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Given data:

Triangle having sides 4 cm, 5 cm and 6 cm.

Another similar triangle whose sides are (3/5) time of the corresponding sides of the given triangle.

Steps of construction:

$\left( i \right)$ Draw a horizontal line BC of 4 cm using a ruler.

$\left( {ii} \right)$ Now take a compass with pointed end at B and make an arc with pencil end at 5 cm above line BC as shown in the below figure.

$\left( {iii} \right)$ Now again take a compass with pointed end at C and make an arc with pencil end at 6 cm above line BC, which cut the previous arc at point A as shown in the below figure, now join AB and AC.

So this is the required triangle of sides 4 cm, 5 cm and 6 cm.

$\left( {iv} \right)$ Now make a line parallel to line AC from point B downwards as shown in the below figure, and on this line mark five points at interval of 1 cm as shown in the figure below.

$\left( v \right)$ Now from point (r) as shown in the above figure draw a parallel line to AB which cut the line BC at point C’ and join them as shown in the figure.

$\left( {vi} \right)$ Now from point C’ make a parallel line to AC which cuts the line AB at point A’ and join them as shown in the below figure.

So A’BC’ is the required similar triangle whose sides are (3/5) time of the corresponding sides of the given triangle.

So this is the required triangle.

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