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# NCERT Solutions for Class 8 Maths Chapter 2 - Exercise Last updated date: 05th Dec 2023
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## NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1

NCERT Solutions for Class 8 Maths Chapter 2 provided by Vedantu offers clarifications for the students who can go far but lack the concentration. These solutions help the students to score excellent marks in their exams. If you are a student of Class 8, then this NCERT Solutions for Class 8 Maths Chapter 2 PDF file is beneficial to obtain. All the experts at Vedantu have enough skills and followed CBSE guidelines to create the NCERT Solutions of Class 8, which are available on the site for download. Subjects like Science, Maths, English will become easy to study if you have access to NCERT Solution for Class 8 Science, Maths solutions and solutions of other subjects.

## Access NCERT solutions for Maths Chapter 2 – Linear Equations in One Variable

1. Find the solution of $\text{x-2=7}$.

Ans: We have an equation $\text{x-2=7}$, to solve the following equation we will shift $\text{2}$ to right hand side, we get

$\text{x=7+2}$

$\text{x=9}$

2. Find the solution of $\text{y+3=10}$.

Ans: We have an equation $\text{y+3=10}$, to solve the following equation we will shift $\text{3}$ to right hand side, we get

$\text{y=10-3}$

$\text{y=7}$

3. Find the solution of $\text{6=z+2}$.

Ans: We have an equation $\text{6=z+2}$, to solve the following equation we will shift $\text{2}$ to left hand side, we get

$\text{6-2=z}$

$\text{z=4}$

4. Find the solution of $\frac{\text{3}}{\text{7}}\text{+x=}\frac{\text{17}}{\text{7}}$.

Ans: We have an equation $\frac{\text{3}}{\text{7}}\text{+x=}\frac{\text{17}}{\text{7}}$, to solve the following equation we will shift $\frac{\text{3}}{\text{7}}$ to right hand side, we get

$\text{x=}\frac{\text{17}}{\text{7}}\text{-}\frac{\text{3}}{\text{7}}$

$\text{x=}\frac{\text{14}}{\text{7}}$

$\text{x=2}$

5. Find the solution of $\text{6x=12}$.

Ans: We have an equation $\text{6x=12}$, to solve the following equation, we will shift $6$ to right hand side and divide $12$ by $6$, we get

$\text{x=}\frac{\text{12}}{6}$

$\text{x=2}$

6. Find the solution of $\frac{\text{t}}{\text{5}}\text{=10}$.

Ans: We have an equation $\frac{\text{t}}{\text{5}}\text{=10}$, to solve the following equation, we will shift $5$ to right hand side and multiply $10$ by $5$, we get

$\text{t=10}\times \text{5}$

$\text{t=50}$

7. Find the solution of $\frac{\text{2x}}{\text{3}}\text{=18}$.

Ans: We have an equation $\frac{\text{2x}}{\text{3}}\text{=18}$, to solve the following equation, we will multiply both sides of equation by $\frac{\text{2}}{\text{3}}$ , we get

$\text{x=}\frac{\text{18 }\!\!\times\!\!\text{ 3}}{\text{2}}$

$\text{x=27}$

8. Find the solution of $\text{1}\text{.6=}\frac{\text{y}}{\text{1}\text{.5}}$.

Ans: We have an equation $\text{1}\text{.6=}\frac{\text{y}}{\text{1}\text{.5}}$, to solve the following equation, we will multiply both sides of equation by $1.5$ , we get

$\text{1}\text{.6 }\!\!\times\!\!\text{ 1}\text{.5=y}$

$\text{y=2}\text{.4}$

9. Find the solution of $\text{7x-9=16}$.

Ans: We have an equation $\text{7x-9=16}$, to solve the following equation we will shift $\text{9}$ to right hand side, we get

$\text{7x=16+9}$

$\text{7x=25}$

Now, we will divide both sides by $\text{7}$, we get

$\text{x=}\frac{\text{25}}{\text{7}}$

10. Find the solution of $\text{14y-8=13}$.

Ans: We have an equation $\text{14y-8=13}$, to solve the following equation we will shift $\text{8}$ to right hand side, we get

$\text{14y=13+8}$

$\text{14y=21}$

Now, we will divide both sides by $\text{14}$, we get

$\text{x=}\frac{\text{21}}{\text{14}}$

$\text{x=}\frac{\text{3}}{\text{2}}$

11. Find the solution of $\text{17+6p=9}$.

Ans: We have an equation $\text{17+6p=9}$, to solve the following equation we will shift $\text{17}$ to right hand side, we get

