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# RS Aggarwal Class 8 Mathematics Solutions for Chapter-8 Linear Equations

Last updated date: 09th Aug 2024
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## Class 8 RS Aggarwal Mathematics Linear Equations solutions - free PDF download

Mathematics is a high-scoring subject in which pupils achieve the highest possible score on the exam. When it comes to test preparation, it is the most difficult moment for most students, as they struggle to solve problems. As a result, our skilled teachers at Vedantu created helpful aids to assist students in easily preparing the RS Aggarwal Class 8 Mathematics Solutions for Chapter-8 Linear Equations for their exams. All of the answers are designed and adhere to the most recent CBSE patterns. When students learn on a regular basis, they might acquire simple tactics and shortcut ways. This Chapter's PDFs are available here, and students can download them for free using the link on Vedantu’s site.

## Solutions to Linear Equations for Class 8 RS Aggarwal

Scoring good marks in the math final examination becomes easy with the help of RS Aggarwal Class 8 Mathematics Solution Chapter 8. It is recommended that students should practice all the sums given in every math Chapter to score well in the examination. They can download Chapter 8 Class 8 Mathematics RS Aggarwal Solutions PDF from Vedantu. Students can refer to the RS Aggarwal Mathematics Class 8 Chapter 8 Solutions,to clear all their doubts from the Chapter. You can download the RS Aggarwal Class 8 Mathematics Chapter 8 solutions PDF from Vedantu for free. You may also be able to download NCERT Solution and NCERT Solutions for Class 8 Mathematics. Subjects like Science, Mathematics, English will become easy to study if you have access to NCERT Solution for Class 8 Science, Mathematics solutions and solutions of other subjects.

### Exercise-Wise Solutions

We have provided step by step solutions for all exercise questions given in the PDF of Class 8 RS Aggarwal Chapter-8 Linear Equations. All the Exercise questions with solutions in Chapter-8 Linear Equations are given below:

When it comes to the topic of Linear Equations, then there are some concepts that students should be familiar with before they start solving sums. If you want to learn those topics, then you can refer to the thoroughly discussed topics below. All answers given in the RS Aggarwal Solutions for Class 8 Mathematics Chapter 8 PDF file are accurate and reliable.

According to experts, Linear Equations can be defined as equations of the first order. This means that equations are defined for lines in any particular coordinate system. In other words, a Linear Equation is an equation for a straight line.

Usually, the general representation of the straight-line equation can be written as y = mx + b. In this equation, m is the slope of the line and b is the y-intercept. Also, Linear Equations can have the highest exponent value of 1. Some examples of Linear Equations are:

• 3x - y + z = 4

• x + y = 4

• x/2 = 7

• M + 1 = 0

• 4y = 8

• 2x - 3 = 0

Similarly, when an equation has a homogenous variable, which can also mean that there is only one variable, then this type of equation is known as a Linear Equation in one variable. This further means that a line equation can be achieved by relating zero to a linear polynomial over any particular field. This can be used to obtain the coefficients.

If a student finds solutions to Linear Equations, then that will result in the generation of values. These values when substituted for the unknown values would make the equation true. When it comes to the case of one variable, then there is also a single solution.

However, in the case of Linear Equations with two variables, the solutions can be calculated as the Cartesian coordinates of a point of the Euclidean plane. It should be noted here that Linear Equations can be present in one variable, two variables, and three variables. The examples for all of these Linear Equations are:

• Linear Equation in One Variable: 3x + 5 = 0, 97x = 47, and 32x + 8 = 0.

• Linear Equation in Two Variables: 6x + 9y - 11 = 0, y + 7x = 3, and 3a + 5t = 2.

• Linear Equation in Three Variables: 3x + 12y = 2z, x + y + t = 0, and a - 4b = z.

The equation of a straight line can be given by:

Y = mx + b

Here, m is the slope of the line, b is the y-intercept, and x and y are the coordinates of the x-axis and the y-axis, respectively.

Further, if a straight line is parallel to the x-axis, then the x coordinate should be equal to zero. Hence, this means that:

Y = b

Also, if the line is parallel to the y-axis, then the y coordinate will be zero. This means that:

Mx + b = 0

X = -b/m

The slope of the line can also be defined as being equal to the ratio of change in y coordinates and the change in x coordinates. An individual can evaluate the value of a slope by using the following formula.

M = (y2 - y1) / (x2 - x1)

From this formula, it is clear that the slop shows the rise of a line in the plane. This is seen along with the distance covered on the x-axis. Students should remember that the slope of a line is also known as a gradient.

There are other important formulas related to Linear Equations that students should be familiar with. To help students, we have created a table of all those formulas. And that table is mentioned below.

 Linear Equation General Form Example Slope intercept form Y = mx + c Y + 2x = 4 Point Slope Form Y - y1 = m (x - x1) Y - 3 = 6 (x - 2) General Form Ax + By + C = 0 2x + 4y - 5 = 0 Intercept Form x / x0 + y / y0 = 1 x / 2 + y / 4 = 1 As a Function F (x) instead of yF (x) = x + c F (x) = x + 4 The Identity Function F (x) = x F (x) = 4x Constant Functions F (x) = C F (x) = 7

In this table, m is the slope of a line, and xo and yo are the intercepts of the x-axis and y-axis, respectively.

