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# NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1

## NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1

Last updated date: 29th Jan 2023
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NCERT Solutions for Class 8 Maths Chapter 2 provided by Vedantu offers clarifications for the students who can go far but lack the concentration. These solutions help the students to score excellent marks in their exams. If you are a student of Class 8, then this NCERT Solutions for Class 8 Maths Chapter 2 PDF file is beneficial to obtain. All the experts at Vedantu have enough skills and followed CBSE guidelines to create the NCERT Solutions of Class 8, which are available on the site for download. Subjects like Science, Maths, English will become easy to study if you have access to NCERT Solution for Class 8 Science, Maths solutions and solutions of other subjects.

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## Access NCERT solutions for Maths Chapter 2 – Linear Equations in One Variable

1. Find the solution of $\text{x-2=7}$.

Ans: We have an equation $\text{x-2=7}$, to solve the following equation we will shift $\text{2}$ to right hand side, we get

$\text{x=7+2}$

$\text{x=9}$

2. Find the solution of $\text{y+3=10}$.

Ans: We have an equation $\text{y+3=10}$, to solve the following equation we will shift $\text{3}$ to right hand side, we get

$\text{y=10-3}$

$\text{y=7}$

3. Find the solution of $\text{6=z+2}$.

Ans: We have an equation $\text{6=z+2}$, to solve the following equation we will shift $\text{2}$ to left hand side, we get

$\text{6-2=z}$

$\text{z=4}$

4. Find the solution of $\frac{\text{3}}{\text{7}}\text{+x=}\frac{\text{17}}{\text{7}}$.

Ans: We have an equation $\frac{\text{3}}{\text{7}}\text{+x=}\frac{\text{17}}{\text{7}}$, to solve the following equation we will shift $\frac{\text{3}}{\text{7}}$ to right hand side, we get

$\text{x=}\frac{\text{17}}{\text{7}}\text{-}\frac{\text{3}}{\text{7}}$

$\text{x=}\frac{\text{14}}{\text{7}}$

$\text{x=2}$

5. Find the solution of $\text{6x=12}$.

Ans: We have an equation $\text{6x=12}$, to solve the following equation, we will shift $6$ to right hand side and divide $12$ by $6$, we get

$\text{x=}\frac{\text{12}}{6}$

$\text{x=2}$

6. Find the solution of $\frac{\text{t}}{\text{5}}\text{=10}$.

Ans: We have an equation $\frac{\text{t}}{\text{5}}\text{=10}$, to solve the following equation, we will shift $5$ to right hand side and multiply $10$ by $5$, we get

$\text{t=10}\times \text{5}$

$\text{t=50}$

7. Find the solution of $\frac{\text{2x}}{\text{3}}\text{=18}$.

Ans: We have an equation $\frac{\text{2x}}{\text{3}}\text{=18}$, to solve the following equation, we will multiply both sides of equation by $\frac{\text{2}}{\text{3}}$ , we get

$\text{x=}\frac{\text{18 }\!\!\times\!\!\text{ 3}}{\text{2}}$

$\text{x=27}$

8. Find the solution of $\text{1}\text{.6=}\frac{\text{y}}{\text{1}\text{.5}}$.

Ans: We have an equation $\text{1}\text{.6=}\frac{\text{y}}{\text{1}\text{.5}}$, to solve the following equation, we will multiply both sides of equation by $1.5$ , we get

$\text{1}\text{.6 }\!\!\times\!\!\text{ 1}\text{.5=y}$

$\text{y=2}\text{.4}$

9. Find the solution of $\text{7x-9=16}$.

Ans: We have an equation $\text{7x-9=16}$, to solve the following equation we will shift $\text{9}$ to right hand side, we get

$\text{7x=16+9}$

$\text{7x=25}$

Now, we will divide both sides by $\text{7}$, we get

$\text{x=}\frac{\text{25}}{\text{7}}$

10. Find the solution of $\text{14y-8=13}$.

Ans: We have an equation $\text{14y-8=13}$, to solve the following equation we will shift $\text{8}$ to right hand side, we get

