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NCERT Solutions for Class 8 Maths Chapter 5 Squares and Square Roots Exercise 5.4

NCERT Solutions

Class 8

Maths

Chapter 6 Squares And Square Roots Exercise 6.4

Last updated date: 25th Jul 2024

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NCERT Solutions for Maths Class 8 Chapter 5 Exercise 5.4 - Free PDF Download

The Class 8 Maths Chapter 5 Exercise 5.4 focuses on the practical application of finding square roots using the division method. This exercise aims to strengthen your understanding of square roots by providing a variety of problems that require you to use systematic division to determine the square root of a given number. By working through ex 5.4 class 8, you will develop a deeper comprehension of the division method for square roots, an essential skill for solving more complex mathematical problems. Students can download the revised Class 8 Maths NCERT Solutions from our page which is prepared so that you can understand it easily.

Table of Content

1. NCERT Solutions for Maths Class 8 Chapter 5 Exercise 5.4 - Free PDF Download

2. Glance on NCERT Solutions Maths Chapter 5 Exercise 5.4 Class 8 Squares and Square Roots

3. Access NCERT Solutions for Maths Class 8 Chapter 5 – Squares and Square Roots

3.1

Exercise 5.4

4. Class 8 Maths Chapter 5 : Exercises Breakdown

5. CBSE Class 8 Maths Chapter 5 Other Study Materials Other

6. Chapter-Specific NCERT Solutions for Class 8 Maths

FAQs

The Chapter 5 Maths Exercise 5.4 Class 8 Solutions are aligned with the updated CBSE guidelines for Class 8, ensuring students are well-prepared for exams. Access the Class 8 Maths Syllabus here.

Glance on NCERT Solutions Maths Chapter 5 Exercise 5.4 Class 8 Squares and Square Roots

In NCERT Solutions Maths Chapter 5 Exercise 5.4 Class 8 we find square roots using the division method
This method is a step-by-step process to find the square root of a perfect square (a number which can be obtained by squaring an integer) by dividing the number by the squares of decreasing perfect squares.
This exercise involves finding the nearest perfect squares on either side of a given number to approximate its square root.
Ex 5.4 class 8 related to the number of digits in the square root of a number or other theoretical aspects of square roots.

Access NCERT Solutions for Maths Class 8 Chapter 5 – Squares and Square Roots

Exercise 5.4

1. Find the square root of each of the following numbers by division method.

2304

Ans: The square root of the given number is

	$\quad\quad 48 \quad$
$\quad 4\quad$	$\overline{23}\:\overline{04}\\$ $ -16\qquad $
$\quad 88\quad$	${\;}704\\ $ $ {\;}704 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{2304} = 48$

4489

Ans: The square root of the given number is

	$\quad\quad 67 \quad$
$\quad 6\quad$	$ \overline{44}\:\overline{89}\\ $ $ -36\qquad $
$\quad 127\quad$	${\;} 889\\ $ $ {\;} 889 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{4489} = 67$.

3481

Ans: The square root of the given number is

	$\quad\quad 59 \quad$
$\quad 5\quad$	$\overline{34}\:\overline{81}\\ $ $ -25\qquad $
$\quad 109\quad$	${\;} 981\\ $ $ {\;} 981 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{3481} = 59$

Ans: The square root of the given number is

	$\quad \quad 23 \quad$
$\quad 2\quad$	$\overline{5}\:\overline{29}\\ $ $ -4\qquad $
$\quad 43\quad$	$ {} 129\\ $ $ {} 129 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{529} = 23$.

3249

Ans: The square root of the given number is

	$\quad\quad 57 \quad$
$\quad 5\quad$	$ \overline{32}\:\overline{49}\\ $ $ -25\qquad $
$\quad 107\quad$	${\;} 749\\$ $ {\;} 749 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{3249} = 57$

1369

Ans: The square root of the given number is

	$\quad\quad 37 \quad$
$\quad 3\quad$	$ \overline{13}\:\overline{69}\\ $ $ -9\qquad $
$\quad 67\quad$	$ {\;} 469\\ $ $ {\;} 469 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{1369} = 37$

5776

Ans: The square root of the given number is

	$\quad\quad 76 \quad$
$\quad 7\quad$	$ \overline{57}\:\overline{76}\\ $ $ -49\qquad $
$\quad 146\quad$	${\;} 876\\ $ $ {\;} 876 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{5776} = 76$.

