NCERT Solutions for Class 6 Maths Chapter 2: Whole Numbers - Exercise 2.2

Exercise 2.2

1. Find the sum by suitable arrangement:

(a) $837+208+363$

Ans: $(837+363)+208$

$\begin{align} & \Rightarrow 1200+208 \\ & \Rightarrow 1408 \\ \end{align}$

(b) $1962+453+1538+647$

Ans: $(1962+1538)+(453+647)$

\[\begin{align} & \Rightarrow 3500+1100 \\ & \Rightarrow 4600 \\ \end{align}\]

2. Find the product by suitable arrangement:

(a) $2\times 1768\times 50$

Ans: $(2\times 50)\times 1768$

\[\begin{align} & \Rightarrow 100\times 1768 \\ & \Rightarrow 176800 \\ \end{align}\]

(b) $4\times 166\times 25$

Ans: \[(4\times 25)\times 166\]

\[\begin{align} & \Rightarrow 100\times 166 \\ & \Rightarrow 16600 \\ \end{align}\]

(c) $8\times 291\times 125$

Ans: \[(8\times 125)\times 291\]

\[\begin{align} & \Rightarrow 1000\times 291 \\ & \Rightarrow 291000 \\ \end{align}\]

(d) $625\times 279\times 16$

Ans: \[(625\times 16)\times 279\]

\[\begin{align} & \Rightarrow 10000\times 279 \\ & \Rightarrow 2790000 \\ \end{align}\]

(e) $285\times 5\times 60$

Ans: \[285\times (5\times 60)\]

\[\begin{align} & \Rightarrow 285\times 300 \\ & \Rightarrow 85500 \\ \end{align}\]

(f) $125\times 40\times 8\times 25$

Ans: \[(125\times 8)\times (40\times 25)\]

\[\begin{align} & \Rightarrow 1000\times 1000 \\ & \Rightarrow 1000000 \\ \end{align}\]

3. Find the value of the following:

(a) $297\times 17+297\times 3$

Ans: \[297\times (17+3)\]

\[\begin{align} & \Rightarrow 297\times 20 \\ & \Rightarrow 5940 \\ \end{align}\]

(b) $54279\times 92+8\times 54279$

Ans: \[54279\times (92+8)\]

\[\begin{align} & \Rightarrow 54279\times 100 \\ & \Rightarrow 5427900 \\ \end{align}\]

(c) $81265\times 169-81265\times 69$

Ans: \[81265\times (169-69)\]

\[\begin{align} & \Rightarrow 81265\times 100 \\ & \Rightarrow 8126500 \\ \end{align}\]

(d) $3845\times 5\times 782+769\times 25\times 218$

Ans: \[3845\times 5\times 782+ 769\times 5\times 5\times 218\]

\[\begin{align} & \Rightarrow 3845\times 5\times 782+3845\times 5\times 218 \\ & \Rightarrow 3845\times 5\times (782+218) \\ & \Rightarrow 3845\times 5\times 1000 \\ & \Rightarrow 19225000 \\ \end{align}\]

4. Fin(d)the product using suitable properties:

(a) $738\times 103$

Ans: \[738\times (100+3)\]

\[\Rightarrow 738\times 100+738\times 3\] (By using distributive property)

\[\begin{align} & \Rightarrow 73800+2214 \\ & \Rightarrow 76014 \\ \end{align}\]

(b) $854\times 102$

Ans: \[854\times (100+2)\]

\[\Rightarrow 854\times 100+854\times 2\] (By using distributive property)

\[\begin{align} & \Rightarrow 85400+1708 \\ & \Rightarrow 87108 \\ \end{align}\]

(c) $258\times 1008$

Ans: \[258\times (1000+8)\]

\[\Rightarrow 258\times 1000+258\times 8\] (By using distributive property)

\[\begin{align} & \Rightarrow 258000+2064 \\ & \Rightarrow 260064 \\ \end{align}\]

(d) $1005\times 168$

Ans: \[(1000+5)\times 168\]

\[\Rightarrow 1000\times 168+5\times 168\] (By using distributive property)

\[\begin{align} & \Rightarrow 168000+840 \\ & \Rightarrow 168840 \\ \end{align}\]

5. A taxi-driver filled his car's petrol tank with 40 liters of petrol on Monday. The next day, he fille(d)the tank with 50 liters of petrol. If the petrol costs Rs. 44 per liter, how much di(d)he spend in all on petrol?

Ans: Petrol fille(d)on Monday = 40 liters

$\Rightarrow $Petrol fille(d)on Next day = 50 liters

$\Rightarrow $Total petrol fille(d)= 90 liters

$\Rightarrow $Cost of 1 liter petrol = Rs. 44

$\Rightarrow $Cost of 90 liters petrol = Rs. $(44\times 90)$

$\Rightarrow $ $\begin{align} & =44\times (100-10) \\ & =4400-440 \\ \end{align}$

$\Rightarrow $ = Rs. $3960$

Taxi drivers spent Rs. $3960$ on petrol.

6. A vendor supplies 32 liters of milk to a hotel in the morning and 68 liters of milk in the evening. If the milk costs Rs. 15 per liter, how much money is due to the vendor per day?

Ans: Supply of Milk in morning = 32 liters

$\Rightarrow $Supply of Milk in evening = 68 liters

$\Rightarrow $Total supply = $32+68=100$liters

$\Rightarrow $Cost of 1 liter milk = Rs. 15

$\Rightarrow $Cost of 100 liters milk = Rs. $(15\times 100)$

$\Rightarrow $ = Rs. $1500$

Rs. $1500$is due to the vendor per day.

7. Match the following:

$(i) 425\times 136=425\times (6+30+100)$             (a) Commutativity under multiplication

$(ii) 2\times 48\times 50=2\times 50\times 49$         (b) Commutativity under addition

$(iii) 80+2005+20=80+20+2005$         (c) Distributivity multiplication under addition 

Ans: $(i) 425\times 136=425\times (6+30+100)$ (c) Distributivity multiplication under addition 

Hence, (c) is the correct answer.

$(ii) 2\times 48\times 50=2\times 50\times 49$       (a) Commutativity under multiplication

Hence, (a) is the correct answer.

$(iii) 80+2005+20=80+20+2005$         (b) Commutativity under addition

Hence, (b) is the correct answer.

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Exercise 2.2

Opting for the NCERT solutions for Ex 2.2 Class 6 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 2.2 Class 6 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.

Vedantu in-house subject matter experts have solved the problems/ questions from the exercise with the utmost care and by following all the guidelines by CBSE. Class 6 students who are thorough with all the concepts from the Maths textbook and quite well-versed with all the problems from the exercises given in it, then any student can easily score the highest possible marks in the final exam. With the help of this Class 6 Maths Chapter 2 Exercise 2.2 solutions, students can easily understand the pattern of questions that can be asked in the exam from this chapter and also learn the marks weightage of the chapter. So that they can prepare themselves accordingly for the final exam.

Besides these NCERT solutions for Class 6 Maths Chapter 2 Exercise 2.2, there are plenty of exercises in this chapter which contain innumerable questions as well. All these questions are solved/answered by our in-house subject experts as mentioned earlier. Hence all of these are bound to be of superior quality and anyone can refer to these during the time of exam preparation. In order to score the best possible marks in the class, it is really important to understand all the concepts of the textbooks and solve the problems from the exercises given next to it. 

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