Question

0.52 g of dibasic acid required 100 mL of 0.1 NaOH for complete neutralization. The equivalent mass of acid is:
(A) 26
(B) 52
(C) 104
(D) 156

Answer 1

Hint: When a strong acid and a strong base react, it gives salt and water. This process is known as neutralization. Equivalent mass of a substance is the amount of substance that will react with one mole of proton or electron to neutralize the reaction.

Complete step by step answer:
> Let us understand the concept of neutralization first. Neutralization is defined as “a type of chemical reaction in which a strong acid and strong base react with each other to form water and salt”.
- According to the question, we need to find the equivalent mass of dibasic acid that neutralizes 100 mL of base. Let equivalent mass be ‘E’.
Given, weight of dibasic acid = 0.52 g
Normality of base = 0.1 N
Volume of base = 100 mL
- Milliequivalent can be calculated by the following formulas –
- Milliequivalent = (weight x equivalent weight) / 100.
- Milliequivalent = Normality x Volume (in mL)
As we know –
Number of gram equivalent of acid = Number of gram equivalent of base
Or, Milliequivalent of Acid = Milliequivalent of Base
Therefore,
\[\dfrac{\text{0}\text{.52}}{\text{E}}\text{ x 1000 = 100 x 0}\text{.1}\]
E = \[\dfrac{\text{0}\text{.52 x 1000}}{\text{100 x 0}\text{.1}}\]
E = 52
Therefore, the answer is – option (b) – The equivalent mass of acid is 52.

Additional Information: Equivalent mass of a compound is equal to its atomic or molecular mass divided by its n-factor.

Note: Milliequivalent mass is equivalent mass divided by 1000. Milliequivalent can also be calculated using the following formulas –
Milliequivalent = (Number of equivalents) x 1000
Milliequivalent = (Number of moles) x (n-factor) x 1000