
What is the Mechanism of Electrophilic Addition to Alkenes and Markovnikov Rule
Electrophilic Addition Reactions of Alkenes
As we are about to move in-depth with the addition of alkenes through an electrophilic reaction, it is important to know the 2 other ways this process happens. They are namely ozonolysis and oxidation reactions (particularly with alkenes). Common examples for electrophilic addition reactions with hydrogen halides include hydrogen chloride and hydrogen bromide.
It can happen through the procedure of Free Radical Mechanism as well. Free radical mechanism reactions follow the hierarchy of Chain Initiation, Chain Propagation and Chain Termination in the free radical group of compounds (reaction with stable molecules).
The widely accepted order of hydrogen halide is HI > HBr > HCl. symmetrical alkenes (double bonds have the same ligands) such as ethene are easily predictable in their end products, as compared to non-symmetrical like propene (double bonds have a varied count of ligands) alkenes. This phenomenon is also sometimes referred to as Markownikoff's or Markovnikov rule.
Markovnikov Rule for Electrophilic Addition Reaction
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According to the Markovnikov rule, considering the negative part of an adding molecule, it will get linked to that 1 carbon atom that already has a fewer count of hydrogen atoms.
The Oxidation Reaction of Alkenes
When alkenes get oxidized, it leads to the production of alcohols and ketones. Oxidation reactions are also termed as the Baeyer test.
Let us consider an example with potassium permanganate (KMnO₄). When potassium permanganate, in an aqueous and cool state, is used in the oxidation process of alkenes, this will help in the formation of vicinal glycols.
Oxidation Reaction Of Potassium Permanganate
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Note that an oxidising agent like Potassium Permanganate and the presence of a cold condition is necessary for oxidation reactions to take place.
FAQs on Electrophilic Addition Mechanism in Alkenes
1. What is an electrophilic addition reaction of alkenes?
An electrophilic addition reaction of alkenes is a reaction in which an electrophile adds across the carbon–carbon double bond (C=C) of an alkene to form a saturated product. The π bond in alkenes is electron-rich and attracts an electrophile (electron-deficient species).
- The π bond breaks and forms a new σ bond with the electrophile.
- A carbocation intermediate is usually formed.
- A nucleophile then attacks the carbocation to give the final addition product.
2. Why do alkenes undergo electrophilic addition reactions?
Alkenes undergo electrophilic addition because their C=C double bond contains a high electron density that attracts electrophiles. The π bond is weaker and more reactive than a σ bond.
- The π electrons act as a nucleophile.
- Electrophiles (such as H+ or Br2) are drawn to the electron-rich double bond.
- Breaking the π bond and forming two new σ bonds makes the molecule more stable.
3. What is the mechanism of electrophilic addition in alkenes?
The mechanism of electrophilic addition in alkenes involves formation of a carbocation intermediate followed by nucleophilic attack.
- Step 1: The electrophile attacks the C=C bond, forming a carbocation.
- Step 2: A nucleophile attacks the carbocation to form the final product.
CH2=CH2 + HBr → CH3–CH2Br
This two-step mechanism is typical for hydrogen halide addition to alkenes.
4. What is Markovnikov’s rule in electrophilic addition?
Markovnikov’s rule states that in the addition of HX to an unsymmetrical alkene, the hydrogen atom attaches to the carbon with more hydrogens already attached. This leads to formation of the more stable carbocation intermediate.
- The more substituted carbocation is more stable.
- The halide (X−) attaches to the more substituted carbon.
CH3–CH=CH2 + HBr → CH3–CHBr–CH3
Here, 2-bromopropane is the major product.
5. What happens when alkenes react with hydrogen halides?
When alkenes react with hydrogen halides (HX), they undergo electrophilic addition to form haloalkanes. The reaction follows Markovnikov’s rule for unsymmetrical alkenes.
- General reaction: Alkene + HX → Haloalkane
- Example: CH2=CH2 + HCl → CH3–CH2Cl
- A carbocation intermediate is formed.
6. How does bromine react with alkenes?
Bromine reacts with alkenes by electrophilic addition to form a vicinal dibromide. The reddish-brown color of Br2 disappears during the reaction.
- Example: CH2=CH2 + Br2(l) → CH2Br–CH2Br
- A cyclic bromonium ion intermediate is formed.
- This reaction is used as a test for unsaturation.
7. What is hydration of alkenes?
Hydration of alkenes is the electrophilic addition of water (H2O) across a double bond to form an alcohol, usually in the presence of an acid catalyst. The reaction follows Markovnikov’s rule.
- Acid catalyst: typically H2SO4 or H3PO4
- Example: CH2=CH2 + H2O → CH3–CH2OH
- The product is an alcohol.
8. What are the types of electrophilic addition reactions of alkenes?
The main types of electrophilic addition reactions of alkenes include addition of hydrogen halides, halogens, water, and hydrogen. These reactions all involve breaking the π bond.
- Hydrohalogenation: Alkene + HX
- Halogenation: Alkene + Br2 or Cl2
- Hydration: Alkene + H2O (acid-catalyzed)
- Hydrogenation: Alkene + H2 (with metal catalyst)
9. What is the difference between electrophilic addition and nucleophilic addition?
The key difference is that electrophilic addition involves attack by an electrophile on a double bond, while nucleophilic addition involves attack by a nucleophile on a polar multiple bond.
- Electrophilic addition: common in alkenes (nonpolar C=C).
- Nucleophilic addition: common in carbonyl compounds (C=O).
- Electrophilic addition forms a carbocation intermediate.
10. Can you give an example of electrophilic addition with a balanced equation?
A classic example of electrophilic addition is the reaction of propene with HBr to form 2-bromopropane. The balanced equation is:
CH3–CH=CH2 + HBr → CH3–CHBr–CH3
- The double bond breaks.
- A secondary carbocation forms as an intermediate.
- Br− attacks to give the final product.





















