
\[C{{H}_{3}}-I+2Na+I-CH{{3}_{}}\xrightarrow{dry\,ether}\] _______
(A) \[{{C}_{2}}{{H}_{5}}\text{ }-\text{ }{{C}_{2}}{{H}_{5}}\]
(B) \[C{{H}_{4}}\]
(C) \[{{C}_{3}}{{H}_{8}}\]
(D) \[C{{H}_{3\text{ }}}-\text{ }C{{H}_{3}}\]
Answer
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Hint: the answer to this question is a is a colourless, odourless gas. It is formed isolated on an industrial scale from natural gas and as a petrochemical by-product of petroleum refining. When four hydrogen is removed from it, the triple bond form of this is used to make plastic.
Complete step by step answer:
\[C{{H}_{3}}-I+2Na+I-CH{{3}_{}}\xrightarrow{dry\,ether}\]
> To answer this question, we should know that the above represented chemical reaction is pointing in the direction that the product will be ethane. This type of reaction is called Wurtz reaction. So, first we will know about Wurtz reaction. We should know that, Wurtz reaction is a coupling reaction wherein sodium metal is reacted with two alkyl halides in the presence of dry ether. These conditions lead to the formation of higher alkane along with a compound containing sodium and the halogen.
> Now, we will complete the reaction that is presented in the question.
2R-X + 2Na → R-R + 2NaX
In the same way, we will complete the given reaction.
\[C{{H}_{3}}-I+2Na+I-C{{H}_{3}}\to C{{H}_{3}}-C{{H}_{3}}+2NaI\]
So, from the completion of above reaction we now say that this reaction is Wurtz reaction. And In this reaction, two different alkyl halides are coupled to yield a longer alkane chain with the help of sodium and dry ether solution. The products that are formed: ethane and sodium iodide. So, now we can say that option D is the correct option. In option D, the formula is of ethane.
Note: From the above discussion we can now say that we cannot synthesize methane via the Wurtz reaction since the product of an organic coupling reaction must have at least two carbon atoms. And we should note that only symmetric alkanes can be synthesized via this method. We can produce a mixture of alkane products, when we react dissimilar alkanes. But these mixtures are very difficult to separate.
Complete step by step answer:
\[C{{H}_{3}}-I+2Na+I-CH{{3}_{}}\xrightarrow{dry\,ether}\]
> To answer this question, we should know that the above represented chemical reaction is pointing in the direction that the product will be ethane. This type of reaction is called Wurtz reaction. So, first we will know about Wurtz reaction. We should know that, Wurtz reaction is a coupling reaction wherein sodium metal is reacted with two alkyl halides in the presence of dry ether. These conditions lead to the formation of higher alkane along with a compound containing sodium and the halogen.
> Now, we will complete the reaction that is presented in the question.
2R-X + 2Na → R-R + 2NaX
In the same way, we will complete the given reaction.
\[C{{H}_{3}}-I+2Na+I-C{{H}_{3}}\to C{{H}_{3}}-C{{H}_{3}}+2NaI\]
So, from the completion of above reaction we now say that this reaction is Wurtz reaction. And In this reaction, two different alkyl halides are coupled to yield a longer alkane chain with the help of sodium and dry ether solution. The products that are formed: ethane and sodium iodide. So, now we can say that option D is the correct option. In option D, the formula is of ethane.
Note: From the above discussion we can now say that we cannot synthesize methane via the Wurtz reaction since the product of an organic coupling reaction must have at least two carbon atoms. And we should note that only symmetric alkanes can be synthesized via this method. We can produce a mixture of alkane products, when we react dissimilar alkanes. But these mixtures are very difficult to separate.
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