7921

Ans: The square root of the given number is

	$\quad\quad 30 \quad$
$\quad 8\quad$	$ \overline{79}\:\overline{21}\\ $ $ -64\qquad $
$\quad 169\quad$	$ {\;} 1521\\ $ $ {\;} 1521 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{7921} = 89$

Ans: The square root of the given number is

	$\quad\quad 24 \quad$
$\quad 2\quad$	$\overline{5}\:\overline{76}\\ $ $ -4\qquad $
$\quad 44\quad$	$ {\;} 176\\ $ $ {\;} 176 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{576} = 24$

1024

Ans: The square root of the given number is

	$\quad\quad 32 \quad$
$\quad 3\quad$	$\overline{10}\:\overline{24}\\$ $ -9\qquad $
$\quad 62\quad$	$ {\;} 124\\ $ $ {\;} 124 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{1024} = 32$

3136

Ans:The square root of the given number is

	$\quad\quad 56 \quad$
$\quad 5\quad$	$ \overline{31}\:\overline{36}\\ $ $ -25\qquad $
$\quad 106\quad$	$ {\;} 636\\ $ $ {\;} 636 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{3136} = 56$

Ans: The square root of the given number is

	$\quad \quad 30 \quad$
$\quad 3\quad$	$\overline{9}\:\overline{00}\\ $ $-9\qquad $
$\quad 60\quad$	$ {\;} 00\\ $ $ {\;} 00 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{900} = 30$

2. Find the number of digits in the square root of each of the following numbers (without any calculation).

Ans: Starting from the right side, take the numbers into pairs and place the bar above the number, then we get

$64 = \overline{64}$

There is only one bar (one pair) in the given number, so the number of digits in the square root will be one digit.

Ans: Starting from the right side, take the numbers into pairs and place the bar above the number, then we get

\[144 = \overline{1}\overline{44}\]

There are only two bar (two pair) in the given number, so the number of digits in the square root will be two-digit.

4489

Ans: Starting from the right side, take the numbers into pairs and place the bar above the number, then we get

$4489 = \overline{44}\overline{89}$

There is only two bar (two pair) in the given number, so the number of digits in the square root will be two-digit.

27225

Ans: Starting from the right side, take the numbers into pairs and place the bar above the number, then we get

$27225 = \overline{2}\overline{72}\overline{25}$

There is only three bar (three pair) in the given number, so the number of digits in the square root will be three-digit.

390625

Ans: Starting from the right side, take the numbers into pairs and place the bar above the number, then we get

$390625 = \overline{39}\overline{06}\overline{25}$

There is only three bar (three pair) in the given number, so the number of digits in the square root will be three-digit.

3. Find the square root of the following decimal numbers.

\[~\mathbf{2}.\mathbf{56}\]

Ans: The square root of the given number is

	$\quad\quad 1.6 \quad$
$\quad 1\quad$	$\overline{2.}\:\overline{56}\\ $ $ -1\qquad $
$\quad 26\quad$	${\;} 156\\ $ $ {\;} 156 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{2.56} = 1.6$.

\[\mathbf{7}.\mathbf{29}\]

Ans: The square root of the given number is

	$\quad\quad 2.7 \quad$
$\quad 2\quad$	$ \overline{7.}\:\overline{29}\\ $ $ -4\qquad $
$\quad 47\quad$	${\;} 329\\ $ $ {\;} 329 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{7.29} = 2.7$.