There are several methods that one should follow to solve Linear Equations in one variable. As a general rule, both sides of the equation should be balanced for solving a Linear Equation. After that, students should solve the equation by using several mathematical operations on both sides of the equation. This should be done in a manner that does not have any effect on the balance of the equation. For example, if one has to solve the equation (2x - 10) / 2 = 3 (x - 1), then this can be done by following the steps that are mentioned below.

Step 1: Begin by clearing the fraction.

X - 5 = 3 (x - 1)

Step 2: Simplify both sides of the equation.

2x - 5 = 3x - 3

X = 3x + 2

X - 3x = 2

Step 3: Isolate the value of x.

-2x = 2

X = -1

In the case of Linear Equations with two variables, then there are different methods in which those equations can be solved. And those ways are:

• Method of substitution.

• Determinant methods.

• Method of elimination.

• Cross multiplication method.

Also, when it comes to solving Linear Equations in three variables, then those equations can be solved by using the matrix method. Students will get to learn about those methods in other Classes in the future.

### Get the Solutions on Vedantu

There are three exercises in RS Aggarwal Class 8 Chapter 8. In all of these exercises, students are tested on their knowledge of Linear Equations. If a student has any doubts while solving these exercises, then the student may take the help of experts at Vedantu. We provide students with solved R S Aggarwal Class 8 Chapter 8 Solutions PDF for free.

There are many benefits that students can get from downloading Class 8 Mathematics R S Aggarwal Chapter 8 from Vedantu. Some of these benefits are listed below.

• All answers are 100% accurate and reliable.

• Answers are accompanied by an explanation section that can help students to further understand the answer in a better light.

• Answers are written by the best subject matter experts in India.

## FAQs on RS Aggarwal Class 8 Mathematics Solutions for Chapter-8 Linear Equations

1. Is solving Class 8 RS Aggarwal Chapter 8 Linear Equations beneficial for exams?

Solving Chapter 8 Linear Equations of Class 8 RS Aggarwal is critical in understanding the concepts of the Chapter perfectly. The Chapter is important from the exam perspective as well as for strengthening the foundation for higher studies. Hence, students RS Aggarwal textbook problems to learn how to solve any type of question from the Chapter. RS Aggarwal Chapter 8 Linear Equation exercises allow students to score well in the exams. Class 8 students must solve RS Aggarwal questions for Chapter 8 Linear Equations for proper revision and doubt clearance.

2. Why should I download Class 8 RS Aggarwal solutions for Chapter 8 Linear Equations?

Students must download RS Aggarwal Solutions for Chapter 8 Linear Equations to get the solutions to exercise questions. These are available on popular ed-tech platforms like Vedantu. At Vedantu, RS Aggarwal Linear Equations problems are explained in a fairly simple manner so that students can understand them on their own. The solutions allow students to practice the Chapter for better understanding of concepts. For clearing any doubts regarding Class 8 RS Aggarwal Chapter 8 Linear Equations, students can refer to the solutions available in the free PDF format.

3. What are the learning objectives of RS Aggarwal Mathematics Chapter 8 of Class 8?

With the help of Chapter 8 Linear Equations, students will learn how to solve Linear Equations in one variable. Linear Equations are a crucial part of Algebra. Solving the problems of the Chapter improves arithmetic skills as well as problem-solving abilities. Students will get to know how to frame Linear Equations based on the problem statement. It also ensures that students are able to solve problems where some equations are involved.

4. From where can one avail RS Aggarwal solutions for Class 8 Mathematics Chapter 8 Linear Equations?

There are many ed-tech platforms that offer RS Aggarwal Solutions for Class 8 Mathematics. However, Vedantu is becoming the students’ favorite platform where one can find the well-curated solutions prepared by expert teachers. These mentors have a vast knowledge of the subject and are also well-experienced. RS Aggarwal Solutions for Class 8 Mathematics Chapter 8 Linear Equations include solved exercise problems. This helps students to easily solve the Chapter. Vedantu provides a step-by-step solution to make it easier for students to grasp the knowledge. Vedantu’s RS Aggarwal Solutions are 100% correct. You can download the PDF for free.

5. What is the most effective method for learning Chapter 8? Factorization in RS Aggarwal's Class 8 Mathematics Chapter 7?

Class 8 Mathematics Chapter-7, RS Aggarwal Factorisation is a fascinating Chapter that necessitates a full comprehension of the principles as well as the practice of a variety of numerical based on the same notion. The bigger the number of questions you practise after fully understanding the subject or theory of the Chapter, the stronger your grip on it will be. This can tremendously assist you in gaining confidence and improving your exam performance. After you've completed all of the Chapters, you should work on the previous year papers and mocks available on Vedantu to improve your speed and efficiency, as well as your total subject score.