
All the words that can be formed using alphabets A, H, L, U, R are written as in a dictionary and no alphabet is repeated. What will be the rank of word RAHUL?
A \[71\]
B \[72\]
C \[73\]
D \[74\]
Answer
216.3k+ views
Hint: Permutation is the arrangement of items in some particular sequence. In this question there are five alphabets and need to form words without repeating the alphabets. In the dictionary words are always in alphabetical order. First find all the words that start with each given alphabet. Then check the word that starts with the alphabet R. Then find the rank of the word RAHUL.
Formula Used: \[n! = 1 \times 2 \times 3 \times ... \times n\]
Here, n is natural number.
Complete step by step solution: There are five alphabets A, H, L, U and R. The alphabetical order of the given alphabets is A, H, L, R and U.
Now, calculate number of words starting with alphabet A.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Calculate number of words starting with alphabet H.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Now, calculate number of words starting with alphabet L.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Hence, calculate total numbers words before words starting with R.
Total numbers words before words starting with R \[24 + 24 + 24 = 72\]
The first words starting with R is RAHLU and the second word is RAHUL. Hence, the word RAHLU is at rank 73 and the word RAHUL is at 74.
So, the word RAHUL has Rank 74.
Option ‘D’ is correct
Note: The common mistake happen here by students are taking permutation of all alphabets which is wrong.
Formula Used: \[n! = 1 \times 2 \times 3 \times ... \times n\]
Here, n is natural number.
Complete step by step solution: There are five alphabets A, H, L, U and R. The alphabetical order of the given alphabets is A, H, L, R and U.
Now, calculate number of words starting with alphabet A.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Calculate number of words starting with alphabet H.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Now, calculate number of words starting with alphabet L.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Hence, calculate total numbers words before words starting with R.
Total numbers words before words starting with R \[24 + 24 + 24 = 72\]
The first words starting with R is RAHLU and the second word is RAHUL. Hence, the word RAHLU is at rank 73 and the word RAHUL is at 74.
So, the word RAHUL has Rank 74.
Option ‘D’ is correct
Note: The common mistake happen here by students are taking permutation of all alphabets which is wrong.
Recently Updated Pages
SRMJEEE Result 2024 (Out) Check all the Updates Here

UPESEAT Exam Date 2023

GUJCET Exam Date 2023

TS EAMCET Application form 2023 & Exam Dates

MHT CET Cutoff 2023|Check Previous Year Cut off, Cutoff Trend

TS EAMCET Seat Allotment

Trending doubts
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Difference Between Exothermic and Endothermic Reactions Explained

Top IIT Colleges in India 2025

IIT Fees Structure 2025

IIT CSE Cutoff: Category‐Wise Opening and Closing Ranks

Understanding the Mechanisms and Key Differences in SN1 and SN2 Reactions

Other Pages
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

NCERT Solutions for Class 11 Maths Chapter 10 Conic Sections

NCERT Solutions for Class 11 Maths Chapter 9 Straight Lines

Hybridisation in Chemistry – Concept, Types & Applications

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series

