QUESTION

# The population of a town increases $5\%$ every year. If the present population is 180800. Find the population after a year.

Hint: First of all, find the increase in the population every year. Then the population after a year is the sum of the present population and the increase in the population every year.

Population of the town increases every year at the rate of $5\%$
So, $5\%$ of 180800 is given by
$= \dfrac{5}{{100}} \times 180800 \\ = 5 \times 1808 \\ = 9040 \\$
Note: The population after a year must be more than the present population as there is an increase in the population of every year in the town. The $x\%$ of $y$ is given by $\dfrac{x}{{100}} \times y$.