Answer
Verified
34.8k+ views
Hint: Solubility product,${ K }_{ sp }$, is the product of a substance’s dissolved ion concentrations raised to the power of their stoichiometric coefficients. ${ K }_{ sp }$ is related to the solubility as one can be used to derive the other, as the solubility product is the product of solubility of each ion in moles per liter.
Complete step by step solution:
It is given that,
${ K }_{ sp }= { 4\times 10 }^{ -9 }$
S =?
where, ${ K }_{ sp }$ = solubility product constant
S = solubility
The salt ${ BaCl }_{ 2 }$ will dissociate as shown below;
${ BaCl }_{ 2 }{ \rightleftharpoons Ba }^{ +2 }{ +2Cl }^{ - }$
Barium chloride dissociates into a barium ion and two chloride ions. Let, the solubility of ${ BaCl }_{ 2 }$ is S then the solubility of ions will be S and 2S respectively.
Let, the solubility of ${ BaCl }_{ 2 }$ is S, then the solubility of the products shown above.
As we know, solubility products are the products of substances raised to their power of coefficients.
So, ${ K }_{ sp }{ =Ba }^{ +2 }{ \times (Cl }^{ -1 }{ ) }^{ 2 }$
= ${ S\times 2S }^{ 2 }$
${ K }_{ sp }= { 4S }^{ 3 }$
Now, put the value of ${ K }_{ sp }$, we get
${ 4\times 10 }^{ -9 }= { 4S }^{ 3 }$
${ S }^{ 3 }{ =10 }^{ -9 }$
${ S }{ =10 }^{ -3 }$
Hence, its solubility would be ${ 1\times 10 }^{ -3 }$.
The correct option is B.
Additional Information:
Ionic product is the product of the concentrations of ions, each raised to a power equal to the stoichiometric number for a solution of salt at a specified concentration.
Ionic product equals the solubility product for a saturated solution.
Note:The possibility to make a mistake is that when barium chloride dissociates into barium ion and two chloride ions. As the solubility product is the product of substances raised to their power of coefficients, so the solubility of chloride ion will be 2S not S.
Complete step by step solution:
It is given that,
${ K }_{ sp }= { 4\times 10 }^{ -9 }$
S =?
where, ${ K }_{ sp }$ = solubility product constant
S = solubility
The salt ${ BaCl }_{ 2 }$ will dissociate as shown below;
${ BaCl }_{ 2 }{ \rightleftharpoons Ba }^{ +2 }{ +2Cl }^{ - }$
Barium chloride dissociates into a barium ion and two chloride ions. Let, the solubility of ${ BaCl }_{ 2 }$ is S then the solubility of ions will be S and 2S respectively.
Let, the solubility of ${ BaCl }_{ 2 }$ is S, then the solubility of the products shown above.
As we know, solubility products are the products of substances raised to their power of coefficients.
So, ${ K }_{ sp }{ =Ba }^{ +2 }{ \times (Cl }^{ -1 }{ ) }^{ 2 }$
= ${ S\times 2S }^{ 2 }$
${ K }_{ sp }= { 4S }^{ 3 }$
Now, put the value of ${ K }_{ sp }$, we get
${ 4\times 10 }^{ -9 }= { 4S }^{ 3 }$
${ S }^{ 3 }{ =10 }^{ -9 }$
${ S }{ =10 }^{ -3 }$
Hence, its solubility would be ${ 1\times 10 }^{ -3 }$.
The correct option is B.
Additional Information:
Ionic product is the product of the concentrations of ions, each raised to a power equal to the stoichiometric number for a solution of salt at a specified concentration.
Ionic product equals the solubility product for a saturated solution.
Note:The possibility to make a mistake is that when barium chloride dissociates into barium ion and two chloride ions. As the solubility product is the product of substances raised to their power of coefficients, so the solubility of chloride ion will be 2S not S.
Recently Updated Pages
To get a maximum current in an external resistance class 1 physics JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Let f be a twice differentiable such that fleft x rightfleft class 11 maths JEE_Main
Find the points of intersection of the tangents at class 11 maths JEE_Main
For the two circles x2+y216 and x2+y22y0 there isare class 11 maths JEE_Main
The path difference between two waves for constructive class 11 physics JEE_MAIN
Other Pages
when an object Is placed at a distance of 60 cm from class 12 physics JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Which of the following sets of displacements might class 11 physics JEE_Main
Oxidation state of S in H2S2O8 is A 6 B 7 C +8 D 0 class 12 chemistry JEE_Main
What is the pH of 001 M solution of HCl a 1 b 10 c class 11 chemistry JEE_Main
The correct IUPAC name of the given compound is A isopropylbenzene class 11 chemistry JEE_Main