Lanthanoid Contraction

What is Meant by Lanthanide Contraction?

Lanthanoid contraction definition - In Chemistry, lanthanoid contraction, also called lanthanide contraction, occurs as the atomic size or the ionic radii of the tripositive lanthanide ions steadily decrease from La to Lu because of the electrons entering the inner (n-2) f orbitals and the increasing nuclear charge. This particular gradual decrease in the size with an increasing atomic number is referred to as lanthanide contraction.

This is the simple form of lanthanide contraction definition.


About Lanthanide Contraction

Lanthanide contraction is the steady decrease in the size of the ions and atoms of the rare earth elements with increasing atomic numbers from lanthanum (atomic number 57) to lutetium (with an atomic number 71). For every consecutive atom, the nuclear charge can be more positive by a single unit, accompanied by the corresponding increase in the electron count present in the 4f orbitals surrounding the nucleus.

The 4f electrons imperfectly protect each other from the increased positive charge of the nucleus, resulting in a steady rise in the effective nuclear charge attracting every electron as the lanthanide elements progress, resulting in successive decreases in ionic and atomic radii.


Consequences of Lanthanide Contraction

The following points will depict the effect of lanthanide contraction more clearly:

  • Atomic Size

The size of the atom of the third transition series is approximately similar to that of the atom of the second transition series. For example, the radius of Zr = radius of Hf and the radius of Nb = radius of Ta, and so on.

  • Difficulty in the Separation of Lanthanides

As there is only a small change in the ionic radii of the Lanthanides, their chemical properties are the same. This makes the element's separation in the pure state difficult.

  • Effect on the Basic Strength of Hydroxides

As the size of the lanthanides decreases from the elements La to Lu, the covalent character of the hydroxides increases, and thus their basic strength decreases. Therefore, Lu(OH)3 is said to be least basic, and La (OH)3 is said to be more basic.

  • Complex Formation

Due to the smaller size, whereas, higher nuclear charge, the tendency to produce coordinate. Complexity increases from the element La3+ to Lu3+.

  • Electronegativity

It increases from the elements La to Lu.

  • Ionization Energy

Electron's attraction by the nuclear charge is higher, and thus Ionization energy of the 5d elements is much larger compared to 4d and 3d. In the 5d series, the total elements except Pt and Au contain a filled s-shell.

Elements from Hafnium to rhenium contain similar Ionization energy, and after that, the Ionization energy increases with the number of shared d-electrons such that Gold and Iridium hold the maximum Ionization Energy.

Case Study

Mercury - the Liquid Metal

At room temperature, mercury is the only metal that remains in its liquid form. The nucleus pulls the 6s valence electrons very close together (due to lanthanide contraction), making the outer s-electrons less involved in metallic bonding.

  • Formation of Complex

Lanthanides with a 3+ oxidation state have a higher charge to radius ratio and hence a lower charge to radius ratio. As compared to d-block elements, this decreases the ability of lanthanides to form complexes. Still they form complexes with strong chelating agents like EDTA, β-diketones, oxime, and so on. They do not form Pπ-complexes.


Cause of Lanthanide Contraction

The effect of lanthanide contraction results from the poor shielding of nuclear charge (with the attractive nuclear force on electrons) by 4f electrons; the 6s electrons can be drawn towards the nucleus, hence resulting in the smaller atomic radius.


In the case of single-electron atoms, the average separation of an electron from the nucleus is defined by the subshell it belongs to and decreases with an increased charge on the nucleus, where this, in turn, leads to the decrease in atomic radius. Whereas, in the case of multi-electron atoms, the decrease in the radius brought about by an increase in nuclear charge is partially offset by the increasing electrostatic repulsion among the electrons.


A "shielding effect" operates, in which existing electrons shield the outer electrons from the nuclear charge by causing them to undergo less effective charge on the nucleus as more electrons are applied to the outer shells. The inner electrons' shielding effect decreases in the following order: s > p > d > f.


In general, as a specific subshell is filled in a period, the atomic radius decreases. This particular effect is specifically pronounced in the case of lanthanides, as the 4f subshell that is filled across these elements is not more effective at shielding the outer shell (n=5 and n=6) electrons. Therefore, the shielding effect can be less able to counter the decrease in radius caused by an increasing nuclear charge. This leads to the "lanthanide contraction". And, the ionic radius drops from a range of 103 pm for lanthanum (III) to 86.1 pm for lutetium (III).

The relativistic effects have been blamed for up to 10% of the lanthanide contraction.

FAQs (Frequently Asked Questions)

Q1. Explain the Influence on the Post-Lanthanides?

Answer: The elements following the lanthanides in the periodic table can be influenced by the lanthanide contraction. The period-6 radii transition metals are smaller than that would be expected if there were no lanthanides available, and in fact, are very same as the radii of the period-5 transition metals because the effect of the additional electron shell is entirely offset by the lanthanide contraction.

Q2. What are Lanthanide Contraction Reasons?

Answer: A few reasons that include lanthanoid contraction include Atomic size, Effect on the basic strength of hydroxides, Difficulty in the separation of lanthanides, the ionization energy of d-block elements, and the complex formation.

Q3. What is the d-Block Contraction?

Answer: The d-block contraction, which is also called the Scandide Contraction, determines the atomic radius trend that the d-block elements (or the Transition metals) experience. Generally, the trend for atomic radius moving across the periodic table is, the atomic radius significantly decreases. Whereas, In the transition metals having D-electrons as we move from the left to right across the periodic table, the atomic radius of the element only decreases slightly. This is due to the reason they have a similar amount of s electrons but are only differing in the d-electrons.

Q4. What are the Effects of Lanthanoid Contraction?

Answer: The increased attraction results of the outer shell electrons across the lanthanide period can be divided into the effects on the series of lanthanide itself, including the decrease in the ionic radii and influences on the post-lanthanide elements.