Questions & Answers

Question

Answers

(a) $4c{{m}^{2}}$

(b) $16c{{m}^{2}}$

(c) $24c{{m}^{2}}$

(d) $32c{{m}^{2}}$

Answer
Verified

Let us start the solution to the above question by drawing a representative diagram of the situation given in the figure.

Now we know that the area of the square is equal to half of the square of the length of the diagonal of the square.

$\therefore \text{ Area of the square = }\dfrac{{{\left( diagonal \right)}^{2}}}{2}$

Now, it is given that the length of the diagonal of the square is 8cm. So, if we put this in our equation, we get

$\text{Area of the square = }\dfrac{{{8}^{2}}}{2}$

Now, we know that the square of 8 is equal to 64.

$\text{Area of the square = }\dfrac{64}{2}=32c{{m}^{2}}$

Therefore, the area of the square whose diagonal is 8 cm in length is equal to 32 sq cm.

×

Sorry!, This page is not available for now to bookmark.