51.84

Ans: The square root of the given number is

	$\quad\quad 7.2 \quad$
$\quad 7\quad$	$\overline{51.}\:\overline{84}\\ $ $ -49\qquad $
$\quad 142 \quad$	${\;} 284\\ $ $ {\;} 284 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{51.84} = 7.2$.

42.25

Ans: The square root of the given number is

	$\quad\quad 6.5 \quad$
$\quad 6\quad$	$\overline{42}\:\overline{.25}\\ $ $ -36\qquad $
$\quad 125\quad$	$ {\;} 625\\ $ $ {\;} 625 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{42.25} = 6.5$.

31.36

Ans: The square root of the given number is

	$\quad\quad 5.6 \quad$
$\quad 5\quad$	$ \overline{31}\:\overline{.36}\\ $ $ -9\qquad $
$\quad 106\quad$	$ {\;} 636\\$ $ {\;} 636 $
	$\qquad\quad 0\quad$

$\Rightarrow \text{ }\sqrt{31.36} = 5.6$.

4. Find the least number, which must be subtracted from each of the following numbers so as to get a perfect square. Also, find the square root of the perfect square so obtained.

$402$

Ans: The square root of the given number is

	$\quad\quad 20 \quad$
$\quad 2\quad$	$\overline{4}\:\overline{02}\\$ $-4\qquad $
$\quad 40\quad$	${\;} 002\\$ $ {\;} 002 $
	$\qquad\quad 0\quad$

The remainder of the long division method is$2$.

It shows that the square of $20$ is less than the square root of $402$ .

Therefore a perfect square will be get by subtracting $2$ from the$402$.

$\therefore \Rightarrow $The required perfect square $= 402 - 2 = 400$

The square root of the perfect square$\sqrt{400} = 20$.

1989

Ans: The square root of the given number is

	$\quad\quad 44 \quad$
$\quad 4\quad$	$\overline{19}\:\overline{89}\\ $ $ -16\qquad $
$\quad 84\quad$	$ {\;} 389\\ $ $ {\;} 336 $
	$\qquad\quad 53\quad$

The remainder of the long division method is $53$.

It shows that the square of $44$ is less than the square root of $1989$ .

Therefore a perfect square will be obtained by subtracting $53$ from the$1989$.

$\therefore \Rightarrow $The required perfect square $= 1989 - 53 = 1936$

The square root of the perfect square$\sqrt{1989} = 44$.

3250

Ans: The square root of the given number is

	$\quad\quad 57 \quad$
$\quad 5\quad$	$ \overline{32}\:\overline{50}\\ $ $ -25\qquad $
$\quad 107\quad$	$ {\;} 750\\ $ $ {\;} 749 $
	$\qquad\quad 1\quad$

The remainder of the long division method is $1$.

It shows that the square of $57$ is less than the square root of $3250$ .

Therefore a perfect square will be get by subtracting $2$ from the $3250$.

$\therefore \Rightarrow $The required perfect square $= 3250 - 1 = 3249$

The square root of the perfect square $\sqrt{3249} = 57$.

Ans: The square root of the given number is

	$\quad\quad 28 \quad$
$\quad 2\quad$	$\overline{8}\:\overline{25}\\ $ $ -4\qquad $
$\quad 48\quad$	$ {\;} 425\\ $ $ {\;} 384 $
	$\qquad\quad 41\quad$

The remainder of the long division method is $41$.

It shows that the square of $28$ is less than the square root of $825$ .

Therefore a perfect square will be get by subtracting $41$ from the $825$.

$\therefore \Rightarrow $The required perfect square $= 825 - 41 = 784$

The square root of the perfect square $\sqrt{784} = 28$.

4000

Ans: The square root of the given number is

	$\quad\quad 63 \quad$
$\quad 6\quad$	$ \overline{40}\:\overline{00}\\ $ $ -36\qquad $
$\quad 123\quad$	$ {\;} 400\\ $ $ {\;} 369 $
	$\qquad\quad 31\quad$

The remainder of the long division method is $31$.

It shows that the square of $63$ is less than the square root of $4000$ .

