Answer
Verified
36.6k+ views
Hint: Oxidation number of every atom must be known to calculate the oxidation number of an atom. We assume the atom for which the oxidation number is to be calculated as “x”.
Complete step-by-step solution:
We know that the charge of a hydrogen atom is +1 and there are four hydrogen atoms so we will take four +1 charges. Now, we need to calculate the oxidation number of Nitrogen now. So, we take the oxidation number of Nitrogen as “x”.
$\begin{array}{l}\mathop {\rm{N}}\limits^{\rm{x}} {\mathop {\rm{H}}\limits^{ + 1} _{\rm{4}}} = 1\\ \Rightarrow {\rm{x}} + 4 \times (1) = 4\\ \Rightarrow x = - 3\end{array}$
So, we can conclude that the oxidation number of nitrogen is -3. Therefore, out of the given five options, E is the correct option. Options A, B, C and D are incorrect.
Additional information:
Oxidation number refers to the number of the electrons which an atom loses or gains in order to form chemical bonds with some other atom.
Some rules of writing oxidation numbers are:
1) In a free uncombined element, the oxidation number is zero.
2) The summation of the oxidation number of all the participating atoms in a compound is always zero.
3) The summation of the oxidation number of all the participating atoms in an ion is equal to the charge of that of the ion.
4) The oxidation number of the fluorine atom in all the compounds is -1.
5) The oxidation number of the halogens in all the compound is -1
6) Hydrogen always has an oxidation number of +1 except in hydrides.
7) Oxygen has an oxidation number of -2 except that of peroxides.
Note: Oxidation number measures the loosing or the excepting of the electrons in forming chemical bonds. Oxidation number of some common atoms never changes such as hydrogen and oxygen except for some exceptions.
Complete step-by-step solution:
We know that the charge of a hydrogen atom is +1 and there are four hydrogen atoms so we will take four +1 charges. Now, we need to calculate the oxidation number of Nitrogen now. So, we take the oxidation number of Nitrogen as “x”.
$\begin{array}{l}\mathop {\rm{N}}\limits^{\rm{x}} {\mathop {\rm{H}}\limits^{ + 1} _{\rm{4}}} = 1\\ \Rightarrow {\rm{x}} + 4 \times (1) = 4\\ \Rightarrow x = - 3\end{array}$
So, we can conclude that the oxidation number of nitrogen is -3. Therefore, out of the given five options, E is the correct option. Options A, B, C and D are incorrect.
Additional information:
Oxidation number refers to the number of the electrons which an atom loses or gains in order to form chemical bonds with some other atom.
Some rules of writing oxidation numbers are:
1) In a free uncombined element, the oxidation number is zero.
2) The summation of the oxidation number of all the participating atoms in a compound is always zero.
3) The summation of the oxidation number of all the participating atoms in an ion is equal to the charge of that of the ion.
4) The oxidation number of the fluorine atom in all the compounds is -1.
5) The oxidation number of the halogens in all the compound is -1
6) Hydrogen always has an oxidation number of +1 except in hydrides.
7) Oxygen has an oxidation number of -2 except that of peroxides.
Note: Oxidation number measures the loosing or the excepting of the electrons in forming chemical bonds. Oxidation number of some common atoms never changes such as hydrogen and oxygen except for some exceptions.
Recently Updated Pages
To get a maximum current in an external resistance class 1 physics JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Let f be a twice differentiable such that fleft x rightfleft class 11 maths JEE_Main
Find the points of intersection of the tangents at class 11 maths JEE_Main
For the two circles x2+y216 and x2+y22y0 there isare class 11 maths JEE_Main
The path difference between two waves for constructive class 11 physics JEE_MAIN
Other Pages
The mole fraction of the solute in a 1 molal aqueous class 11 chemistry JEE_Main
Sodium acetate on heating with soda lime produce A class 12 chemistry JEE_Main
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
How many grams of concentrated nitric acid solution class 11 chemistry JEE_Main
The bond order of ClO bond in ClO4 ion and the effective class 11 chemistry JEE_Main
when an object Is placed at a distance of 60 cm from class 12 physics JEE_Main