Answer
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Hint: Here, we will first try to express the three consecutive odd numbers using a single variable n. After this we will equate their sum to 57 to find the value of n and also the values of three consecutive odd numbers.
Complete step-by-step answer:
Since, we know that any odd number is always of the form (2k +1). We express an odd number in this form because we know that an odd number is not divisible by 2.
Now, the next odd number after (2k+1) will be (2k+3) because if we take (2k+2) then we can see that it is clearly divisible by 2.
So, we can say that the difference between any two consecutive odd numbers is:
= 2k+3 – (2k+1)
=2k+3-2k-1
=2
So, for every two consecutive odd numbers there is a difference of 2.
Now, let us take ‘n’ to be an odd number.
So, an odd number just before n will be (n-2).
And also an odd number just after n will be (n+2).
Since, it is given that the sum of these three consecutive odd numbers is 57. So, we can write the following equation:
n-2+n+n+2=57
3n=57
So, n = 19
The odd number before n will be = n -2 = 19-2 = 17
And the odd number after n will be = n+2 = 19 + 2 = 21
Therefore, the required three consecutive odd numbers are 17, 19 and 21.
Hence, option (a) is the correct answer.
Note: Here, the most important thing to note is that the difference between two consecutive odd numbers is 2. To avoid chances of mistakes the equations should be made carefully.
Complete step-by-step answer:
Since, we know that any odd number is always of the form (2k +1). We express an odd number in this form because we know that an odd number is not divisible by 2.
Now, the next odd number after (2k+1) will be (2k+3) because if we take (2k+2) then we can see that it is clearly divisible by 2.
So, we can say that the difference between any two consecutive odd numbers is:
= 2k+3 – (2k+1)
=2k+3-2k-1
=2
So, for every two consecutive odd numbers there is a difference of 2.
Now, let us take ‘n’ to be an odd number.
So, an odd number just before n will be (n-2).
And also an odd number just after n will be (n+2).
Since, it is given that the sum of these three consecutive odd numbers is 57. So, we can write the following equation:
n-2+n+n+2=57
3n=57
So, n = 19
The odd number before n will be = n -2 = 19-2 = 17
And the odd number after n will be = n+2 = 19 + 2 = 21
Therefore, the required three consecutive odd numbers are 17, 19 and 21.
Hence, option (a) is the correct answer.
Note: Here, the most important thing to note is that the difference between two consecutive odd numbers is 2. To avoid chances of mistakes the equations should be made carefully.
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