Therefore a perfect square will be get by subtracting $31$ from the $4000$.

$\therefore \Rightarrow $The required perfect square $= 4000 - 31 = 3969$

The square root of the perfect square $\sqrt{3969} = 63$.

5. Find the least number which must be added to each of the following numbers so as to get a perfect square. Also, find the square root of the perfect square so obtained.

Ans: The square root of the given number is

	$\quad\quad 22 \quad$
$\quad 2\quad$	$ \overline{5}\:\overline{25}\\ $ $ -4\qquad $
$\quad 42\quad$	$ {\;} 125\\ $ $ {\;} 84 $
	$\qquad\quad 41\quad$

The remainder of the long division method is $41$.

It shows that the square of $22$ is less than the square root of $525$ .

${{22}^{2}} = 484 \And {{23}^{2}} = 529$

We need to find the least number, which must be added to the given number to get a perfect square.

Therefore a perfect square will be get by subtracting ${{23}^{2}}$ from the $525$.

$\therefore \Rightarrow $The required perfect square $= 529 - 525 = 4$

The square root of the perfect square $\sqrt{529} = 23$.

1750

Ans: The square root of the given number is

	$\quad\quad 41 \quad$
$\quad 4\quad$	$ \overline{17}\:\overline{50}\\ $ $ -16\qquad $
$\quad 51\quad$	$ {\;} 150\\ $ $ {\;} 81 $
	$\qquad\quad 69\quad$

The remainder of the long division method is \[69\].

It shows that the square of $41$ is less than the square root of $1750$ .

${{41}^{2}} = 1681 \And {{42}^{2}} = 1764$

We need to find the least number, which must be added to the given number so as to get a perfect square.

Therefore a perfect square will be get by subtracting ${{42}^{2}}$ from the $1750$.

$\therefore \Rightarrow $The required perfect square $= 1764 - 1750 = 14$

The square root of the perfect square $\sqrt{1764} = 42$.

Ans: The square root of the given number is

	$\quad\quad 15 \quad$
$\quad 1\quad$	$ \overline{2}\:\overline{52}\\ $ $ -1\qquad $
$\quad 25\quad$	$ {\;} 152\\ $ $ {\;} 125 $
	$\qquad\quad 27\quad$

The remainder of the long division method is \[27\].

It shows that the square of $15$ is less than the square root of $252$ .

${{15}^{2}} = 225 \And {{16}^{2}} = 256$

We need to find the least number, which must be added to the given number so as to get a perfect square.

Therefore a perfect square will be get by subtracting ${{16}^{2}}$ from the $252$.

$\therefore \Rightarrow $The required perfect square $= 256 - 252 = 4$

The square root of the perfect square $\sqrt{1256} = 16$.

1825

Ans: The square root of the given number is

	$\quad\quad 42 \quad$
$\quad 4\quad$	$ \overline{18}\:\overline{25}\\ $ $ -16\qquad $
$\quad 82\quad$	$ {\;} 225\\ $ $ {\;} 164 $
	$\qquad\quad 61\quad$

The remainder of the long division method is \[61\].

It shows that the square of $42$ is less than the square root of $1825$ .

${{42}^{2}} = 1764 \And {{43}^{2}} = 1849$

We need to find the least number, which must be added to the given number so as to get a perfect square.

Therefore a perfect square will be get by subtracting ${{43}^{2}}$ from the $1825$.

$\therefore \Rightarrow $The required perfect square $= 1849 - 1825 = 24$

The square root of the perfect square $\sqrt{1849} = 43$.

6412

Ans: The square root of the given number is

	$\quad\quad 80 \quad$
$\quad 8\quad$	$ \overline{64}\:\overline{12}\\ $ $ -64\qquad $
$\quad 160\quad$	$ {\;} 012\\$ $ {\;} 0 $
	$\qquad\quad 12\quad$

The remainder of the long division method is \[12\].

It shows that the square of $15$ is less than the square root of $6412$ .

