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# When a differential amplifier is operated single-ended,(A) The output is grounded(B) One input is grounded and the signal is applied to the other(C) Both inputs are connected together(D) The output is not inverted

Last updated date: 17th Jul 2024
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Hint: All the voltages are measured with respect to the ground voltage. The ground voltage is considered to be \$0V\$. As the name suggested, a single-ended differential amplifier amplifies the signal that is given through only one of the input.

Complete Step by step solution:
The inputs of a single ended differential amplifier are the ground on one end and signal on the other end.
Conventionally, we take the ground voltage \$0V\$ for each and every circuit. All the other voltages are measured with respect to ground voltage.
For example, the voltage in our houses is \$220V\$. This voltage is measured with respect to the ground only.

Thus, option (B) is the correct option.

Additional information: If we give two signals of different amplitudes to a differential amplifier, the difference of the amplitude will be amplified. For example, if one signal is \$10V\$and the other signal is \$15V\$ then \$(15 - 10)V = 5V\$will be amplified by the differential amplifier. In the case of a single ended differential amplifier, we have ground on one end and a signal \$(8V)\$ on the other end. We can say that on one end we have \$0V\$ and on the other end we have \$8V\$. Thus, \$(8 - 0)V = 8V\$ will be amplified. Thus we can treat a single-ended differential amplifier as any other differential amplifier with \$0V\$ as an input. So that the signal through the second input line gets amplified.

Note: If the output of such a differential amplifier is asked, the output can be easily calculated by treating a single ended differential amplifier like any other differential amplifier. The output will be the same in this case.