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Relation Between Molarity And Normality in Chemistry

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What Is the Formula for Relation Between Molarity And Normality with Examples

The relation between molarity and normality is a crucial concept in chemistry, especially when preparing or analyzing solutions. Molarity (M) and normality (N) are both measures of solution concentration, but they differ in how they account for the reacting particles. This article explains the connection between these units, using the appropriate formula and highlighting the importance of the n factor in their relationship according to class 11 and class 12 chemistry topics.


Understanding Molarity and Normality

Molarity and normality are essential for expressing the concentration of chemical solutions. Each term serves a different purpose in stoichiometric calculations and titrations.


Definition of Molarity (M)

  • Molarity is the number of moles of solute dissolved per litre of solution.
  • Mathematically expressed as: \( M = \frac{\text{Number of moles of solute}}{\text{Volume of solution in litres}} \).
  • Commonly used when dealing with reactions in which substances react in simple mole ratios.

Definition of Normality (N)

  • Normality is the number of gram equivalents of solute per litre of solution.
  • Given by: \( N = \frac{\text{Number of equivalents}}{\text{Volume of solution in litres}} \).
  • Widely used in titration calculations and reactions involving acid-base or redox processes.

Relation Between Molarity and Normality: Formula and n Factor

The relation between molarity and normality formula is based on the n factor, which represents the number of reactive units per mole of solute. The n factor varies depending on the type of reaction:


  • Acids: n factor is the number of replaceable hydrogen ions (\( H^+ \)) per molecule.
  • Bases: n factor is the number of hydroxide ions (\( OH^- \)) provided per molecule.
  • Redox Reactions: n factor is the total electrons exchanged per mole.

The direct relationship is expressed as:

$$ N = M \times n\ \text{factor} $$

  • Where \( N \) = normality, \( M \) = molarity, and n factor is specific to the solute and the reaction.
  • This relation helps convert between normality and molarity for various solutions.

Stepwise Derivation of the Relation

  • Start with the basic definitions:
    • Normality: \( N = \frac{\text{Number of equivalents}}{\text{Volume of solution in litres}} \)
    • Molarity: \( M = \frac{\text{Number of moles}}{\text{Volume of solution in litres}} \)
  • One equivalent = n factor × number of moles.
  • So: \( \text{Number of equivalents} = \text{Number of moles} \times n\ \text{factor} \)
  • Therefore, \( N = \frac{M \times \text{Volume} \times n\ \text{factor}}{\text{Volume}} = M \times n\ \text{factor} \)

Application and Importance

  • This relationship is fundamental in titration, buffer calculations, and volumetric analysis.
  • It highlights the importance of the n factor in determining the relationship between molarity, normality, and the nature of the reaction.
  • Understanding the relationship between molarity and normality ensures accurate solution preparation in lab settings.

For more on how concentration terms relate to other properties in chemistry, see our guide on how density and volume are connected, or explore comparison topics such as speed versus velocity. If you’re looking into other key chemistry relations, the link between pressure and velocity may also be useful.


In summary, the relation between molarity and normality in chemistry is clearly defined: normality equals molarity multiplied by the n factor. This direct formula simplifies calculations across acid-base and redox reactions. Mastering the relation between molarity and normality and understanding the significance of the n factor is essential for both class 11 and class 12 chemistry students. Remember, the context of your chemical reaction determines the n factor, which connects the concepts of molarity, normality, and sometimes even molality and solution volume, ensuring precise chemical analysis and solution preparation.


FAQs on Relation Between Molarity And Normality in Chemistry

1. What is the relation between molarity and normality?

The relation between molarity (M) and normality (N) is given by the formula N = M × n-factor, where n-factor is the number of equivalents per mole of solute.

  • Molarity (M) = moles of solute per liter of solution.
  • Normality (N) = gram equivalents of solute per liter of solution.
  • The n-factor depends on the type of reaction (acid–base, redox, precipitation).
Thus, normality adjusts molarity based on the reactive capacity of the solute.

2. What is the formula to convert molarity to normality?

The formula to convert molarity to normality is N = M × n-factor.

  • Identify the reaction type (acid–base or redox).
  • Determine the n-factor (number of H+, OH-, or electrons exchanged).
  • Multiply molarity (M) by n-factor.
For example, in H2SO4, n-factor = 2 (two replaceable H+), so 1 M H2SO4 = 2 N.

3. How do you calculate molarity from normality?

Molarity is calculated from normality using the formula M = N / n-factor.

  • Determine the n-factor of the solute in the given reaction.
  • Divide the given normality (N) by the n-factor.
For example, if a solution of HCl is 2 N and n-factor = 1, then M = 2/1 = 2 M.

4. What is the difference between molarity and normality?

The main difference is that molarity measures moles per liter, while normality measures equivalents per liter of solution.

  • Molarity (M) = moles of solute / liter of solution.
  • Normality (N) = gram equivalents of solute / liter of solution.
  • Molarity is independent of reaction type.
  • Normality depends on the n-factor and reaction context.
Thus, normality changes with the reaction, but molarity remains constant for a given solution.

5. What is the n-factor in the relation between molarity and normality?

The n-factor is the number of equivalents of a substance that react or are supplied per mole in a specific reaction.

  • For acids: number of replaceable H+ ions (e.g., HCl = 1, H2SO4 = 2).
  • For bases: number of OH- ions (e.g., NaOH = 1, Ca(OH)2 = 2).
  • For redox reactions: number of electrons lost or gained per mole.
The n-factor directly links molarity and normality through N = M × n-factor.

6. Can you give an example showing the relation between molarity and normality?

Yes, for H2SO4, the relation is N = M × 2 because it donates two H+ ions.

  • Given: 0.5 M H2SO4
  • n-factor = 2
  • N = 0.5 × 2 = 1 N
In the neutralization reaction H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l), two equivalents of base react with one mole of acid.

7. Is normality always equal to molarity?

Normality is equal to molarity only when the n-factor = 1.

  • For monoprotic acids like HCl, n-factor = 1, so N = M.
  • For monobasic bases like NaOH, n-factor = 1, so N = M.
  • For polyprotic acids or polybasic bases, N ≠ M.
Therefore, normality equals molarity only when one equivalent reacts per mole.

8. Why does normality depend on the type of reaction?

Normality depends on the reaction because the n-factor changes with the number of reactive units involved.

  • In acid–base reactions, it depends on H+ or OH- exchanged.
  • In redox reactions, it depends on electrons transferred.
  • The same compound can have different normalities in different reactions.
For example, H3PO4 may have n-factor 1, 2, or 3 depending on how many H+ ions react.

9. How is normality related to equivalents in chemistry?

Normality is defined as the number of gram equivalents per liter of solution.

  • Equivalent weight = molar mass / n-factor.
  • Normality (N) = equivalents of solute / liter of solution.
  • Since equivalents = moles × n-factor, N = M × n-factor.
This shows the direct mathematical connection between molarity, normality, and equivalents.

10. How do you use the relation between molarity and normality in titration calculations?

In titration, the relation is used through the equation N1V1 = N2V2.

  • Convert molarity to normality if needed using N = M × n-factor.
  • Apply N1V1 = N2V2.
  • Solve for the unknown concentration or volume.
For example, in the neutralization HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l), since both have n-factor = 1, molarity and normality are numerically equal.