${{80}^{2}} = 6400 \And {{81}^{2}} = 6561$

We need to find the least number, which must be added to the given number so as to get a perfect square.

Therefore a perfect square will be get by subtracting ${{81}^{2}}$ from the $6412$.

$\therefore \Rightarrow $The required perfect square $= 6561 - 6412 = 149$

The square root of the perfect square $\sqrt{6561} = 81$.

6. Find the length of the side of a square whose area is $441 {{m}^{2}}$.

Ans: Let us take the length of the side of the square to be $x m$.

Area of Square $= {{\left( x \right)}^{2}} = 441 {{m}^{2}}$.

$x = \sqrt{441}$

The square root of $x $is

	$\quad\quad 21 \quad$
$\quad 2\quad$	$ \overline{4}\:\overline{41}\\ $ $ -4\qquad $
$\quad 41\quad$	$ {\;} 041\\ $ $ {\;} 041 $
	$\qquad\quad 0\quad$

$\therefore \Rightarrow x = 21 m$.

So, The length of the side of a square is $21 m$.

7. In a right triangle

$ ABC, \therefore B\text{ }=\text{ }90{}^\circ . \\ $

If \[AB = 6 cm , BC = 8 cm, \]find \[AC\]

Ans:

\[\Delta ABC\]is a right angle at \[B.\]

By Pythagoras theorem,

\[A{{C}^{2}} = A{{B}^{2}} + B{{C}^{2}}\]

\[A{{C}^{2}} = {{\left( 6 cm \right)}^{2}} + {{\left( 8 cm \right)}^{2}}\]

\[A{{C}^{2}} = \left( 36 + 64 \right) c{{m}^{2}}\]

\[A{{C}^{2}} = \left( 100 \right)c{{m}^{2}}\]

\[AC = \left( \sqrt{100} \right)cm = \left( \sqrt{10 \times 10} \right)cm\]

\[AC = 10cm\].

If \[AC = 13 cm, BC = 5 cm,\] find \[AB\]

Ans:

\[\Delta ABC\]is a right angle at \[B.\]

By Pythagoras theorem,

\[A{{C}^{2}} = A{{B}^{2}} + B{{C}^{2}}\]

\[{{\left( 13 \right)}^{2}} = A{{B}^{2}} + {{\left( 5 cm \right)}^{2}}\]

\[A{{B}^{2}} = {{\left( 13 cm \right)}^{2}} - {{\left( 5 cm \right)}^{2}}\]

\[A{{B}^{2}} = \left( 169 - 25 \right)c{{m}^{2}}\]

\[A{{B}^{2}} = \left( 144 \right)c{{m}^{2}}\]

\[AC = \left( \sqrt{144} \right)cm = \left( \sqrt{12 \times 12} \right)cm\]

\[AB = 12 cm\]

8. A gardener has $1000$plants. He wants to plant these in such a way that the number of rows and the number of columns remain the same. Find the minimum number of plants he needs more for this.

Ans:

The gardener has $1000$ plants and it has the same number of rows and the same number of columns.

The square root of 1000 is

	$\quad\quad 31 \quad$
$\quad 3\quad$	$ \overline{10}\:\overline{00}\\ $ $ -9\qquad $
$\quad 61\quad$	$ {\;} 100\\ $ $ {\;} 061 $
	$\qquad\quad 39\quad$

The remainder of the long division method is \[39\].

It shows that the square of $31$ is less than the square root of $1000$ .

${{31}^{2}} = 961 \And {{32}^{2}} = 1024$

We need to find the least number, which must be added to the given number so as to get a perfect square.

Therefore a perfect square will be get by subtracting ${{32}^{2}}$ from the$1000$.

$\therefore \Rightarrow $The required perfect square $= 1024 - 1000 = 24$

Hence, The required number of plants is $24$.

9. These are $500$ children in a school. For a P.T. drill, they have to stand in such a manner that the number of rows is equal to the number of columns. How many children would be left out in this arrangement?

Ans:

It is given that there are $500$ children in a school.