$\text{6p=9-17}$

$\text{6p=-8}$

Now, we will divide both sides by $\text{6}$, we get

$\text{p=-}\frac{\text{8}}{\text{6}}$

$\text{p=-}\frac{\text{4}}{\text{3}}$

12. Find the solution of $\frac{\text{x}}{\text{3}}\text{+1=}\frac{\text{7}}{\text{15}}$.

Ans: We have an equation $\frac{\text{x}}{\text{3}}\text{+1=}\frac{\text{7}}{\text{15}}$, to solve the following equation we will shift $\text{1}$ to right hand side, we get

$\frac{\text{x}}{\text{3}}\text{=}\frac{\text{7}}{\text{15}}\text{-1}$

$\frac{\text{x}}{\text{3}}\text{=-}\frac{\text{8}}{\text{15}}$

Now, we will multiply both sides by $\text{3}$, we get

$\text{x=-}\frac{\text{8 }\!\!\times\!\!\text{ 3}}{\text{15}}$

$\text{x=-}\frac{\text{8}}{\text{5}}$

## Why Choose NCERT Solutions for Class 8 Maths Chapter 2?

Math can be very tricky and hard to perform. It gets better with practice. But the method should be in an efficient way that you remember the equation and formula. To make this convenient for you, we have the perfect solution.

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Significance of NCERT Solutions:

Maths is a difficult subject for so many students. On the other hand, it can be effortless for some. It depends on every individual's efficiency of understanding. To make it simple for you, NCERT Solutions have a practical list of subject experts to simplify the Class 8 Maths Chapter 2. You can obtain the free PDF downloads from our Website.

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To make sure our students are gaining better results by practising our answers for Linear Equations in One Variable Class 8, our teachers conduct a series of a questionnaire and maintain the consistency of it.

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Important Topics under NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Exercise 2.1

Chapter 2 of the class 8 maths syllabus is on Linear Equations in One Variable. It is a very important chapter in mathematics that is covered in class 8 and is divided into 5 major sections. The following is a list of the important topics covered under Linear Equations in One Variable. We advise students to go through each one of these topics carefully to make sure they don’t miss out on internalising the concepts of Linear Equations in One Variable.

• Introduction

• Solving equations where linear expressions are on one side and numbers are on the other side of the equation

• Applications of linear equations in one variable

• Solving equations with variables on both the sides

• Reducing the given equations to a simpler form

### Important Takeaways from NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable

• Division and multiplication of algebraic expressions with integers as coefficients

• Common errors faced by students

• Factorisation

• Introduction to identities

• Process of solving linear equations in one variable

Importance of Linear Equations in One Variable

Learning about Linear Equations helps you modularized the real phenomena that make one variable changing constantly with the other variable involved.

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Vedantu has transformed the idea of training. It produces an enormously abridged version of material so that you can absorb and master complicated theories of Maths in a more accessible manner. Study today with Vedantu and excel in your class!

And, by registering on our site, you will keep getting the information about our classes, upcoming events, free classes, webinars, and other important updates. You can avail of all the services for free, and you can also get points by inviting your friends to the page. You can join Vedantu discussion forums from where you can make study friends and have a study together.

### NCERT Solutions Class 8 Maths Chapter 2 All Exercises

Chapter 2 - Linear Equations in One Variable Exercises in PDF Format

Exercise 2.2

16 Questions with Solutions

Exercise 2.3

10 Questions with Solutions

### 10 Questions with Solutions

Exercise 2.5

10 Questions with Solutions

7 Questions with Solutions

## FAQs on NCERT Solutions for Class 8 Maths Chapter 2 - Exercise

1. Where can I get NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1?

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1 are available at India's top online learning resource, Vedantu. These solutions, which strictly comply with the most recent CBSE requirements, were created by highly certified and experienced teachers. These solutions include precise and thorough responses to every sum presented in the NCERT Mathematics textbook for Class 8. On Vedantu's official website (Vedantu.com), you may quickly and gratis download PDF versions of these study guides. You can also get the Vedantu mobile app.

2. How many Questions are there in Chapter 2 Linear Equations in One Variable Exercise 2.1?

Exercise 2.1 from Chapter 2: Linear Equations in One Variable Math consists of a total of 12 problems. In general, each question in Chapter 2 uses a single variable to teach the foundations of a linear equation. You can consult Vedantu, India's most popular online platform if you're looking for NCERT solutions for Class 8 Math. At Vedantu, all of the chapter exercises are collected in one location and solved step-by-step by a qualified teacher in accordance with the NCERT book's instructions.

3. How can I benefit from Vedantu’s NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1?

There are lots of benefits you can get from Vedantu’s NCERT solutions. Some of them are listed below:

• By responding to these NCERT practice questions, they will be able to learn all the crucial ideas and formulae.

• These solutions are created by experienced professionals working at Vedantu and precisely follow the CBSE curriculum.

• Students will perform better if these solutions are presented to them in an easy-to-understand and step-by-step fashion.