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Hint- In order to find the same number of crayons and pencils, try to solve using L.C.M.

Number of colour pencils to be packed in a packet \[ = 24\]

Number of crayons to be packed in a packet \[ = 32\]

We have to find the L.C.M of $24$ and $32$.

\[

24 = 2 \times 2 \times 3 \\

32 = 2 \times 2 \times 2 \times 2 \times 2 \\

\]

L.C.M of $24$ and $ 32 $ \[{\text{ = }}2 \times 2 \times 2 \times 2 \times 2 \times 3 = 96\]

Capacity of $1$ packet of colour pencils \[ = 24\]

So, for 96 pencils, number of packets needed \[ = \dfrac{{96}}{{24}} = 4\]

$3$Now, capacity of $1$ packet of crayons \[ = 32\]

SO, for 96 crayons, number of packets needed \[ = \dfrac{{96}}{{32}} = 3\]

$\therefore $ In order to buy full packs of both and same number of pencils and crayons, we need to buy $4$ packets of colour pencils and $3$ packets of crayons.

Note- L.C.M stands for Lowest Common Multiple. For any two numbers a and b, L.C.M is the smallest positive integer that is divided by both a and b. Hence, whenever you see problems like these, L.C.M is the shortest way to find solutions.

Number of colour pencils to be packed in a packet \[ = 24\]

Number of crayons to be packed in a packet \[ = 32\]

We have to find the L.C.M of $24$ and $32$.

\[

24 = 2 \times 2 \times 3 \\

32 = 2 \times 2 \times 2 \times 2 \times 2 \\

\]

L.C.M of $24$ and $ 32 $ \[{\text{ = }}2 \times 2 \times 2 \times 2 \times 2 \times 3 = 96\]

Capacity of $1$ packet of colour pencils \[ = 24\]

So, for 96 pencils, number of packets needed \[ = \dfrac{{96}}{{24}} = 4\]

$3$Now, capacity of $1$ packet of crayons \[ = 32\]

SO, for 96 crayons, number of packets needed \[ = \dfrac{{96}}{{32}} = 3\]

$\therefore $ In order to buy full packs of both and same number of pencils and crayons, we need to buy $4$ packets of colour pencils and $3$ packets of crayons.

Note- L.C.M stands for Lowest Common Multiple. For any two numbers a and b, L.C.M is the smallest positive integer that is divided by both a and b. Hence, whenever you see problems like these, L.C.M is the shortest way to find solutions.