$\text{14y=13+8}$

$\text{14y=21}$

Now, we will divide both sides by $\text{14}$, we get

$\text{x=}\frac{\text{21}}{\text{14}}$

$\text{x=}\frac{\text{3}}{\text{2}}$

11. Find the solution of $\text{17+6p=9}$.

Ans: We have an equation $\text{17+6p=9}$, to solve the following equation we will shift $\text{17}$ to right hand side, we get

$\text{6p=9-17}$

$\text{6p=-8}$

Now, we will divide both sides by $\text{6}$, we get

$\text{p=-}\frac{\text{8}}{\text{6}}$

$\text{p=-}\frac{\text{4}}{\text{3}}$

12. Find the solution of $\frac{\text{x}}{\text{3}}\text{+1=}\frac{\text{7}}{\text{15}}$.

Ans: We have an equation $\frac{\text{x}}{\text{3}}\text{+1=}\frac{\text{7}}{\text{15}}$, to solve the following equation we will shift $\text{1}$ to right hand side, we get

$\frac{\text{x}}{\text{3}}\text{=}\frac{\text{7}}{\text{15}}\text{-1}$

$\frac{\text{x}}{\text{3}}\text{=-}\frac{\text{8}}{\text{15}}$

Now, we will multiply both sides by $\text{3}$, we get

$\text{x=-}\frac{\text{8 }\!\!\times\!\!\text{ 3}}{\text{15}}$

$\text{x=-}\frac{\text{8}}{\text{5}}$

## Why Choose NCERT Solutions for Class 8 Maths Chapter 2?

Math can be very tricky and hard to perform. It gets better with practice. But the method should be in an efficient way that you remember the equation and formula. To make this convenient for you, we have the perfect solution.

### Benefits Attached to the NCERT Solutions for Class 8 Maths Chapter 2

Significance of NCERT Solutions:

Maths is a difficult subject for so many students. On the other hand, it can be effortless for some. It depends on every individual's efficiency of understanding. To make it simple for you, NCERT Solutions have a practical list of subject experts to simplify the Class 8 Maths Chapter 2. You can obtain the free PDF downloads from our Website.

Quality NCERT Solutions

To make sure our students are gaining better results by practising our answers for Linear Equations in One Variable Class 8, our teachers conduct a series of a questionnaire and maintain the consistency of it.

Our Skilled Teachers Put their Efforts

The panel of experienced teachers writes all the simplified content provided in NCERT Solutions for Class 8 Maths Chapter 2 PDF. They primarily use shortcut techniques according to the standards of NCERT Solutions.

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The study material at NCERT Solutions is easy to understand and stays in mind as a memory for a long time.

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The helpful and simplified material at CBE NCERT Solution is entirely accurate that helps you in your exam preparation.

Content is According to NCERT Guidelines

All the subject experts have to make sure that the material is according to the guidelines provided by NCERT Solutions.

Important Topics under NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Exercise 2.1

Chapter 2 of the class 8 maths syllabus is on Linear Equations in One Variable. It is a very important chapter in mathematics that is covered in class 8 and is divided into 5 major sections. The following is a list of the important topics covered under Linear Equations in One Variable. We advise students to go through each one of these topics carefully to make sure they don’t miss out on internalising the concepts of Linear Equations in One Variable.

• Introduction

• Solving equations where linear expressions are on one side and numbers are on the other side of the equation

• Applications of linear equations in one variable

• Solving equations with variables on both the sides

• Reducing the given equations to a simpler form

### Important Takeaways from NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable

• Division and multiplication of algebraic expressions with integers as coefficients

• Common errors faced by students

• Factorisation

• Introduction to identities

• Process of solving linear equations in one variable

Importance of Linear Equations in One Variable

Learning about Linear Equations helps you modularized the real phenomena that make one variable changing constantly with the other variable involved.

### How Vedantu’s NCERT Solution Help You Study and Learn in Easy Way?

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### NCERT Solutions Class 8 Maths Chapter 2 All Exercises

Chapter 2 - Linear Equations in One Variable Exercises in PDF Format

Exercise 2.2

16 Questions with Solutions

Exercise 2.3

10 Questions with Solutions

### 10 Questions with Solutions

Exercise 2.5

10 Questions with Solutions

7 Questions with Solutions