Question

Which type of bond is present in \[{{\rm{H}}_{\rm{2}}}{\rm{S}}\] molecule?
A) Ionic bond
B) Covalent bond
C) Co-ordinate bond
D) All of three

Answer 1

Hint: A chemical bond defines the attraction of ions, atoms or molecules that causes the formation of molecules. The chemical bonds are of different types, ionic, covalent and coordinate bonds.

Complete step by step solution:Let's discuss the different types of bonds.
An ionic bond defines the one which forms due to the attraction of oppositely charged ions. For example, the molecule of sodium chloride is due to the attraction of the sodium cation and the chloride anion.
The formation of a covalent bond occurs due to the share of electrons between atoms. For example, methane (\[{\rm{C}}{{\rm{H}}_{\rm{4}}}\]) is a covalent compound as the bond formed between C and hydrogen atoms are covalent bond.

The coordinate bond is the one that forms due to the donation of an electron pair by any one atom. For example, in the molecule of \[{\rm{N}}{{\rm{H}}_{\rm{4}}}^ + \] , one N-H bond is a coordinate bond.

Let's come to the question. In the molecule of \[{{\rm{H}}_{\rm{2}}}{\rm{S}}\], sulphur has the six numbers of valence electrons and the oxygen atom has one valence electron. So, they share electrons amongst themselves to form covalent bonds. And thus both hydrogen and sulphur attain noble gas configuration and become stable. The structure of \[{{\rm{H}}_{\rm{2}}}{\rm{S}}\]molecule is,

\[{\rm{H}} - {\rm{S}} - {\rm{H}}\]

Hence, option B is right.

Note: Another type of bonding present, that is, hydrogen bond. This bond is formed when an electronegative atom like Nitrogen, oxygen and fluorine undergoes bond formation with the atom of hydrogen.