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Understanding the Relationship Between Molarity and Normality

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How to Calculate Normality from Molarity with Examples

The relation between molarity and normality is a crucial concept in chemistry, especially when preparing or analyzing solutions. Molarity (M) and normality (N) are both measures of solution concentration, but they differ in how they account for the reacting particles. This article explains the connection between these units, using the appropriate formula and highlighting the importance of the n factor in their relationship according to class 11 and class 12 chemistry topics.


Understanding Molarity and Normality

Molarity and normality are essential for expressing the concentration of chemical solutions. Each term serves a different purpose in stoichiometric calculations and titrations.


Definition of Molarity (M)

  • Molarity is the number of moles of solute dissolved per litre of solution.
  • Mathematically expressed as: \( M = \frac{\text{Number of moles of solute}}{\text{Volume of solution in litres}} \).
  • Commonly used when dealing with reactions in which substances react in simple mole ratios.

Definition of Normality (N)

  • Normality is the number of gram equivalents of solute per litre of solution.
  • Given by: \( N = \frac{\text{Number of equivalents}}{\text{Volume of solution in litres}} \).
  • Widely used in titration calculations and reactions involving acid-base or redox processes.

Relation Between Molarity and Normality: Formula and n Factor

The relation between molarity and normality formula is based on the n factor, which represents the number of reactive units per mole of solute. The n factor varies depending on the type of reaction:


  • Acids: n factor is the number of replaceable hydrogen ions (\( H^+ \)) per molecule.
  • Bases: n factor is the number of hydroxide ions (\( OH^- \)) provided per molecule.
  • Redox Reactions: n factor is the total electrons exchanged per mole.

The direct relationship is expressed as:

$$ N = M \times n\ \text{factor} $$

  • Where \( N \) = normality, \( M \) = molarity, and n factor is specific to the solute and the reaction.
  • This relation helps convert between normality and molarity for various solutions.

Stepwise Derivation of the Relation

  • Start with the basic definitions:
    • Normality: \( N = \frac{\text{Number of equivalents}}{\text{Volume of solution in litres}} \)
    • Molarity: \( M = \frac{\text{Number of moles}}{\text{Volume of solution in litres}} \)
  • One equivalent = n factor × number of moles.
  • So: \( \text{Number of equivalents} = \text{Number of moles} \times n\ \text{factor} \)
  • Therefore, \( N = \frac{M \times \text{Volume} \times n\ \text{factor}}{\text{Volume}} = M \times n\ \text{factor} \)

Application and Importance

  • This relationship is fundamental in titration, buffer calculations, and volumetric analysis.
  • It highlights the importance of the n factor in determining the relationship between molarity, normality, and the nature of the reaction.
  • Understanding the relationship between molarity and normality ensures accurate solution preparation in lab settings.

For more on how concentration terms relate to other properties in chemistry, see our guide on how density and volume are connected, or explore comparison topics such as speed versus velocity. If you’re looking into other key chemistry relations, the link between pressure and velocity may also be useful.


In summary, the relation between molarity and normality in chemistry is clearly defined: normality equals molarity multiplied by the n factor. This direct formula simplifies calculations across acid-base and redox reactions. Mastering the relation between molarity and normality and understanding the significance of the n factor is essential for both class 11 and class 12 chemistry students. Remember, the context of your chemical reaction determines the n factor, which connects the concepts of molarity, normality, and sometimes even molality and solution volume, ensuring precise chemical analysis and solution preparation.


FAQs on Understanding the Relationship Between Molarity and Normality

1. What is the relation between molarity and normality?

The relation between molarity and normality depends on the number of equivalents per mole of solute.
Specifically:

  • Normality (N) = Molarity (M) × n
  • Where n is the number of equivalents (such as H+ ions in acids, OH- ions in bases, or electrons transferred in redox reactions)
  • This helps convert between molarity and normality for acids, bases, and salts
This relation is vital for exam preparation, titration calculations, and CBSE Class 11 and 12 chemistry syllabus.