For a P.T. drill, they have to stand in such a manner that the number of rows is equal to the number of columns.

To find that the number of children left in this arrangement,

	$\quad\quad 22 \quad$
$\quad 2\quad$	$ \overline{5}\:\overline{00}\\ $ $ -4\qquad $
$\quad 42\quad$	$ {\;} 100\\ $ $ {\;} 084 $
	$\qquad\quad 16\quad$

The remainder of the long division method is$16$.

It shows that the square of $22$ is less than the square root of $500$ .

Therefore a perfect square will be get by subtracting $16$ from the $500$.

$\therefore \Rightarrow $ The required perfect square $= 500 - 16 = 484$

The square root of the perfect square $16$.

Then the number of children would be left out in this arrangement is $16$

Conclusion

In conclusion, Chapter 5 Exercise 5.4 has provided a comprehensive understanding of squares and square roots, crucial for mastering higher-level math concepts. This exercise covers key topics such as properties of squares and square roots, shortcut methods for finding squares and estimating square roots, and various problem-solving techniques.

Over the past few years, approximately 4 to 5 questions from Class 8 Maths Ch 6 Ex 5.4 have been featured in exams, emphasizing its importance in the curriculum. Mastery of these concepts will significantly aid students in their mathematical journey.

Class 8 Maths Chapter 5 : Exercises Breakdown

Exercise	Number of Questions
Exercise 5.1	9 Questions & Answers
Exercise 5.2	2 Questions & Answers
Exercise 5.3	10 Questions & Answers

CBSE Class 8 Maths Chapter 5 Other Study Materials Other

S.No.	Important Links for Chapter 5 Squares and Square Roots of Maths
1.	Class 8 Squares and Square Roots of Maths Important Questions
2.	Class 8 Squares and Square Roots of Maths Formulas
3.	Class 8 Squares and Square Roots of Maths Notes
4.	Class 8 Squares and Square Roots of Maths NCERT Exemplar Solutions
5.	Class 8 Squares and Square Roots of Maths RD Sharma Solutions
6.	Class 8 Squares and Square Roots of Maths RS Aggarwal Solutions

Chapter-Specific NCERT Solutions for Class 8 Maths

Given below are the chapter-wise NCERT Solutions for Class 8 Maths. You can use it as your 8th maths guide. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.

S.No.	NCERT Solutions Class 8 Maths Chapter-wise List
1	Chapter 1 - Rational Numbers
2	Chapter 2 - Linear Equations In One Variable
3	Chapter 3 - Understanding Quadrilaterals
4	Chapter 4 - Data Handling
5	Chapter 5 - Squares And Square Roots
6	Chapter 6 - Cubes and Cube Roots
7	Chapter 7 - Comparing Quantities
8	Chapter 8 - Algebraic Expressions and Identities
9	Chapter 9 - Mensuration
10	Chapter 10 - Exponents and Powers
11	Chapter 11 - Direct and Inverse Proportions
12	Chapter 12 - Factorisation
13	Chapter 13 - Introduction to Graphs

FAQs on NCERT Solutions for Class 8 Maths Chapter 5 Squares and Square Roots Exercise 5.4

1. What are the important topics covered in NCERT Solutions for class 8 Maths Chapter 5- Squares and Square Roots?

The important topics covered in NCERT Solutions for Class 8 Maths Chapter 5 are: Squares and Square Roots are covered in Class 8 Chapter 5 of the text as "square number," "square root," "properties of square numbers," "numbers between square numbers," "adding odd numbers," "sum of consecutive natural numbers," and "product of two consecutive odd or even numbers." calculating a number's square, Pythagorean triplets, Square roots of decimals, repeated subtraction to find the square root, prime factorization to find the square root, the division method, and estimating the square root

2. Where can I get NCERT Solutions for Class 8 Maths Chapter 5 - Squares and Square Roots Exercise 5.4?

Vedantu, India's No. 1 online educational platform, offers NCERT Solutions for Class 8 Maths, Chapter 5: Squares and Square Roots Exercise 5.4, which have been meticulously prepared by highly qualified and experienced teachers in accordance with the most recent CBSE guidelines. These solutions include precise and comprehensive answers to every sum in the Class 8 NCERT Maths textbook. On Vedantu's official website (Vedantu.com), you may quickly and gratis download PDF versions of these study guides. You can also get the Vedantu mobile app.

