
When a differential amplifier is operated single-ended,
(A) The output is grounded
(B) One input is grounded and the signal is applied to the other
(C) Both inputs are connected together
(D) The output is not inverted
Answer
444k+ views
Hint: All the voltages are measured with respect to the ground voltage. The ground voltage is considered to be $0V$. As the name suggested, a single-ended differential amplifier amplifies the signal that is given through only one of the input.
Complete Step by step solution:
The inputs of a single ended differential amplifier are the ground on one end and signal on the other end.
Conventionally, we take the ground voltage $0V$ for each and every circuit. All the other voltages are measured with respect to ground voltage.
For example, the voltage in our houses is $220V$. This voltage is measured with respect to the ground only.
Thus, option (B) is the correct option.
Additional information: If we give two signals of different amplitudes to a differential amplifier, the difference of the amplitude will be amplified. For example, if one signal is $10V$and the other signal is $15V$ then $(15 - 10)V = 5V$will be amplified by the differential amplifier. In the case of a single ended differential amplifier, we have ground on one end and a signal $(8V)$ on the other end. We can say that on one end we have $0V$ and on the other end we have $8V$. Thus, $(8 - 0)V = 8V$ will be amplified. Thus we can treat a single-ended differential amplifier as any other differential amplifier with $0V$ as an input. So that the signal through the second input line gets amplified.
Note: If the output of such a differential amplifier is asked, the output can be easily calculated by treating a single ended differential amplifier like any other differential amplifier. The output will be the same in this case.
Complete Step by step solution:
The inputs of a single ended differential amplifier are the ground on one end and signal on the other end.
Conventionally, we take the ground voltage $0V$ for each and every circuit. All the other voltages are measured with respect to ground voltage.
For example, the voltage in our houses is $220V$. This voltage is measured with respect to the ground only.
Thus, option (B) is the correct option.
Additional information: If we give two signals of different amplitudes to a differential amplifier, the difference of the amplitude will be amplified. For example, if one signal is $10V$and the other signal is $15V$ then $(15 - 10)V = 5V$will be amplified by the differential amplifier. In the case of a single ended differential amplifier, we have ground on one end and a signal $(8V)$ on the other end. We can say that on one end we have $0V$ and on the other end we have $8V$. Thus, $(8 - 0)V = 8V$ will be amplified. Thus we can treat a single-ended differential amplifier as any other differential amplifier with $0V$ as an input. So that the signal through the second input line gets amplified.
Note: If the output of such a differential amplifier is asked, the output can be easily calculated by treating a single ended differential amplifier like any other differential amplifier. The output will be the same in this case.
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