2. How do you convert molarity to normality?

To convert molarity to normality, multiply the molarity by the number of equivalents per mole.

  • Use this formula: Normality (N) = Molarity (M) × n
  • Find the value of n based on the reaction (e.g. number of replaceable H+ for acids, OH- for bases)
  • This method is important in titrations and stoichiometry problems
This conversion ensures accuracy in chemistry lab work and board exams.

3. What is molarity?

Molarity (M) is the number of moles of solute per litre of solution.

  • Given by: M = (Number of moles of solute) / (Volume of solution in litres)
  • It measures the concentration of a chemical solution
  • Commonly used in chemical calculations and CBSE exams
Molarity is a key concept in Class 11 Chemistry syllabus.

4. What is normality?

Normality (N) is the number of gram equivalents of solute per litre of solution.

  • Formula: N = (Number of gram equivalents of solute) / (Volume of solution in litres)
  • It depends on the type of reaction – acid-base, redox, or precipitation
  • Normality is often used for titration calculations
This concept is widely asked in competitive and board exams.

5. What are the key differences between molarity and normality?

The main differences between molarity and normality are:

  • Molarity is based on moles of solute per litre; normality is based on equivalents per litre
  • Molarity is constant for a given solution, normality may vary depending on the reaction
  • Normality considers the valency factor (n) or number of reacting units
  • Normality is mainly used in titrations, while molarity is used for general concentration measurement
Knowing these differences is essential for Class 11 and 12 chemistry students.

6. How do you calculate normality if molarity is given?

To calculate normality from molarity:

  • Use the formula: Normality (N) = Molarity (M) × n
  • Where n is the number of equivalents per mole, depending on the reaction:
    • For H2SO4, n = 2 (because it provides 2 H+ in acid-base reactions)
    • For NaOH, n = 1
This conversion streamlines calculations for CBSE board exam questions and titration analysis.

7. Why is normality preferred in titration calculations?

Normality is preferred in titration calculations because it accounts for the number of equivalents reacting.

  • Simplifies stoichiometric equations in acid-base and redox titrations
  • Directly relates to the volume and concentration used in neutralization reactions
  • Makes calculations easier where more than one hydrogen or hydroxyl group is involved
This is a common requirement in the Class 11 and 12 Chemistry practicals syllabus.

8. Give an example relating molarity and normality for H2SO4.

For sulphuric acid (H2SO4), the normality is twice its molarity in acid-base reactions.

  • It gives 2 H+ ions per molecule, so n = 2
  • If molarity = 1 M, then normality = 2 N
  • Uses: Useful for quick conversions in CBSE exam numerical problems
This example is important for practical laboratory titrations.

9. Can a solution have the same value for molarity and normality?

Yes, molarity and normality are equal when the number of equivalents per mole is 1.

  • This occurs in compounds like NaCl (neutral salt) and HCl (monoprotic acid)
  • For such substances, M = N
  • Helps avoid confusion in quick board exam questions
Knowing these substances is helpful for competitive chemistry exams too.

10. What is the formula for normality in terms of molarity?

The formula for normality in terms of molarity is:
N = M × n

  • Where N = normality, M = molarity, and n = number of equivalents per mole
  • This formula applies to all types of reactions: acid-base, redox, and precipitation
  • Relevant for quick formula-based questions in CBSE exams

11. What are equivalents in chemistry?

Equivalents in chemistry refer to the amount of a substance that reacts with or supplies one mole of hydrogen ions (for acids), one mole of electrons (for redox reactions), or one mole of hydroxide ions (for bases).

  • The concept of equivalents helps compute normality
  • Important for acid-base, redox, precipitation, and neutralization reactions
This is a recurring term in the Class 11 and 12 NCERT Chemistry syllabus.

12. How does temperature affect molarity and normality?

Both molarity and normality are affected by temperature since volume expands or contracts with temperature change.

  • Increase in temperature increases volume, decreasing molarity and normality
  • Always use solutions at a specified temperature for accurate results in labs and exams
Remember this in practicals and competitive exams questions.