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A parallel plate condenser of capacity 100pF is connected to 230V of AC supply of 300rads1 frequency. The rms value of displacement current.
(A) 6.9μA
(B) 2.3μA
(C) 9.2μA
(D) 4.6μA

Answer
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Hint The rms value of the current is determined by using the rms formula of the current and the rms value of the current is equal to the rms of the voltage divided by the inductive capacitance of the capacitor. Then the inductive capacitance is written as the product of the frequency and the capacitance.
Useful formula
The rms value of the current is given as,
Irms=ErmsXC
Where, Irms is the rms value of the current, Erms is the rms value of the voltage and XC is the inductive capacitance.

Complete step by step answer
Given that,
The capacitance of the parallel plate is given as, C=100pF=100×1012F,
The rms value of the voltage is given as, Erms=230V,
The angular frequency is given as, ω=300rads1.
Now,
The rms value of the current is given as,
Irms=ErmsXC....................(1)
Now, the inductive capacitance is written as XC=1ωC. By substituting this equation in the above equation, then the above equation is written as,
Irms=Erms(1ωC)
By rearranging the terms in the above equation, then the above equation is written as,
Irms=Erms×ωC
By substituting the rms value of the voltage, angular frequency and the capacitance of the parallel plate in the above equation, then the above equation is written as,
Irms=230×300×100×1012
By multiplying the terms in the above equation, then the above equation is written as,
Irms=6.9×106A
Then the above equation is also be written as,
Irms=6.9μA
Thus, the above equation shows the rms value of displacement current.

Hence, the option (A) is the correct answer.

Note The rms value of displacement current is directly proportional to the rms value of the voltage and inversely proportional to the inductive capacitance. As the rms value of the voltage increases, then the rms value of displacement current also increases.
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