
Note; In this question we had to find the value of time that the man will take to walk up the escalator. So, it is important to understand that the total time is the one that we have to calculate and we can find it in a very simple way by using the formula of time. The calculation in this question is quite easy but we have to remember that in such types of questions first we will find individual time taken by both man and escalator and then we will find total time taken.
Complete step by step solution:
Given,
Let the time taken by the man to walk on stalled escalator is ${t_1}$, ${t_1} = 90s$
Let the time for which the escalator was moving is ${t_2}$, ${t_2} = 60s$
Let the total distance travelled is d and the speed of man is ${v_m}$ and the speed of escalator is ${v_e}$
As we know that the formula of time given by,
$time = \dfrac{{distance}}{{velocity}}$
The time taken by man ${t_1} = \dfrac{d}{{{v_m}}}$
$\Rightarrow 90 = \dfrac{d}{{{v_m}}}$
Speed of man is ${v_m} = \dfrac{d}{{90}}$
The time taken by escalator ${t_2} = \dfrac{d}{{{v_e}}}$
$\Rightarrow 60 = \dfrac{d}{{{v_e}}}$
$\Rightarrow {v_e} = \dfrac{d}{{60}}$
If total time taken is t then
Total time taken \[t = \dfrac{d}{{{v_m}}} + \dfrac{d}{{{v_e}}}\]
Putting the values of ${v_m}$and ${v_e}$in above equation
\[\Rightarrow t = \dfrac{d}{{\dfrac{d}{{90}}}} + \dfrac{d}{{\dfrac{d}{{60}}}}\]
\[\Rightarrow t = \dfrac{1}{{\dfrac{1}{{90}}}} + \dfrac{1}{{\dfrac{1}{{60}}}}\]
\[\Rightarrow t = \dfrac{{60 \times 90}}{{60 + 90}}\]
\[\Rightarrow t = \dfrac{{5400}}{{150}}\]
\[\Rightarrow t = 36s\]
Result- Hence, the total time taken by the man to walk up the moving escalator is \[t = 36s\].
Hence, option (D) is correct.
Note; In this question we had to find the value of time that the man will take to walk up the escalator. So, it is important to understand that the total time is the one that we have to calculate and we can find it in a very simple way by using the formula of time. The calculation in this question is quite easy but we have to remember that in such types of questions first we will find individual time taken by both man and escalator and then we will find total time taken.
Recently Updated Pages
JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Instantaneous Velocity Explained: Formula, Examples & Graphs

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Hybridisation in Chemistry – Concept, Types & Applications

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2025-26

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2025-26

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2025-26

CBSE Notes Class 11 Physics Chapter 4 - Laws of Motion - 2025-26

