

Step-by-Step Methods to Find Square Roots
Square root definition can be defined as a number which when multiplied by itself gives a as the product, then it is known as a square root. For example, since
5 × 5 = 25, so \[\sqrt{25}\] = 5
All real numbers have two square roots, one is a positive square root and another one is a negative square root. The positive square root is also referred to as the principal square root. Two positive numbers when multiplied results in a positive number because of having the same sign. As far as negative numbers are concerned, they don't have real square roots because a square is either positive or 0. Square root symbol is represented as \[\sqrt{}\]
Perfect Squares
When two equal numbers are multiplied, it results in a perfect square. For example, 55=25
This is a basic property of the square root
Square Root Table
Referring to this square root table, half of the energy will be saved.
How To Find Square Root?
Now, since we know what a square root is, we can quickly jump into knowing how to find a square root of a number. There is no square root formula as such but well, there are two ways to find the square root of a number. They are the Prime Factorization Method and the Division Method. You will know how to solve the square root equation using these two methods.
Finding Square Root Using Prime Factorization Method
To find the square root of a perfect square we have to follow the following steps:
Step 1) First resolve the given number into prime factors.
Step 2) Make pairs of similar factors.
Step 3) The product of prime factors, chosen one out of every pair, gives the square root of the given number.
For example, find the square root of 24336.
Solution) Resolving 24336 into prime factors, we get:
24336 = \[\underline{2}\] × \[\underline{2}\] × \[\underline{2}\] × \[\underline{2}\] × \[\underline{3}\] × \[\underline{3}\] × \[\underline{13}\] × \[\underline{13}\]
\[\sqrt{24336}\] = 2 × 2 × 3 × 13 = 156
Finding Square Root Using Division Method
In case of large numbers; we find the square root by using the following steps:
Step 1) Mark off the digits in pairs starting with the unit digit. Every pair and remaining one digit (if any) is called a period.
Step 2) Think of the largest number whose square is equal to or just less than the first period. Take this number as the divisor as well as quotient.
Step 3) In this step subtract the product of divisor and quotient from the first period and bring down the next period to the right of the remainder. This becomes the new dividend.
Step 4) now, a new divisor is obtained by taking twice the quotient and annexing with it a suitable digit which is also taken as the next digit of the quotient, chosen in such a way that the product of new divisor and this digit is equal to or just less than the new dividend.
Solved Examples
Question 1) By using the table of square roots, find the values of
i) \[\sqrt{13}\]
ii) \[\sqrt{83}\]
iii) \[\sqrt{150}\]
iv) \[\sqrt{36}\]
Solution 1)
i) Let x = 13
From the table, we find that when x = 13, then \[\sqrt{x}\] 3.606.
Therefore, \[\sqrt{13}\] = 3.606.
ii) Let x = 83
From the table, we find that when x = 83, then \[\sqrt{x}\] = 9.110.
Therefore, \[\sqrt{83}\]=9.110.
iii) \[\sqrt{150}\] = \[\sqrt{5 × 5 × 6}\] = 5 × \[\sqrt{6}\] = 5 × 2.449
Using the table for \[\sqrt{6}\], = 12.245
Therefore, \[\sqrt{150}\] = 12.245
iv)\[\sqrt{368}\] = \[\sqrt{4 × 4 × 23}\] = 4 × \[\sqrt{23}\] = 4 × 4.796
Using the table for \[\sqrt{23}\], = 19.184
Therefore, \[\sqrt{368}\] = 19.184
Question 2) find the square root of 1764
Solution 2)
Resolving 1764 into prime factors, we get:
1764 = \[\underline{2}\] × \[\underline{2}\] × \[\underline{3}\] × \[\underline{3}\] × \[\underline{7}\] × \[\underline{7}\]
\[\sqrt{1764}\] = 2 × 3 × 7 = 42
Question 3) Find the smallest number which when multiplied by 720 gives a perfect square number.
i) Give the perfect square number so obtained?
ii) Find the square root of this perfect square number.
Solution 3) Resolving 720 into prime factors, we get:
720 = 2 × 2 × 2 × 2 × 3 × 3 × 5.
Thus, 2,2,3 exist in pairs while 5 is alone.
So, we should multiply the given number by 5 to get a perfect square number.
i) Perfect square number so obtained = 720 × 8 = 3600
ii) Now, 3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5
Therefore, \[\sqrt{3600}\] = 2 × 2 × 3 × 5 = 60
FAQs on Square Root Explained: Quick Guide for Students
1. What is a square root and how does it relate to a square number?
A square root of a number is a value that, when multiplied by itself, gives the original number. It is the inverse operation of squaring a number. For example, the square root of 25 is 5 because 5 × 5 = 25. The symbol used to denote the square root is called a radical sign (√).
2. What are the main methods to find the square root of a number as per the CBSE syllabus?
As per the NCERT curriculum for the 2025-26 session, there are two primary methods for finding a square root without a calculator:
- Prime Factorisation Method: This method is best for finding the square root of perfect squares. It involves breaking the number down into its prime factors and then pairing them up.
- Long Division Method: This method is more versatile and can be used to find the square root of large numbers, non-perfect squares, and decimal numbers to a desired precision.
3. Where are square roots used in real life and other areas of Maths?
Square roots have many practical applications. In mathematics, they are crucial for solving quadratic equations and in geometry for the Pythagoras' theorem to find the length of sides in a right-angled triangle. In real life, architects and engineers use square roots to calculate dimensions and ensure structures are stable. They are also used in fields like finance for certain calculations and in physics for formulas involving area and velocity.
4. Why does a positive number have two square roots, and why do we usually use only the positive one?
A positive number has two square roots because a negative number multiplied by itself results in a positive number. For instance, both 7 × 7 = 49 and (-7) × (-7) = 49. Therefore, the square roots of 49 are +7 and -7. However, we usually use the positive root, known as the principal square root. This is because in most real-world applications, such as measuring length, area, or distance, a negative value is not meaningful.
5. What is the difference between the square root of a perfect square and a non-perfect square?
The key difference lies in the nature of the result. The square root of a perfect square (like 36 or 81) is always a whole number (6 or 9, respectively). In contrast, the square root of a non-perfect square (like 30 or 82) is an irrational number, which means it is a non-terminating, non-repeating decimal. For such numbers, we typically find an estimated or approximate value using the long division method.
6. How can you tell if a number might be a perfect square just by looking at its last digit?
You can quickly identify numbers that cannot be perfect squares by examining their unit digit (the last digit). A number that ends in 2, 3, 7, or 8 can never be a perfect square. A perfect square can only end with the digits 0, 1, 4, 5, 6, or 9. This is a useful shortcut for eliminating options in multiple-choice questions.
7. What does an expression like 5√2 mean, and why can't it be simplified to a single whole number?
The expression 5√2 means 5 multiplied by the square root of 2. It cannot be simplified to a single whole number because the square root of 2 (√2) is an irrational number (approximately 1.414...). Multiplying an irrational number by a whole number (other than zero) results in another irrational number. Therefore, 5√2 is the simplest form of this number, representing a precise value without approximation.
8. What is the fastest way to find the square root of a small perfect square in an exam?
For small perfect squares, the fastest and most efficient method is memorisation. Students are strongly advised to memorise the squares of all integers from 1 to at least 25. This allows for instant recall of square roots for numbers like 144 (√144 = 12), 196 (√196 = 14), or 625 (√625 = 25), which saves valuable time during calculations in an exam.





















