
A $100V$ carrier wave is made to vary between $160V$ and $40V$ by a modulation signal. What is the modulation index?
Answer
214.2k+ views
Hint: In order to solve this question you have to remember the definition of modulation index and the formula for finding the modulation index. Recall all the concepts related to the modulation, types of modulation, characteristics of the modulation.
Formula used:
$\mu = \dfrac{{{A_m}}}{{{A_c}}}$
Where, ${A_m}$ is the amplitude of the modulation signal
${A_c}$ is the amplitude of the carrier signal
And, $\mu $ is the modulation index
Complete step by step solution:
Here, in the question, we have given the amplitude of the carrier signal,
${A_c} = 100V$
Also given the maximum and minimum amplitude of the modulated wave,
${A_{\max }} = 160V$ and ${A_{\min }} = 40V$
We also know that,
$ \Rightarrow {A_{\max }} = {A_c} + {A_m}$
$ \Rightarrow {A_{\min }} = {A_c} - {A_m}$
Where ${A_m}$ is the amplitude of the modulation signal
${A_c}$ is the amplitude of the carrier signal.
On putting the value of ${A_{\max }}$ in the above equation for the maximum amplitude of the modulated wave, we get,
$ \Rightarrow 160V = {A_c} + {A_m}$
On putting the value of ${A_c}$ in the above equation,
$ \Rightarrow 160V = 100 + {A_m}$
On further solving, we get the value of the amplitude of the modulation signal,
${A_m} = 60V$
Now we have the formula for calculating the modulation index, given by,
modulation index, $\mu = \dfrac{{{A_m}}}{{{A_c}}}$
Where ${A_m}$ is the amplitude of the modulation signal
${A_c}$ is the amplitude of the carrier signal
On putting the values of ${A_m}$ and the ${A_c}$ in the above formula, we get
$\mu = \dfrac{{60V}}{{100V}}$
On further solving we get the value of the modulation index,
$\mu = 0.6$
Thus the value of the modulation index is $0.6$.
Additional Information: There is one more formula for finding the modulation index using the maximum and minimum amplitude of the modulated wave. The formula is given by, $\mu = \dfrac{{{A_{\max }} - {A_{\min }}}}{{{A_{\max }} + {A_{\min }}}}$.
Note: The modulation index is also known as modulation depth. If the modulating index is multiplied by 100 then it is converted into the percentage of modulation. If the value of the modulating index is 1, then it is the example of a perfect modulating, and its percentage of modulation is 100%.
Formula used:
$\mu = \dfrac{{{A_m}}}{{{A_c}}}$
Where, ${A_m}$ is the amplitude of the modulation signal
${A_c}$ is the amplitude of the carrier signal
And, $\mu $ is the modulation index
Complete step by step solution:
Here, in the question, we have given the amplitude of the carrier signal,
${A_c} = 100V$
Also given the maximum and minimum amplitude of the modulated wave,
${A_{\max }} = 160V$ and ${A_{\min }} = 40V$
We also know that,
$ \Rightarrow {A_{\max }} = {A_c} + {A_m}$
$ \Rightarrow {A_{\min }} = {A_c} - {A_m}$
Where ${A_m}$ is the amplitude of the modulation signal
${A_c}$ is the amplitude of the carrier signal.
On putting the value of ${A_{\max }}$ in the above equation for the maximum amplitude of the modulated wave, we get,
$ \Rightarrow 160V = {A_c} + {A_m}$
On putting the value of ${A_c}$ in the above equation,
$ \Rightarrow 160V = 100 + {A_m}$
On further solving, we get the value of the amplitude of the modulation signal,
${A_m} = 60V$
Now we have the formula for calculating the modulation index, given by,
modulation index, $\mu = \dfrac{{{A_m}}}{{{A_c}}}$
Where ${A_m}$ is the amplitude of the modulation signal
${A_c}$ is the amplitude of the carrier signal
On putting the values of ${A_m}$ and the ${A_c}$ in the above formula, we get
$\mu = \dfrac{{60V}}{{100V}}$
On further solving we get the value of the modulation index,
$\mu = 0.6$
Thus the value of the modulation index is $0.6$.
Additional Information: There is one more formula for finding the modulation index using the maximum and minimum amplitude of the modulated wave. The formula is given by, $\mu = \dfrac{{{A_{\max }} - {A_{\min }}}}{{{A_{\max }} + {A_{\min }}}}$.
Note: The modulation index is also known as modulation depth. If the modulating index is multiplied by 100 then it is converted into the percentage of modulation. If the value of the modulating index is 1, then it is the example of a perfect modulating, and its percentage of modulation is 100%.
Recently Updated Pages
Chemical Equation - Important Concepts and Tips for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

Conduction, Transfer of Energy Important Concepts and Tips for JEE

JEE Analytical Method of Vector Addition Important Concepts and Tips

Atomic Size - Important Concepts and Tips for JEE

JEE Main 2022 (June 29th Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

JEE Main Correction Window 2026 Session 1 Dates Announced - Edit Form Details, Dates and Link

Equation of Trajectory in Projectile Motion: Derivation & Proof

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Hybridisation in Chemistry – Concept, Types & Applications

Angle of Deviation in a Prism – Formula, Diagram & Applications

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

CBSE Class 10 Sanskrit Set 4 52 Question Paper 2025 – PDF, Solutions & Analysis

Collision: Meaning, Types & Examples in Physics

Atomic Structure: Definition, Models, and Examples

Degree of Dissociation: Meaning, Formula, Calculation & Uses

How to Convert a Galvanometer into an Ammeter or Voltmeter

