
How do you solve for \[x\] in \[4x + 2 = 22\] ?
Answer
544.5k+ views
Hint: We are given an equation with one variable. Solving the equation given is nothing but finding the value of that one variable from the given equation only. For that we will first separate the terms with variables from constants. That is taking the \[x\] variable on one side of the equation. Then solve the operations step by step. At the end we will get the value of \[x\] .
Complete step-by-step answer:
Given that,
\[4x + 2 = 22\]
This is an equation with one variable.
Now taking 2 on RHS we het,
\[ \Rightarrow 4x = 22 - 2\]
On performing the subtraction we get.
\[ \Rightarrow 4x = 20\]
Now taking 4 on other side of equation we get,
\[ \Rightarrow x = \dfrac{{20}}{4}\]
Now divide20 by 4,
\[ \Rightarrow x = 5\]
This is our final answer for the solution of the given equation.
So, the correct answer is “x = 5”.
Note: Given is an equation with one variable only so it should have only one fixed solution. That is only one value will satisfy this equation. Note that when we solve this type of equation we try to separate the variable from the given remaining terms. If we are given two such terms of the same variable then first perform the operation in between and then proceed to solve.
Complete step-by-step answer:
Given that,
\[4x + 2 = 22\]
This is an equation with one variable.
Now taking 2 on RHS we het,
\[ \Rightarrow 4x = 22 - 2\]
On performing the subtraction we get.
\[ \Rightarrow 4x = 20\]
Now taking 4 on other side of equation we get,
\[ \Rightarrow x = \dfrac{{20}}{4}\]
Now divide20 by 4,
\[ \Rightarrow x = 5\]
This is our final answer for the solution of the given equation.
So, the correct answer is “x = 5”.
Note: Given is an equation with one variable only so it should have only one fixed solution. That is only one value will satisfy this equation. Note that when we solve this type of equation we try to separate the variable from the given remaining terms. If we are given two such terms of the same variable then first perform the operation in between and then proceed to solve.
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