3. How many Questions are there in Chapter 5 - Squares and Square Roots Exercise 5.4?

There are nine questions in Class 8 Maths Chapter 5 - Squares and Square Roots Exercise 5.4. Generally, all the questions in Chapter 5 explain important concepts such as "square numbers," "square roots," and "properties of square numbers," If you are looking for NCERT solutions for Class 8 Math, you can go to Vedantu, India's leading online platform. At Vedantu, all the chapter exercises at One Place are prepared by an expert teacher according to NCERT book guidelines, and these solutions are 100% accurate and presented in a stepwise manner.

4. What is the importance of Vedantu’s NCERT Solutions for Class 8 Maths Chapter 5 - Squares and Square Roots Exercise 5.4?

The best online educational platform in India, Ventantu, offers free NCERT solutions for all subjects. Among the main benefits are:

These answers have been thoughtfully prepared in accordance with the most recent CBSE standards.
Solutions that are presented in a step-by-step fashion and are 100 percent accurate always produce excellent outcomes.
Students can complete the math assignment on time by using a variety of strategies and time-saving techniques.
Both the Vedantu website and mobile app offer free PDF downloads of all of these study materials.

5. Do I need to practice all the questions provided in NCERT Solutions for Class 8 Maths Chapter 5 - Squares and Square Roots Exercise 5.4?

To get high grades, you must undoubtedly practice all of the questions from the NCERT textbook. The Class 8 Maths NCERT answers are the most helpful source since they provide a variety of problems that need the right concept and knowledge to be answered. You can get ready for any challenging or uncommon exam questions by consistently practising. For free, Vedantu offers comprehensive, step-by-step NCERT solutions for all math chapters.

6. Why is learning the division method for square roots important in Class 8 Maths Ch 6 Ex 5.4?

The division method provides a systematic approach to finding square roots, which is essential for solving more complex mathematical problems. You can learn more about this in Class 8 Maths Exercise 5.4 Solutions.

7. Are there any prerequisites for understanding Exercise 5.4?

Yes, you should have a basic understanding of squares, square roots, and division.

8. How does practising Class 8 Maths Exercise 5.4 Solutions benefit me in exams?

Practising Maths Class 8 Chapter 5 Exercise 5.4 helps solidify your understanding of the division method, which can be beneficial in exams where finding square roots is required.

9. Are there any shortcuts to finding square roots other than the division method?

Yes, there are other methods like prime factorization and estimation, but the division method is a precise and reliable technique taught in Exercise 5.4.

10. Where can I find the NCERT Solutions for Class 8 Maths 5.4 Exercise?

NCERT Solutions for Exercise 5.4 can be found in textbooks and on various educational websites like Vedantu, which provide free PDF downloads.

NCERT Solutions for Class 8 Maths Chapter 5 Squares and Square Roots Exercise 5.4

NCERT Solutions for Maths Class 8 Chapter 5 Exercise 5.4 - Free PDF Download

Glance on NCERT Solutions Maths Chapter 5 Exercise 5.4 Class 8 Squares and Square Roots

Access NCERT Solutions for Maths Class 8 Chapter 5 – Squares and Square Roots

Exercise 5.4

Conclusion

Class 8 Maths Chapter 5 : Exercises Breakdown

CBSE Class 8 Maths Chapter 5 Other Study Materials Other

Chapter-Specific NCERT Solutions for Class 8 Maths

FAQs on NCERT Solutions for Class 8 Maths Chapter 5 Squares and Square Roots Exercise 5.4

NCERT Solutions for Class 8

CBSE Study Materials for Class 8

CBSE Study Materials